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Lecture 4 - Impedance Matching Networks

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In this lecture, we begin to examine impedance transformations using series-to-parallel impedance conversions in two-element LC "L-match" circuits. We examine upward and downward impedance transformations and the limitations of a 2-element match.

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20 апр 2020

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Комментарии : 14

@user-tu1on5fg9e 2 года назад

THANK YOU MR. WALLING

@abrahamcraig7626 3 года назад

Hi Professor Walling, Why does one need to convert between series matching networks and parallel matching networks? What are some examples that require this transformation?

@islandmonkey87 2 года назад

what would be the source and load in the case of an antenna and an sdr for recieving purposes? is the antenna the source and the sdr the load?

@abdeldjalilselama2490 3 года назад

thank you professor

@mathewgrabau3870 3 года назад

I like your explanation very much, but I'm not arriving at the same value that you calculated at 11:24.

@petzhang3019 Год назад

(4.89*2)/5ghz = 1.956 pH. The value in lecture is wrong. It's also calculated wrong in 9:10, I think.

@SebastianOspinaHD 3 года назад

Hello professor, would you please tell me the book/s you are using for this topic ? I would like to go a little bit deeper, thank you.

@wallingphd 3 года назад

Hi, these notes are mainly my own, but I like Tom Lee's book as a reference. I also think the Pozar text is very good.

@SebastianOspinaHD 3 года назад

@@wallingphd thank you so much, this and lecture 5 videos are very well explained and easy to understand. I'm definitely subscribing to your channel

@pavankumarachanti Год назад

Thank you professor. A little request, Could you up the volume in the video? I couldn't hear it properly even with max volume on my laptop.

@wallingphd Год назад

I will check to see what is wrong with the recording.

@rohitn1704 4 года назад

Is it not necessary to match the input as well ? Why are only matching the output of the 2 element match to rl? Or is it inherently matched to the input when we match for load ?

@wallingphd 4 года назад

The match is bilateral, so if you complete it in one direction, it works in the other direction as well. But to verify, if I start at the source, you could start at the load and make the calculations in the opposite direction and you should get the same component values.

@yurifan2537 3 года назад

Hello professor, I'm bad at math and algebra, was just wondering how the equation at 3:40 became that way after parallel? If you could point me to other sources that may help clarify why it became so, I would be grateful. Thanks in advance.