How To Measure Inductance By A Multi-meter? 

Good thought, Mate. To measure Inductance, it has been not an easy & simple task especially on high frequency. To be all things considered thoroughly, the best way is to try the experience a few times by using a normal multi meter and steps in the video then you'd figure yourself out and make sure to play safe! I'd use formula C for lower frequency range such as below a coupe of thousand Hz. In order to do electric project(s) properly, there are three steps (at least two steps) need to be done: (1) Design or draft a circuit, (2) experience or test, (3) Conclusion or may be, to do an improvement as well. Thanks for your interested & good luck! 👍👍

@@diymade2175 Thanks for that .

👍

You are welcome!

was your results accurate ? please share

Many thanks!

Good point! Actually they came from the sections of the video fast edited. Thanks for your interested!

👍

Thank you, I will.

Thank You for the interested. Good points and You are right in theory. Dealing with an inductance is a complex issue especially the one wants to get as accurate as possible however I recommended highly, experiences yourself in the way of this video has showed, such as try a few times to use the different resistors and get the varies voltage values then you'd get an acceptable or satisfied result(s). Thanks again for sharing your thought!

The formula seems inconsistent. Results vary enormously depending on the value of R. Why do the other methods involve costly instruments, then?

Thanks & glad it helped!

Thanks, you too!

You are welcome !

Thanks a lot ! Yes, you are right and great point.

Thanks Mr. J.👍that is most excellent additional and corrective information. I learned, many years ago, how to use algebraic equations to determine most pertinent values and actions of components in an electrical circuit, but something we did not address was inductive reactance, or microhenrys' although we were made aware the reactance was there and lenz's law did help me understand Some counterintuitive characteristics of electricity. I still find myself doing the - I C E - and the -E L I - thing in my head, as I track through single but perhaps manipulated phase circuitry.ahaha! Those were pre-digital multimeter days, a different time. My instructor, Mr. Richard Deputy, whom I was EXTREMELY fortunate to study under, gave us all the little tricks and acronyms and he also said- "you will never use this in the field" . Mostly true that. Digital everything was just around the corner, but having the experience and knowledge that was passed on as it were, has been such a benefit especially when you have complicated circuitry with varied components throughout, well, it gave me the ability to at least have an idea of what to expect in many such instances, and recognize my mistaken calculations as well. Thanks again. Edit youtube cut this out of original - as I track through single but perhaps manipulated phase circuitry.ahaha 🤔 those were the pre digital multimeter days, a different time. My instructor, Mr Richard Deputy was a brilliant and multi field expert and simply a font of useful knowledge and information and I was EXTREMELY FORTUNATE to have a couple years of his presence in my life. I digress. Trying to fill in what youtube has mysteriously deleted from my original reply. This is very confusing , and a little out of context, but my previous 'edit' content should fit into the above diatribe and with your help all of this might make some sense! Oh my gosh this is evolving into such a mess. I need to get the hell out here. Have a good day everyone and thank you for your patience, and your input.

👍

Thanks for your Comment ! I'm glad it could help and good luck with your experience..

Yes, correct. it was a DC 12 V & 21 W globe.

🙂👍

😂😂😂😂 that's enough utube 😅

Had no idea Donald Duck lived next to a busy highway. Watch the dogs ducky. JustSaying.

Yes, you can do that way. Thanks! 👍

Thank you for the interested Mate! The formula was created for the simplified calculation, it didn't meet logic equation strictly & theoretically but within a certain tolerance for the practical experiences and inductance calculation is always complicated especially on high frequency. You can refer to @adnanah comment(s) for more details. Enjoy watching & Thanks again. 👍👌💪

Thanks for your interested! 👍

North Atlantic USA?????????????? what you do there?

Glad to know you've experienced and keep going a few more times so you'll be able to figure things out. From data you've supplied, I'd say: (1) Increasing the globe wattage, (2) Increasing the value of the resistor(s), (3) Using a low AC voltage such as 24V, 36V or 48V instead. The one of ways or ways of combination above can be used depending on your own condition. Have a fun and good luck! Thanks.

@@diymade2175 if a formula is perfect, then the answer should come accurate for all situations, but i am not getting results. from your explanation now i should purchase another transformer to get 24v AC voltage, again a headache. and that future is also not known, will it work or not ? tuff times for us

Have a look at my post yesterday. It lists the problems you are seeing. Lower AC voltage or bulb wattage will not solve this, I expect.

Cheers! 👍

Okay, I'm able to handle this: R / 2π*50 = R / (2 x 3.14 x 50) = R / 314 = R x 1 / 314 = R x 1 divided by 314 = 0.00318 R. So this is where the result of 0.00318 comes from (1 divided by 314). Thanks for your interested !

@@diymade2175 I did have an epiphany a few hours ago and realised it's the reciprocal of 2π f. Haven't worked on formula transformation at this level for 40 years. Thanks for the reply.

👍

Good comment and you might have seen a lot. There are many places in the world, many things have been commercialized, at the same time, the same things offered free to public such as there are the public schools and also the private schools etc. This concept applied to the contents you watched on youtube. Thanks for the interested!

@DIY made perhaps I will bring the link for your presentation back to my home planet and you will pick up some subscribers!

Great appreciated. The link is here: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-fuxHONPjxMc.html Thanks again! 👍

One reason for missed likes is that the viewer found the video through a search. When not signed in they cannot leave a like or a comment. That was my situation just now. Because I really wanted to like this video and its comments I went to the extra trouble of signing in.

Thank you for your interested & comment. Formula C supplied in the video, it was not met strictly & theoretically but within a certain tolerant for the simple practical experience (The more accurate, the more complicated formula will be). The formula you have supplied, it does not appear right however the result of 2.18H is the more accurate one according to this particular formula: L = 0.00318 ( sq Z - sq r )^2 in Henry, where Z = VL / I. Thanks a lot again!

Your equation is correct. When measuring the voltage of the inductor, one needs to combine the internal resistance along with the inductance to get the corresponding impedance. Then one can calculate the resulting current by taking the voltage across the inductor and dividing by the impedance. I also get your numerical results.

@Don : to which of the equations are you referring, when stating it is correct?

@@calculatingcapibara2914 Adnam-AH. He properly took into account impedance for the inductor which included its internal resistance. The voltage reading VL is across that item.

You are referring to DIYmade as "He" here? DIYmade is on the right track when measuring 50 Hz coils at their own frequency. He is wrong in his substraction/correction for ohmic resistance, ignoring quantisation error and proposing a formula using the square of the difference of two squareroots. See my posts above explaining more. For fun, I did some tests myself. As expected, I had only very inaccurate results. Inductancies are complicated components, heavily dependent on frequency, current etc. There is no single easy method for measuring. Understanding the theory behind it can not be missed. Enjoy the hobby!

Thanks Mate & appreciated your input! 👍

👍

Thank you for the interested! You see: L = 0.00318 * R * Vl / Vr in Henry, it can be L = 0.00318 * R * Vl / Vr * 1000 / 1000 = 3.18 * R * Vl / Vr * 1 / 1000 in Henry. Then it also can be L = 3.18 * R * Vl / Vr in Milli Henry [L = 3.18 R (Vl / Vr) in mL for short in the video showed]. That's reason 3.18 showed. Thanks again.