How to find the column size | How to calculate the load on column | Initial size of column | Column 

It will be 0.008Ag instead of 0.08Ag @ 12.16. Only to find out the gross area we use the formula 0.008Ag. So the gross area will become 23809.52mm^2 and d=23809.52/240 = 99.206 mm instead of 34.04 mm. This is to check the depth of the column. It was an error by mistake. Sorry for the inconvenience.

very nicely explained ma'am thankyou

Very clear ❤ all concepts are define very well

This is an amazing ppreseentation

This is a very beautiful video which clearly shows the load on the column and has a lot of information related to the building.

This video is too good

Love this

Very good

Thank You Very Much maam for so detailed explanation 🙏🙏🙏

It will be better to consider 3 bays along X axis and 2 bays along Y axis with G plus 3 floors will be good to explain to arrive size of column.In addition to this thumb rule followed in practice also useful to assume size of column initially. Thank you for explaining neatly with sketch with detailed calculation.

so much help full video thanks

Thank you so much madam 🙏🙏🙏

Thank you.. Good explanation for new student as l am.

Thanks

good

Superb 👌👌 And useful video for structural designing👍

Short ,brief, very nicely explained❤

Dear Ms. Architect, you explained it very well, thank you very much for your valuable lesson video. Are there earthquake and wind loads in the calculations explained in this video? Thank you very much. Hakan

thank you so much mam

I will like you to make a video of design of a primary with a secondary beam attached to the primary beam making the primary beam to have an additional point load from the secondary beam to the UDL of the secondary beam

Very well explained. What if mam it is a uniaxially or biaxially loaded ?

Similar to explain by madam you can calculate load on column for vertical load (DL+LL) for typical 2 or 3 columns by using tributary area method. Multiplying factors 1. For beam spans up to 6.0m multiply by 1.2 and for beam spans greater than 6.0m multiply by 1.30 to arrive gravity loads. 2. Multiply 1.3, 1.4 and 1.5 for EQ zones 3, 4 and 5 respectively for including seismic loads. By considering first floor steel as 2.50% determine size of column for assumed concrete grade and steel grade from formula Pu=0.4fck Ac+0.67 fy Asc. MInimum size of column as per IS13920-2016 will be 300mm or 20x beam dia bars assumed.This will be followed by Architect for arriving preliminary size of rcc column in building design. This is suggestion. Thank you

How will I find the foundation depth? Please Make a video.

Slab load will act on beam like triangular motion only..but you consider like square motion, can clarify regarding this??

Discuss beams.

nice topic

I think you have to explain how did tou arrive the load of floor finish to 1.5 kN/m2 , the live load, and the 25 that you multiply to the thickness of the slab. We have to know it by your explaination. Whare did you get them, and or how did you determine it? Its not just enough to introduce it, but how come?

In roof beam load calculation, self weight of beam is not added to self weight of parapet. Considered 6 kn /m only. . Please correct me if iam wrong

Why you take Asc as 0.08ag ?

Can explain about is this a one way or two way slab?

Excellent

Madam vedio is good, please vedio few slowly is better

How you taken area of steel as 804 mm^2 when finding load bearing capacity of column.

Mam I have column to column distance 12.10 feet span for g+1 building i have use 4 T12 for column .Can it be safe

In load for second floor why self weight of beam and parapet wall weight is not add.

Load on column

What is ( 4 T 12 ) or ( 4 T 16 ) How you taken area of steel as 452mm^2 or 804mm^2 Please explain.

How did you get the 804mm² area of steel?

I feel like subscribing thrice after watching this. Can someone help me out?

Madam you forgot to say about how to calculate the lateral ties dia

At last moments while calculating the area of column I.e, Pu... Why you added 10^3 in the equation? 300×10^3.....!!!??? I didnt understand that

IS THE LOAD CALCULATION OF SLAB IS CORRECT?

While calculating Pu you take equation 300X10^3. Why you take like that pl kindly tell us.

Niceeeeeee explain mam

.008g ki jagah .08g likha hai formule mein , isliye 34.04mm column ki one arm ki length aayi hai.weight mein kn kya hai?

How did u derived Ac =0.992

Sis 0.8% in calcuion is 0.08which is 8 %insted of .8 pls explain

Area of Steel kase aaya mam

How we can contact u...

YOU FORGOT TO ADD THE SELF WEIGHT OF 2ND FLOOR BEAM AND SELF WEIGHT OF PARAPET WALL COMING ON COLUMN C1. AFTER ADDING THOSE TWO THE TOTAL LOAD WILL BE {(2.81+6)X3.35}/2 = 14.75KN

I have a doubt maam that 0.8% should been written at 0.008 na

Madar there are 2 mistakes