Journeyman Electrician Practice Test (20 Questions With Fully Answers) 

End of the line resistors in fire alarm circuits to supervise open or short circuit conditions..

Didn't realize this was a residential practice test.. oh wait it ISNT!!

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This may help. NEC is your exam. It's the same for US, and open book. NCCER will teach you everything you need to know as well as give your certifications which are kept in database for quick employer verification. *State / Local ordinances vary. Check with your City / Inspector or a little reading. (www.necanet.org/professional-development/careers-in-electrical-contracting/licensure/state-code-licensing-requirements/state-electrical-regulations) NEC- The National Electrical Code, or NFPA 70, is a regionally adoptable standard for the safe installation of electrical wiring and equipment in the United States. *(local ordinances can only make these rules more strict, never less) NCCER- The leader in construction training, education, workforce development and accreditation. Show less

@@crsaalk

it asked inside of fuse. and tin has a low melting point. so tin it is.

Correct, Tin is not used in all fuses. Silver plated copper is common. Although NEC is known for asking questions that can be tricky. Some NEC questions expect you to fill in the blank. If you know different metals are used in fuses, it doesn't specify. We know a fuse has one purpose, break the circuit once overheated. Assuming the limited info from the question you should assume the lowest melting point.

So copper?

@@bambiemalone8457 No. Copper has relatively high melting temp at 1000C. Tin and lead alloy at 230C, which is more preferable in most application.

In my reviewer, i have explanations :)

Nope, theory, like a Delmar's textbook.

so its 120V in the circuit and the current is 12A. but the lag is 60V. so you use the PIE Circle which you'll use (P= I x E) P=12x60 P=720watts - (A) is Amps & Current - (V) is Volts/EMF -Electromagnetic Force - (W) is Power/Watts

+Dallas Henderson Power in an AC circuit is given by the equation, P=Voltage by Current by Power Factor. In this case the Current lags the Voltage by 60 degrees...the Power Factor is always the Cosine value of this phase angle...and the Cosine of 60 degrees is 0.5...therefore, the power in this circuit is P=E x I x PF...that is, 120 x 12 x 0.5...equals 720 Watts.

Manuel Almanza and

Shamrock Shore thank you

Dallas Henderson You're welcome.

So the initial 5 ohms stays at 5 because its in series to the other resistors. Then you use the formula to find the resistance of the 4 resistors in the parallel circuit. So after applying the formula, the 4 resistors @ 1 ohm each come to 0.25 ohms. Then you add the two together making 5.25 Ohms. This website is helpful. www.allaboutcircuits.com/video-lectures/series-parallel-circuits/

Question 10

This may help. NEC is your exam. It's the same for US, and open book. NCCER will teach you everything you need to know as well as give your certifications which are kept in database for quick employer verification. *State / Local ordinances vary. Check with your City / Inspector or a little reading. (www.necanet.org/professional-development/careers-in-electrical-contracting/licensure/state-code-licensing-requirements/state-electrical-regulations) NEC- The National Electrical Code, or NFPA 70, is a regionally adoptable standard for the safe installation of electrical wiring and equipment in the United States. *(local ordinances can only make these rules more strict, never less) NCCER- The leader in construction training, education, workforce development and accreditation.

For china

Power calculated with a phase shift is Voltage X Amperage X Cosine (angle)

We don't have the cosine (angle)

Efficiency = output/ input Here o/p = 10 hp= 7460 watt I/p = 9600 watt Efficiency = 77.7%

i hope this wasn't asked by an electrician

@@beuriavlogs4379 how did you get 9600 as the I/p?

check your ohms law. volts square divided by power(watts) = 1440 ohms. the answer is correct. or you can check amp=1.6 amps

Amperage is 166.666mA. Am i correct?

166.67mA

but 220v squared is 48400 divided by 40 watts is 1210ohms

TheJustReyes it’s 57,600.....

just so you know, the testing is not suppose to test what you know about electrical rather how well you can find answers in the NEC codebook.. so yeah its going to ask you oddball questions