Informative video. Have watched a lot from this playlist and really helping me in my project works. But how do I calculate the values for the inductor and capacitor and how do I select the components for the boost converter while designing?
You are right. However, the switching is done at a high enough frequency such that the time for discharge is very small, and the part of the exponential curve in the small time can be approximated as a straight line.
Under steady state, the average voltage across the inductor over one switching cycle must be zero, else the current would keep on rising, which can saturate the inductor. So for inductor volt-second balance must hold in steady state.
its because when you apply periodic current through the inductor the current value is same at the end of each period leading to average value of inductor voltage become zero...Integrate inductor voltage over a period you would get current but as the change in current is zero that integration becomes zero..fyi integrating over a period is essentially average value of that function
@@bonds3865 In case of Boost converter output voltage is greater than input (hence named as boost). Vo=Vt+Vl during off time of the switch, (i,e inductor discharges the stored energy to output at this time, so denoted as negative voltage at off time)
