How to Solve Algebra Word Problems: Work 

for two people only, i would use the product over the sum.(axb)/(a+b)= 5.45455 hrs and for any quantity use the reciprocal method 1/(1/10 +1/12) BAAM you got it. these methods are used in parallel resistor in electronics too.

My first impression in this video, I thought that It was so hard, but when I finished watching this video I was amazed because It was easy when you know how to get it and how to solve it.

i would hate to be a student in your class bro... that was nearly incomprehensive lol.

please explain why this works. I mean, why exactly do you put 1 over the number of hours that it takes each and over the total? This needs explaining.

I dont get it 😂😂

I started looking at this and I had to stop. Extremely complicated.

good explanation. helped me to do the similar problems without difficulty. Thanks a Lots...

1st equation is X/10 + X/12 = 1 LCD 60 then add 6x + 5x = 60 so X=60/11 or X= 5 5/11 = 5hours and 5/11 mins :) I'm grade 8/13yrs old

Question 16 shortcut: If you simplify (1/A) + (1/B) = (1/x), and solve it in terms of x, you will come up with the result of AB/(A+B) = x. So therefore the solution is just ( product over the sum ) of their work speed. That is 10(12)/(10+12).

So irrespective of the task, we are looking for the combined rate, which will tell us the combined time. If the task is denoted by X then the rate for Maria is X/10 and that of Kayla is X/12. The combined rate is X/R where R is the time they take working together. So X/10 + X/12 = X/R. We can divide by X and that gives 1/10 + 1/12 = 1/R

This is what I do in cases like this: (1/a) + (1/b) = 1/x 1. I first take a+b and put it to the left of the equation 2. Then I take a*b and put it to the right of the equation like this: (a*b)/x 3. Using the denominators of this example, it would be this: 10+12 = (10*12)/x 4. Now we separate the x like this: x = 120/22, resulting 5.45 So, no LCD is required here.

That was a great video, thank you for explaining how to solve it so well.

I got a 100 on my test thanks to you Thank you so much

thank you maam.

Thank you so much! This helped me a lot! :)

thanks!

I had to ask google why the known variables are set as denominators, because I can’t learn a technique if I don’t know WHY it works. 1/(hours to complete) expresses each person’s time-to-complete in terms of work done per hour. You’re then converting the combined per hour rate to total hours required.

Like if you’re one of the people that hates word problems and don’t get it 😂😂

ITS REALLY GOOD

THIS IS INSANELY HELPFUL, THANK YOU!! I've been struggling with work rate problems for so long, and you solved it!!literally!!

Very confusing and messy! Problem 16: 12/10=1.2 units of speed and 10/10=1 unit of speed, 12/2.2=5.45 hours or 5 hours 27 minutes.

bro this is so helpful

This video from 8 years ago is still helpfull

I dont know how you get your common denominator..

The first part where you started farting the denominator was really throughout me off and after that I could get passed the rest of the word problem.

This is a tough one, better to study and master the lesson :D :D :D

Very helpful.

NOW I UNDERSTAND

Thank you very much :)

Thanks teacher

Is this common core?

There is a reason why there are so many dislikes... Your explanation of the LCD is not clear.

Shortcut: (10 x 12)/(10 + 12) = 120/22 = 5.45 hours. Can be solved in under 60 seconds.

thankyou!!

This is a difficult one, i better study this!

what if its a problem that has one persons time to do something and the total time of two people to do soemthing together but not the time of one of the people.

very simple product/sum

Problem 16: 12/10=1.2, 10/10=1, 1+1.2=2.2, 12/2.2=5.45 hours or 5 hours 27 minutes.

should convert .45 into minutes which is 27 minutes

thanks bruh

Look at it this way, (1/10 +1/12) x =1(job) x is hours.

it is quiet confusing but if you practice it will be easier!!

Not clearly explained why using 1 to divide each hours. I think it is to calculate the combing rate in one hour. Anyways thanks for taking time to make this video.

can u do a lesson on slope?

4:15 use Euclidean Algorithm.

lol at 2:12, you said lets look at one problem when there were like 4... CAN YOU COUNT???? WHAT HAPPENED???? (i'm just playing XD)

In problem #16, if Maria can pick 40 bushels of apples in 10 hrs, then that means that she can pick 4 bushes in 1 hr. Her rate can be known as 4 bushels per hour, and her portion of work done in 1 hr can be written as 4 bushels/40 bushels. Similarly, if Kayla can pick 40 bushels of apples in 12 hrs, then that means that she can pick 3 and 1/3(written as a mixed number) bushels in 1 hr. Her rate would be 3 and 1/3 bushels per hour, and her portion of work completed in 1 hr would be 3 and 1/3 bushels/40 bushels. Since they decide to work together and start picking up bushels at the same time and neither of them leave early, then we can set "T hrs" as the amount of time it'll take them both to pick a combined amount of 40 bushels of apples.(4 bushels/ 40 bushels) * T hrs can be the portion of bushels picked by Maria in T hrs, and (3 and 1/3 bushels/40 bushels) * T hrs can be the portion of bushels picked by Kayla in T hrs. All that's next is to combine(add) their portions of bushels picked in T hrs, and set them equal to a combined portion of 40 bushels/40 bushels. Therefore: (4 bushels/40 bushels) * T hrs. + (3 and 1/3 bushels/40 bushels) * T hrs. = 40 bushels/40 bushels. Now we just solve the fractional equation to find that T = 60/11= 5 and 5/11 hrs. This means that they took 5 and 5/11 hrs, or 5.45 hrs, to pick a combined amount of 40 bushels of apples. 40 bushels of apples represents the total amount of units required for this type of job, and 40 bushels/40 bushels equals to 1 full job since 40/40 = 1

I realized that Work Problems are kinda difficult but it's easy if you study and master this lesson.

Cool

A*B/A+B. Is a formula for this

Can't you just use 120x as the LMD for the first problem and get 5 hours as the answer?

Is 10 the common denominator?

Cool ^-^

What if the D is not one?

Ez to understand

What if it says to work alone?

Work, in Physics, is an abstract idea, but in Math it's different T.T

hi

006

Please explain 1/10 1/0 why do you do that

a bit hard but easy

2*6 thooo

Nope not a tutorial dude ,not for novice,👎

UGHHHH!?

I hate mathsssßss 🥺🙄

I realized that Work Problems are kinda difficult but it's easy if you study and master this lesson.