Java 2D arrays 🚚 

Wow

Thanks bro, the loop now makes sense to me, I didn't understand how the j int was smaller than the i int while they were both zero.

thx bro

@RestedAura2 you mean the opposite right? cars.length : no of objects in column (vertically/ up to down) or Basically determine no of rows cars[i].length : no of objects in row (horizontally/ left to right) or Basically determine no of columns i was super confused on this topic. correct me if I'm wrong

​@@maximizer174bruh, you got it mixed up. Columns are verticles (top to bottom) Rows are horizontal (left to right)

@@transfertransfer986 isn't that what i said? 😅

Boolean comment = true;

If(comment = true) {System.out.println("Amen to that");}

​@@godcomplex1929error

​@@godcomplex1929 your comment is messed up

nice! That's a good visualization

i love pokemon too my code is little diffrent but thNK U BRO

love aesthetic code@@BroCodez

Yes it is not necessary if each row has same number of columns as number of rows, i.e. square array. Let's say if there are 3 rows total, and each row has 3 columns/elements in them, then cars.length = 3, which will work for this case. But, let's say if the array has 3 rows and 2 columns/elements in each row, this logic will break, since again cars.length will be equal to 3, and we know, the third column doesn't exist in any row. So, it's necessary to use cars[i].length as each row is a seperate array in itself. Also, each row can have varying number of columns/elements, which makes it extremely necessary to use the logic. For example consider this array: Tesla, BMW, Audi, Hyundai Mercedes, Volkswagen Range Rover, Buggati, Toyota First row has 4 elements, second row has 2 elements, while the third row has 3 elements.

@@udayrajoriyaa thanks for the great explanation!

cars.length is showing the number of instances that there is on that row. In this case that would be 3. That's why the loop keeps going as long as 'i' is lower than cars.length. cars.length = 3 'i' keeps increasing by 1 until it's no longer less than 3. So it goes like: 0, 1, 2. And then it stops, because 3 !< 3, it's equal. The same way, when you type it as cars[i].length, you are getting the number of instances on that column. On this example, that number is still 3, but if you added another row, it would be 4. Using this kind of loop, you make sure you're passing through every instance on your array. It's checking the length of every row on the first loop, and the length of every column on the nested loop. I hope this made sense, if you have any question, ask again and I'll try to clarify it.

@@albertocasanovalaras3153 got it. But can you please explain why we use cars[i].length instead of just cars.length . The value is 3 in both cases

@@JusticeBeaver619 Imagine as if he made a variable of Columns and Rows, and assigned the values to each, you could have called that variable in the place of using cars.lenght or cars[i].lenght, which essentially means, "if i is less than Columns" or "if j is less than rows"

As i undestand, that's used to read the size of the array. So the as long as counter doesn't surpass the size of the array, it will continue to loop around. Once, the counter matches the size or 'length' of the array, it will stop.

I had the same question lol, but i think it's because it's a 2D array.i'm not sur but i think it's to say the length of the row not the column. I will let Bro answer this :p

Last line needs to be System.out.print(cars[i][j]+" "); NOT System.out.println(cars[i][j]+" "); . Look for the 'ln' before 'print'. That's causing spaces inbetween each bundle of text.