How To Solve Any Projectile Motion Problem (The Toolbox Method) 

Good suggestion.

Thanks! :D

Asante sana

YEAH AGREE

Dat yellow tho

SURELY YOU'RE JOKING, MR. SAINI!

Jesse Mason I'm serious.

I am flattered then. I spent a lot of time on this one. :)

Watch physics wallah

First of all, wtf. Second of all, is your Physics teacher THAT bad

I just found a simple way. Distance = Horizontal velocity x (Time to decelerate vertically + Time to freefall from height)

my teacher lol

I'm stuck with this kind of guy. don't know why physics teachers are so garbage

feel like you're talking about my teacher lol

Dude I think we have the same teacher

+FrostByte how does he get 5.68s? what is y0?

Sholla Hanafiah y0 is displacement bro taken in projection cocepy

is it 100m?

That makes two of us.

Yup. I was right along with him, then he skipped solving the quadratic, and I'm out.

Glad that you found the toolbox method useful, Dean! Feel free to share this video with your teacher. =)

bro u alive?

To find Yo without having time though, don't you need another equation, V^2 = Vo^2 + 2a(X-Xo)? I think that would be Voy^2 + 2a(Yo) = 0 simplified with your variables

MissPielops Yes, you're absolutely right in my opinion considering the formula you have given is only when the acceleration is constant, which in this case is -g.

3d834 To save time and space. (Sounds epic.)

Jesse Mason at the Range parts when your solving for the components of time isn't it -5.68 and 3.59 instead of the other way around?

Jesse Mason Thank you so much! Your video wasn't boring like other and it really helped!!!! ^_^ Coming in from Trinidad and Tobago btw :)

i did this. and it totally made my day! Thanks.

Awesome reply :D

Jerry Li yo, are you studying for the PQ as well? Good luck!

Jerry Li Thanks. =)

It reminds me of my typing teacher in grade 10. Mr. Dudley was a great guy but he smelled funny and I didn't suffer from anosmia. Nice vids, thanks!

This has helped me so much!!! Hello from Malawi😁

+Chelsea George I do, I do! Cheers from Detroit, Chelsea!

My pleasure, Kevin!

Thanks, Rao!

Cassandra Siegfried omg same

Glad to help and hope you crushed that midterm!

I'm struck by your praise. ;)

Jesse Mason can you improve the quality of you video please i cant understand it

@@tonibautista4439 there's nothing wrong with the vid, maybe slow it down a little on your end or pause every once in a while. the problem is with u not the vid itself

I'm flattered, Kewal! Best of luck with your studies.

I agree. The toolbox is cool but I feel like it overcomplicates some things, especially if you are timed on a test

I helped you. You saved yourself. Nice work, Nani!

I was also stumped on this for a while. He adds the S to the left side of the equation because it is a problem where the projectile is launched from a ledge. Therefore we need to add the height of the ledge to the vertical displacement.

+Nighat Ansari Awww... thanks, Nighat!

Yeah.

i kno, bro. i kno.

Jesse Mason you still the man tho

Everyone is upset about the yellow when it represented the easiest thing which was gravity lol. I get it though it was bright.

I am Batman, no wait, I am Jesse Mason.

Thanks, ODB!

LOL

🤣

mad facts visa bosa x visa bosa y

My pleasure, Eli!

Philippino

"Take 'zat, Pachelbel." - Pete T. (Get it? Because Pachelbel's... cannon! Eh?! I'll just let myself out...)

+jrpg0630 I know, right?

+Jesse Mason Thanks though. Really helpful!

+jrpg0630 Glad to hear it!

Hahaha how did you do?

Miss Spectator 13%

feelsbadman rip IB physics exams coming up in about a week :/

@Donald Trump yeah no wonder orange.

Will do. Thanks, Jerry!

thanks - if you turn your monitor upside down the hue saturates and the yellow becomes much more visible

Thanks for your help I was using positive for gravity which gave me math error Looks like you helped in other ways too

@@dontbeserious5153 same!

My vanity knows no bounds.

@@JesseMason Good video. Just one thing: magnitude is never negative.

@@jlbenson I used to have an annotation that pops up with this correction. I have no idea where it went. Thanks for letting me know, John - will look into this!

Because at impact, the projectile is already landed at land which is at the x-axis, wherein the y is 0. Correct me if I misunderstood the question.

@Dave Henning Yes, the displacement is -100m, but because of where we set the origin of our x,y plane, it's position would be indicated as 0m. Remember that it started at 100m.

Your comment made my day, Sandrine. Cheers from Detroit!

Just slow down the video

I would think you'd like yellow, Pineapple. ;)

@Gamming Lab If I had a dollar for everytime someone commented on that yellow marker...

Gear button up top - take it as slow as you'd like!

***** thank you! :)

i still don't understand why the acceleration become positive because acceleration in earth in always negative g, or is it?

Depends on the direction of motion I think. If you are moving away from the centre of the earth (up) gravity is not helping you. Whereas, if you are moving towards the centre of the earth (down) gravity aids you. Also depends on how you set the directions, which you should do for every physics problem.

I take the format/production seriously so your compliment means a lot to me, Doll!

Thank you for the kind words, Jacob. Hope you crushed today's test!

if this isnt me right now lol

stopitidontlikeit yeah you might not want to pursue something in steam if this doesn’t motivate you. However, there’s a huge amount of majors out there! Just find the right one for you! Or maybe a technical job is your deal?

+sourav ghosh You can just set the initial height to zero, and proceed from there.

+Sourav Ghosh Pretty much the same thing. List all the horizontal and vertical competent information listed downward, SUVAT. Some information is already known, horizontal acceleration is zero whilst vertical is -g (given that 'up' is taken as positive). Also, at the maximum height final velocity is zero (or initial if considering the right hand side). Then select the correct equation with the variables you know and one unknown. Give me a example question if you want.

Thanks, jmc - good luck with your studies!

Sorry, Ian!

Thanks, SHEMA! =)

My pleasure, Dennis!

Thanks so much, Mr. Lennon! Have a great Thanksgiving!

@@JesseMason Thanks and same to you, professor.