For anyone who need this MA= input distance / output distance . Distances are inversely proportional to force so MA = Output Force / Input Force. My way of remembering this is " Mechanics (mechanical advantage both share the mech in the name) only WORRY about the INPUT DISTANCE not about the output distance so they can get paid. So be very careful of your input distance because mechanics will try to trick." No hate to mechanics.
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I was looking at Problem 1 and I could be mistaken here :) but it didn't look correct to me. I'll explain. The input side said 200N at a distance of 4 Meters I thought to figure out the amount of force on the input side one just needed to times the mass by the distance so in problem one on the input side it would be 200N X distance of 4 meters which equals 800NM of force and then you would do the same thing on the other side and ask yourself what mass times 1.5 meter distance equals 800NM of force, to balance it all out which would be 533.3333333333333 X 1.5 meters equals 800NM
Yep that’s correct. I don’t know where this guy got 2.7 from. Even if you do dived 4m by 1.5m( WHICH YOU DO NOT DO!) it equals 2.66666667. All you do is multiply the force(200)by distance to the fulcrum(4) which equals (800), then divide that number by the distance from the fulcrum to the weight(1.5m) which gives you 533.333333 And if they only give you the weight that’s on the lever and you’re trying to figure out the force it’s the same formula just backwards. 533.333333 X 1.5 = 800 divided by 4=200.
solving these questions just by making them equal to each other is a way more straightforward way to get the answer. Makes it more like an algebra problem
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If you push the long end of the lever down a distance d1, how much does the other end move up? (Call this distance d2.) Express you answer in terms of L1 and L2. Part 2 Assume that the work you do is equal the work done on the load. Express this assumption in terms of the forces F1 and F2 and displacements d1 and d2, and use your answer from part 1 to derive the lever equation. Part 2 (you can do this part without doing part 1 or 2) If I gave you a lever arm 10 m long, where would you have to rest it on the fulcrum to lift a 1000 kg object off the ground? (I.e., what must the ratio L1/L2 be?) (Hint: The force you can exert is probably largest if you lean on it and push down with all your weight.)
so if according to question 2... my question was to balance this when my resistance was 50 lbs and 30" away from the FC and my effort is what I'm solving for in pounds and its 15" away from FC that 15/30 = .5 then 30/.5 to get 60? I go back to school tomorrow hopefully I'm right and I don't look completely dumb 😁
Question Problem #4. Assume the triangle has only the one right hand side and that is welded to the lever at the apex as shown and the pivot now becomes the bottom of that leg and sat on the ground, is my input length increased by half the base of the triangle and my resistance length reduced by the same measure? I'm making a log roller/lifter. Nice to know the maths that go with it.
Hello. I am designing a machine that uses a pneumatic cylinder to operate a hole punch to punch through sheet metal. I will be using a lever to get a mechanical advantage to provide the force necessary. I am trying to figure out what kind of force would be experienced by the fulcrum or pivot point. I'm not having any luck finding information on how to calculate that. I would appreciate any help that you could provide. I know I haven't provided much detail here but I can give whatever information is needed to calculate that. Thanks.
A bag of sand 25g place at the end of a seesaw and a boy of mass 15g place at the other end of seesaw.the distant between the bag of sand and the boy is 25cm and acceleration due to gravity is 10m/s. Calculate, the mechanical advantage. 2 the velocity ratios. 3 the efficiency of the machine in percentage. Help me solve this example
A proportion: example problem: (2m X 100N) divided by 1m = 200N..............1 st problem: (4m X 200N) divided by 1.5m = 533.33N this is the correct value since it was round off. 2 nd problem: (2.2m X 150N) divided by 4.6m = 71.74N etc review the side with two given value are multiply then divide by the side with one value.
May I ask has anyone already worked out a chart or tablet for a class A lever that provides the force weight and distance needed to lift on the other side? If so kindly provide the Link. Thank you
I have one im trying to get in a book. if any one can help. be awesome. a fire lieutenant is demonstrating how to use a crow bar to lift a concrete slab up about 2 in to allow a piece of shoring to be put under the concretes edge. the lieutenant ask the group of fire recruits to estimate how much effort would be needed to lift a 300 pound slab if they use a crow bar that is 6ft 6 in. long and the fulcrum is 6inch. from the adz end. the recruits would be most accurate if they agreed that the effort would be approximately . the answer says 25 pounds of effort. but i keep missing somthing? i keep getting it wrong. can any one here help?
I see it differently Problem 1. (200N x 4M) / 1.5M = 533.33N Problem 2. (150 x 2.2) / 4.6 = 71.739N Problem 3. (840 x 1)/ 6 = 140N Why the discrepancy?
