I used to use this method ( and I recommend engineers learn it ). Now I use - * Take the amount of gas used ( here it was 0.01 m3 of gas used in 2 minutes ) 0.01m3 * Multiply that figure by 323 ( 323 is a fixed figure, no variables ) 0.01 x 323 = 3.23m3 of gas used ( gross ) * 3.23 (gross) divided by 1.1 ( to convert to the net figure we require ) = 2.93m3 total.
You've confused everything there mate, the 0.01 needs to be multiplied by 30 minutes, not 323, that burner is not using 3m3 gas per hour mate, a combi just about does that.
