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How to predict products for single replacement reactions 

Crash Chemistry Academy
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This video shows how to predict products in a single replacement reaction, including 1. identifying the reaction type, 2. illustrating and modeling the displacement, 3. balancing ion charges in the product, 4. balancing the equation, 5.detailed instruction on use of the activity series, including reaction with water and acids, 6. the need for an aqueous environment and illustration of the oxidation-reduction occurring in the reaction
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-More on Single Displacement | Wikipedia-
A single-displacement reaction, also known as a single-replacement reaction, is a chemical reaction in which one (or more) element(s) replaces an/other element(s) in a compound. It can be represented generically as:
A + B-C → A-C + B
This will most often occur if A is more reactive than B, thus giving a more stable product. A and B must be either:
Different metals (hydrogen's behavior as a cation renders it as a metal here), in which case C represents an anion; or
Halogens, in which case C represents a cation.
In either case, when AC and BC are aqueous compounds (which is usually the case), C is a spectator ion.
In the activity or reactivity series, the metals with the highest propensity to donate their electrons to react are listed first, and the most unreactive metals are listed last. Therefore, a metal higher on the list is able to displace anything on the list below it.[1] The order of activity for metals, from most reactive to least reactive, is: Li, K, Sr, Na, Ca, Mg, Al, Zn, Cr, Fe, Cd, Co, Ni, Sn, Pb, H, Sb, As, Bi, Cu, Hg, Ag, Pd, Pt, and Au. Similarly, the halogens with the highest propensity to acquire electrons are the most reactive. The activity series for halogens, from highest to lowest, is: F, Cl, Br, and I.[2]
Due to the free state nature of A and B, all single displacement reactions are also oxidation-reduction reactions, where the key event is the movement of electrons from one reactant to another.[3] When A and B are metals, A is always oxidized and B is always reduced. Since halogens prefer to gain electrons, A is reduced (from 0 to −1) and B is oxidized (from −1 to 0) when A and B represent those elements.
A and B may have different charge as ions and therefore some balancing of the equation may be necessary. For example, the reaction between silver nitrate, AgNO3 (which contains an Ag+ ion), and zinc, Zn, forms silver, Ag, and zinc nitrate, Zn(NO3)2 (which contains a Zn2+ ion).
All simple metal with acid reactions are single displacement reactions. For example, the reaction between magnesium, Mg, and hydrochloric acid, HCl, forms magnesium chloride, MgCl2, and hydrogen, H2.
One cation replaces another. A cation is a positively charged ion or a metal. When it is written in generic symbols, it is written out like this:
X + YZ → XZ + Y
Element X has replaced Y in compound YZ to become a new compound XZ and the free element Y. This is an oxidation-reduction reaction wherein element Y is reduced from a cation into the elemental form and element X is oxidized from the elemental form into a cation.
If the reactant in elemental form is not the more reactive metal, then no reaction will occur. Some examples of this would be the reverse reactions to these:
Ag + Cu(NO3)2 → No reaction
Au + HCl → No reaction
Nov 13 WIKIPEDIA 2019 "SINGLE DISPLACEMENT REACTION"

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22 июл 2024

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Комментарии : 16   
@pauldolinko9905
@pauldolinko9905 4 года назад
The depth was unexpected but made it extremely informative and enjoyable. Extremely well presented.
@jarretberenson1214
@jarretberenson1214 4 года назад
Your channel, and this video, was a big help getting me through IB. Thanks you rock.
@madhavsatija5977
@madhavsatija5977 2 года назад
Amazing video, it had great detail, and the visuals were super helpful! Thank you!
@CrashChemistryAcademy
@CrashChemistryAcademy 2 года назад
Thanks for your comment!
@angieg7257
@angieg7257 2 года назад
What a terrific video and explanation!
@joelweiner5877
@joelweiner5877 2 года назад
Thanks!😊
@chromesupport7441
@chromesupport7441 4 года назад
a really excellent video. Thanks.
@aphidsfirst
@aphidsfirst 4 года назад
This is great!!!!
@freepalestine1764
@freepalestine1764 3 года назад
I'm gonna recommend this channel to my class like omg
@CrashChemistryAcademy
@CrashChemistryAcademy 3 года назад
Thanks much, I appreciate it!!
@freepalestine1764
@freepalestine1764 3 года назад
@@CrashChemistryAcademy No problem. Oh wait. So Br2+ HS would be Br2 +HS -> 2BrS+ H2 or should I flip the S and H?
@CrashChemistryAcademy
@CrashChemistryAcademy 3 года назад
Products are HBr + S. You switch the non-metals. The H acts like a metal in this situation.
@freepalestine1764
@freepalestine1764 3 года назад
@@CrashChemistryAcademy thank you so much. I appreciate you and your channel
@CrashChemistryAcademy
@CrashChemistryAcademy 3 года назад
@@freepalestine1764 Thanks and you're welcome!
@jonnyg7629
@jonnyg7629 4 года назад
SWEET!
@returnofthemomos
@returnofthemomos 4 года назад
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