Implementation of Boolean Function using Multiplexers 

That small C' + D thing ruined my day but i came back today to understand this again and found these comments talking about it and now i am relieved !! thank you NESO!

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how did that C' + D suddenly becomes just D?

Aside from the small mistake, this video was very well done and helpful. Thank you!

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How C'+D = D !?

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Thank u very much for your way of description. It really helped me understand the topic and solve similar questions in an extremely short span of time.

WOW.NICE EXPLAINATION AS WELL AS PRONUNCIATION

Explained this so much better than my teacher thanks so much man!

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Very very helpful video. Many thanks.

C'+D=D Who else noticed this mistake🙋

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Ok I understood it was a mistake from the comments, but annotations don't show on mobile devices.

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Sir, your videos are awesome, thank you. But in this videos if we consider C and D as selection lines then will it affect the overal funtionality.? please reply Sir

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Time saver and life saver

Thank you so much sir, pleasent videos

great job sir

amazing explanations,really learnt a lot

good teaching i understood well please can you do with 5 variables, thanx

Thank you so much! This vid was super helpful.

Simplifying function: F = BC' + C'D + A'BD...........(i) Let A&B are the select lines. For AB=00, from(i) F= C'D For AB=01, from(i) F= C' + D For AB=10, from(i) F= C'D For AB=11, from(i) F= C'

Can you please make a video on implementation of function using 8:1 MUX.

the guy's a life saver

Row 2 You have I2 to be C'+ D But for the mux you had D Please y? Thank you I love your lectures

You also need to put playlist link in the discription of every video

Thank you very much ! Its very useful (y)

U made it so easy

Sir I saw your a lots of lecture on digital system , these are very easy to understandand ,after wathing these videos I understood many things. but I have a problem ,one question regarding combinational circuit.......the question is given below.... 1.AB represents a two bit binary number that can be any of the values 00,01,10,11.Similarly CD represents another two bit binary number that can be any of the values 00,01,10,11.Design a combinational logic circuit which gives HIGH output when the numbers AB and CD are equal. plz sir send me answer and logic about that.

What if there was no 1 in one of the rows? let's assume the third row (AB) has no 1, then what would be the value of I³?

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Thank you sir

Brilliant, Thank you.

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This is very helpful but what I got here is this: F(C,B,A)=∑(C'B'A' + C'BA' + CB'A + CBA') ? THANK YOU!

Great explanation . Thankyou

How to implement the Boolean Functions if we have to use a 8X1 Mux ? ps: Do we use the select lines S2 S1 S0 as A,B,C and output depends solely on D or do we we take S1 & S0 as A and B respectively and S2 as an Enable? Would really appreciate a quick answer

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Amazing video! Thanks a ton :)

Thank you. Liked and subscribed.

Thanks a lot. Very useful

Nicely done.

How can I implement a boolean function with 4 variables using only 2x1 MUX? I need a quick response for this one. Thanks.

WORLD CLASS TEACHING PRESENTS HERE❤️

All the remaining actually do this using 8X1 mux .....is this also a correct process

thanks for the videos.

Thank you so much sir

what would the mux look for a 16 to 1

I will be frank I feel like my lecturer for digital electronics is literally following neso academy.

Fantastic! Thanks!

How to implement the same function using 8×1mux

If we have to implement it with 8:1 MUX, then S0, S1, S2 will be connected to A, B, C. 8 Input lines of MUX will depend only on D. You can check it by drawing a truth table or Map. Here I am just putting the results: I0 = D I1 = D I2 = D' I3 = 0 I4 = 0; I5 = D I6 = 1 I7 = 1

I don't understand why I1 is D!! Isn't it C' + D?

If I was used A and B as input than input will input like this I0=B,I1=1,I3=0,I4=A'B please tell me answer

ThankYou ..You made it simple as tht

What if they ask you to implement a boolean function like AB+AC+BC into a 8:1 MUX?

Can we choose any value from a,b,c,d as S0 and S1?

how to can we implement this function using 8*1 mux??

Here, I1 is C compliment or D, but you wrote in the table as only D,may i know why is that written like that

at 6:55 how that becomes D?? isn't it (C' + D) ?? pls clarify sir

please upload a video solve of bolean using demux

why do we need to select selector variables amongst A,B,C and D?

sir plz make a video on to implement boolean function using 8×1 mux

suppose if the row contains fully zeros then what should we do

Thank you 🤗

how is the 1s assigned in the K-map cells to represent the terms in the question i.e 1,4,5,7,9,12,13

hey the f(abcd) and we have to implement it using 8:1 mux...then how it's possible?

I have one doubt if there is 3 inputs then which mux i should chooose or else they only given in questions

what should the steps be if, there are no minterms and only zeroes for some value of AB?

Thumbs up sir!

Sir, i can't do this by using two 4×1 mux & 1 Or gate?

what will be the final value of F(our function) after using multiplexer?

sir, in mux how are selector lines selected ,manualy or automatic

What if the question asks for implementing the boolean function using minimal size MUX, how do we determine which size to use?

But sir how we use this mux for output it gives only one output at one time and also output is only in the form of c and d and for output we have to know also A, B values of selected i/p

We need to draw logic gate right?