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IB Physics: Problem Solving with Circular Motion 

Chris Doner
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21 окт 2024

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Комментарии : 21   
@emir2750
@emir2750 5 лет назад
I don't understand why this channel has just 9k subs . If we assume the number of subscriptions proportional to the awesomeness of the channel, we should have get at least 1 million !
@georgfuellner8134
@georgfuellner8134 6 лет назад
That was an extremely helpful video Mr.Doner. Thank you so much !
@ibarrajulian
@ibarrajulian 3 года назад
Thank you Mr. Doner... enjoying your videos from Honolulu, Hawaii
@donerphysics
@donerphysics 3 года назад
Glad you like them!
@lucaslosantos8307
@lucaslosantos8307 4 года назад
I do not get how the normal is greater than the weight force. They should be equal and cancel each other, but then due to the centripetal force, the resultant is upwards. I do not know if I am wrong or right but this is what I have understood in all this videos. Isnt it possible that the normal is equal to mg but then the centripetal force acts and increases the Force so the force upwards, normal is increase by that centripetal force, but still the normal should be equal to the weight mg. Thank you, please let me know whether I am right or wrong and why. Thank you, making studying much easier
@donerphysics
@donerphysics 4 года назад
The centripetal force is another word for resultant force. We use this word for circular motion.
@familytp8390
@familytp8390 3 года назад
hey, just wondering, for the first example, in the FBD, why didnt you draw the velocity vector?
@donerphysics
@donerphysics 3 года назад
Free body diagrams only involve forces. They allow you to determine the net force which determines the acceleration which determines the motion (velocity)
@familytp8390
@familytp8390 3 года назад
@@donerphysics oh i see
@xinruli5636
@xinruli5636 3 года назад
Hi Mr Doner, I was wondering at 5:50, why can you use mv^2/r and change it to energy, isn't that the net force? How are they interchangeable?
@donerphysics
@donerphysics 3 года назад
I do not understand why you would express it as energy. The (radial) net force must equal mv^2/r for circular motion in the same way the Fnet=ma. a = v^2/r for circular motion.
@adriancfreiburg5044
@adriancfreiburg5044 4 года назад
Isn't the normal force always equal to the weight force? Thats why when we stand still we dont move up or down. Wouldn't it make more sense if the normal force was equal to the weight force plus the centripetal force for objects on earth because it effectively acts in the opposite direction and is of equal magnitude. Would this not also mean that a scale overestimates your weight, because it experiences both your weight force and the centripetal force acting on you?
@donerphysics
@donerphysics 4 года назад
A scale will read a slightly lower value than your weight due to the motion of the Earth. Somewhere around 0.2 N if I remember correctly. We usually ignore this. You are a rotating body, so it is not true that you have no acceleration, and therefore, the real forces acting will not be zero.
@emir2750
@emir2750 4 года назад
i can't stop.
@pollamanxx3993
@pollamanxx3993 3 года назад
ERES MI DIOS TODOPODEROSO (GOD)
@aryamanbansal5734
@aryamanbansal5734 2 года назад
@17:14 If every object needs a downward force of 3N to the the center of the earth in order to move with earth's surface, what would happen to the objects that do not have this? For example, an object weighing 0.020kg (20g). It would have a weight of only 0.20N. Wouldn't it just slide off? I don't suppose the radius could be increased so much to allow for the 3N acceleration required. It would be great if you could answer this question of mine!
@donerphysics
@donerphysics 2 года назад
3N is specific to an 80 kg person. A 20 g object would have a proportionally smaller adjustment to their weight.
@aryamanbansal5734
@aryamanbansal5734 2 года назад
@@donerphysics Yeah that's my bad. Thanks a lot for the clarification!
@kylianjeetmbappe1999
@kylianjeetmbappe1999 2 года назад
Love from downunder
@betulgul5297
@betulgul5297 4 года назад
18:58 So the question asks the centripetal force and the answer is 3 N or 781 N? I am confused.
@donerphysics
@donerphysics 4 года назад
The weight will be less by 3N due to the rotation of the Earth. This is the net or centripetal force on the person. C is for contact force. This is the force from the surface of the Earth, and is equal to 781 N, 3N less than the actual weight.
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