Limiting Reagents and Percent Yield

Подписаться 3,2 млн

Просмотров 494 тыс.

50% 1

Chemistry doesn't always work perfectly, silly. Molecules are left over when one thing runs out! Also we never get all of the products that we thought we might by doing the math. You gotta know about the limiting reagents and the percent yield! Don't worry, it's as easy as bologna sandwiches.
Watch the whole General Chemistry playlist: bit.ly/ProfDaveGenChem
More AP Chemistry review materials from me: bit.ly/URPDave
Organic Chemistry Tutorials: bit.ly/ProfDaveOrgChem
Biochemistry Tutorials: bit.ly/ProfDaveBiochem
Biology Tutorials: bit.ly/ProfDaveBio
Classical Physics Tutorials: bit.ly/ProfDavePhysics1
Modern Physics Tutorials: bit.ly/ProfDavePhysics2
Mathematics Tutorials: bit.ly/ProfDaveMaths
EMAIL► ProfessorDaveExplains@gmail.com
PATREON► / professordaveexplains
Check out "Is This Wi-Fi Organic?", my book on disarming pseudoscience!
Amazon: amzn.to/2HtNpVH
Bookshop: bit.ly/39cKADM
Barnes and Noble: bit.ly/3pUjmrn
Book Depository: bit.ly/3aOVDlT

Опубликовано:

27 июл 2024

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист

Посмотреть позже

Комментарии : 224

@AAG414 3 года назад

I always knew Jesus saves, but I didn't think he'd be saving my Chemistry grade

@christisking7911 4 месяца назад

👀💪💪💪✊✊✊🦁🦁🔥🔥🦁🦁🙏🙏♥️❤️❤️🔥🔥🔥🔥💯💯💯💯💯

@denicagovender5029 2 месяца назад

Well,he kind of looks like Jesus😂

@KSBasha_X 2 месяца назад

@@denicagovender5029that was the point of the joke 🤦‍♂️

@katiecheng6551 5 лет назад

professor dave whippin out the bologna sandwich analogy makes him my favorite person ever

@user-pp1bv7yr2n 4 года назад

@arjungupta3095 2 года назад

He’s a living legend.

@ivoryas1696 2 года назад

Katie Cheng It's so intuitive yet effective Some sandwiches are just Bologna(O) and bread(H), others are double or triple decker and have a different medium like... peanut butter (Ammonia), or have different things that act as bologna but aren't or dishes that don't need it (a turkey sandwich or literally just table salt). It's brilliant!

@tontonanharian6840 2 года назад

The best teacher i never tell my friends to be the excell in class. I already speedrun math to linear algebra with professor dave videos and now i came to learn chemistry

@FaizaF 5 лет назад

Came here from Khan Academy. Much clearer presentation than the current Khan Academy video on limiting reagents. Thank you so much!

@adarsh65kumar 4 года назад

I actually didn't understand this video, so I went to the khan academy video after reading your comment.. to see if it would be any different! Strangely enough, I understood their explanation! KA video is more detailed than this one is, I don't understand why you guys didn't like it! In any case ,I'm greatful to both these educators !

@talalarfi2888 4 года назад

i like khan academy more.. they explain it better (my opinion)

@spoicat5459 2 года назад

@@adarsh65kumar Perhaps learning the same thing from multiple teachers helps better, just a hypothesis though, it happens to me too. If I learn something from one video and don't get it clearly enough, I watch a different one on the same topic and it gives me a different perspectives on the same topic, making it a bit easier to understand.

@AryanSharma-kh5zw 5 лет назад

I love you professor Dave, you know all about the science stuff and you made everything as easy as a piece of bologna sandwich ☺

@ericvaish 5 лет назад

yeah yeah!!!!

@viper_3 Год назад

That's why "He knows lot about science stuffs Professor Dave explains" 🎶🎵

@fzfacts9249 9 дней назад

Bhai is bande ki shakal ranveer kapoor se milti h😂😂😂🤣🤣

@fzfacts9249 9 дней назад

Bas bal jangli wale h isko to animal movie me bhejo shikar karega soor ka sala ranveer kapoor ka bhai lagta h ye angrez😂😂😂

@HyacinthChynthia Год назад

Limiting Reagents and Percent Yield are one of the most confusing topics for me in Chemistry. Thanks to you, I understand it better. This is really helpful for students like me. Thank you very much!

@aneesonhisknees1263 8 лет назад

personally you deserve more subscribers and people need to see this.

@ProfessorDaveExplains 8 лет назад

i tell myself that every day! pretty please tell your friends :)

@haidegee142 7 лет назад

I agree!! Don`t worry, 1 quarter is worth more the 10 pennies. The people that subscribe seem to be very fond of you. Thanks a bunch.

@somalialnd4542 6 лет назад

+Professor Dave Explains i don't understand

@Felishamois 6 лет назад

+abdirahman abdilahi because more people watching this channel, which happens in my experience to be the best of its kind on youtube (yes, more appealing and discrete and comprehensive than Khan Academy), means more scientifically literate people, means better world 🙏

@Rieleyhunt 3 года назад

1 week of not understanding class into 4 minute video. thank you chemistry jesus

@rafyraffee 8 лет назад

THIS IS AN AWESOME CHANNEL!! Please for the love of god don't stop making these videos! I need this so I don't fail chemistry!!!

@samisiddiqi5411 3 года назад

It's been four years. Did you pass?

@rafyraffee 3 года назад

@@samisiddiqi5411 Yes, Yes I did. XD

@thatsme6998 3 года назад

@@rafyraffee yayyyyyyyyy

@joelherring4071 Год назад

Thank you Professor Dave for explaining this so well, I've got a final in a few days and need someone to actually teach me well. YOU ARE THAT MAN

@sarahotto7165 7 лет назад

Thank you so much! I wasted so much time on Kahn Academy confused as all hell, and you summed it up perfectly in less than 5 minutes!

@angeliahanaa 4 года назад

exactly!!!!!!!

@desireehaiflich6836 3 года назад

I was here for my retake for a chemistry test, and I fell in love with these videos! Thank you professor Dave

@maazkazi2591 7 лет назад

literally speaking, i just stumbled across this channel looking for revisions before mah test but i was bowled over by the content and clarity of the video. u literally have earned a new subscriber... :)

@castingashadow8588 8 лет назад

Thanks to this video, I am seeing some light. The graphics add a transitioning touch to the relationships of the numbers we just can't quite see with erase markers. You are making a great difference.

@joannabenedicto 6 лет назад

this is such a great channel, thank you prof. dave!!!

@electromc9295 7 лет назад

This is perfect for studying for my grade 11 chemistry exam. Thank you Professor Dave!

@mgrn7106 2 года назад

How is college 😂😂

@electromc9295 2 года назад

@@mgrn7106 no cap you be doin this on the daily in intro chem classes

@richardjohnson9820 6 лет назад

This video is life saving, thanks tons for the explicit explanation.

@jonathanzyambo8286 2 года назад

Professor Dave has been my favorite so far, am enjoying everything.

@barbzgu6518 3 года назад

New subscriber here. Big thank you proffesor Dave for sharing these. It is indeed a big help to us students who are having hard time in understanding the world of chemistry. Peace Be with you.

@haidegee142 7 лет назад

Can I just say, you`re extremely helpful!! Thank you so much!! Keep up the great work, and know that you`re helping so many people, like myself. G-d bless you.

@poorna4424 4 года назад

Indeed your way of teaching is extremely easy to understand you actually deserve 10m or even more than that

@BigLizardEnergy 6 лет назад

Probably the best thing I have ever subscribed to.. thank you.

@monicab1779 7 лет назад

I'm a freshman in college and your videos are helping me so much!! :D thank you for these awesome videos!!!

@noobageownerx3 7 лет назад

thank u i love u i was getting rly stressed out about my chem exam but this video SAVED ME all the other vids i watch sucked

@okthen9145 2 года назад

Thanks for the brief refresher. I love you!

@tonyzhang4368 3 года назад

This is enormously helpful!

@ladyinred396 7 лет назад

Great! with you Chemistry is so easy! thank you for your tutorials!

@Aurora-lw1gb 8 лет назад

Thank you for this. I now fully understand how to compute for the theoretical yield.

@malayapaul458 7 лет назад

woooooo hooooo I said my friends about your channel and they are just loving it!!

@mohamedalj3ly929 7 лет назад

Thanks a lot for your explanations.

@golaiet2 6 лет назад

Thanks you helped me a lot !

@bigpotato4898 3 года назад

Thank you for teaching me in 4 minutes what my teacher could not teach for the past few months

@waleedmian3114 5 лет назад

Hello Sir I am From Pakistan .Your videos are always helpful for me .Biology and chem lectures are admirable .Keep it up 😊

@izzahshahirah4900 3 года назад

love ur expalnation so much..u help me a lottt, tq prof

@GutterBratt 7 лет назад

you are saving my life gr11 Chem exam tomorrow and 0 idea what I'm doing

@SA-be1bn 3 года назад

howd it go?

@mohammedsulaimanmohammedal1512 5 месяцев назад

i need answers how did it go?

@fatimahanwar9324 7 лет назад

thank you 🌸

@karleyrobinson5913 6 лет назад

prof dave literally saves my life

@yousefelzoghpy1885 3 года назад

Thank you very much professor dave 💓

@codosacho5924 9 лет назад

Thanks for your explanation :)

@triple_gem_shining 9 месяцев назад

fun mix of puzzles and math! this is fun! im getting the answers right as well!! woo!!! thanks dave!!!

@applekingkong129 5 лет назад

Thank you for your vids prof

@user-ww3pf4cr8c 3 года назад

Your explains is more than great Mr Dave 🖒🖒🖒🖒

@alexpapas99 6 лет назад

Awesome analogy...

@thechemmole 3 года назад

haha great! I use a similar example when explaining the limiting reactant to my students; sandwiches make for great examples!

@rehanroy9219 11 месяцев назад

Thank you professor dave. Because of your teaching skills my exam was easy

@isaacchewe1825 3 года назад

Thanks Prof. Dave..

@EetMyFlyingV 6 лет назад

Thank you very much Sir.

@jadisvaz 7 лет назад

I have an A in Chem thanks to you!! my prof honestly gives me no help

@ahmedhisham6598 6 лет назад

you are a very good chemistry teacher

@miaab7143 6 лет назад

thank you 🌷

@sanaaanwarr 7 лет назад

Thank you sooo much.😊☺️

@BenjieKabakoff 3 года назад

You are amazing!!!

@truemusic3064 11 дней назад

limiting reagent=number of moles/stoichometric coefficient💗💗

@jasminaktertonni6691 3 года назад

I am come from Bangladesh. Really your lecture helped me

@spencersled7191 3 месяца назад

Great teacher

@devmehta5658 7 лет назад

sir can you please a separate video for difficult questions of limiting reagents and tricks to solve them.

@lucialandero9721 6 лет назад

thank you so much.....

@christianSGB Год назад

thank you, professor you gave us, a clear explanation

@ChemistryTeacher-qz6vp Год назад

This is ez stupid face try takin an art degree then tell me what's hard

@jlpsinde 5 лет назад

Very good!

@jinkang8009 Год назад

thanks professor dave!

@ChemistryTeacher-qz6vp Год назад

If I had $1 per everytime I called someone a stupid face I'd be rich

@tcg-astral 7 месяцев назад

@@ChemistryTeacher-qz6vpI think your the stupid face here 🤣🤓

@angeliemaebonaobra4448 7 лет назад

Thanks!

@patientndivho6 3 месяца назад

Wow❤u teach well...I now understand chemistry ⚗️

@memershub8353 3 года назад

Very nice explanation......in a small amounta time.... :)

@boogiewoogit5597 Год назад

Dammit Dave, that’s a glorious flowing mane you have

@hindah55 7 лет назад

thank you ssso mmuch

@semhararadom1491 Год назад

fantastic...How can I thank you .professor Dave

@hudsonbeyore7786 Год назад

Khan academy took 20 minutes to explain what you did in 4 and yours is still better 💀

@idaraa1162 6 месяцев назад

Bruh how did I understand this in 5 minutes but not in a 2 hour class.😩❤️

@user-abd_almer313 Год назад

رقم افوغادرو 6.022×10²³ رقم ٦ هذا المقصود به كاربون . الكتلة المولية : العنصر × كتلته . C⁶ × 12 . عندما يحصل تفاعل كيميائي العنصر يتغير من جهة اليسار إلى اليمين اي النواتج ، لذلك يجب حساب مول جديد وهذه هي الطريقة : - قبل التفاعل الكيميائي البروبان × عدد المول / الكتلة المولية = المول . - بعد التفاعل الكيميائي المول × عدد المول الجديد / عدد المول القديم المول المحصول × عدد البروبان / عدد المول .

@mawadaabdalaal9916 2 года назад

عاد يا بروفيسر ديف انت الزيك منو 😍..تتعلى ما تتدلى

@sogomomogoso1032 7 лет назад

thanks

@poorna4424 4 года назад

Sir if u have time please try to make a video on equivalent concept in chemistry really hard to get feel and intiution of that topic I would be very very thank ful to you ( from India Telangana)

@spiritforlearning8829 5 лет назад

How do you do the last question professor dave?

@Jean-qg6gx 6 лет назад

Professor Dave is the best of the best... oooops

@mya4855 4 года назад

sophmore taking ap chem with no chemistry background. you made this much easier to understand, thank you!

@panlaura3541 2 года назад

quick question, when we getting the theoretical yield for CH3COOH, why we taking 21.4g as our final answer, not 21.42g. I went back and rewatch the sig figs chapter, but it still couldn't help me with the result. Thank you in advance for helping !

@valeriejackson7416 Год назад

its 3 sig figs so you wouldn't add the 2

@WeirdSpaghetti Год назад

holy shit bro ty

@JuhoHartikainen 7 месяцев назад

The final percent yield 89.3% is a little off because of a rounding error: 19.1 ÷ 21.42857 ≈ 89.1333% ≈ 89.2%. Don't round to sig figs too early in the process and you should be fine 😊

@Tech-cy9yo 3 года назад

Legend...

@mavycarrasco370 5 лет назад

so for the same reaction, if i change the masses of the reagents, could the limiting reagent change? or is it always the same for the same reaction?

@ProfessorDaveExplains 5 лет назад

yep it totally depends on how much you have of them!

@rb-deos8808 3 года назад

How did you get the mole in the problem???

@lmaoo6948 Год назад

thank u chemistry jesus

@user-xi8yh8qi9j Год назад

Am I missing something or is the first conversion factor at 2:37 totally not equal to one?

@thekingofafrica6720 3 года назад

Me singing along to the Intro song and then feeling stupid...😂😂😂🤣😭😭

@Krankenwagen757 Год назад

Thank you, chemistry jesus

@ChemistryTeacher-qz6vp Год назад

Shut up stupid face

@ansamsertawi367 Год назад

Where were you the whole year good sir...

@ceeces 3 года назад

I still don’t know how did he get the stuff that appeared in 1:39 Update: I got it

@noelliekouedan6743 4 года назад

Do you HAVE to find out how much of both reactants can react with each other to subtract and find the excess.

@noelliekouedan6743 4 года назад

Well like the amount of excess

@sraaahsraaah9793 2 года назад

"if you don't understand stoichiometry clap your hands"👏👏

@sraaahsraaah9793 2 года назад

👏👏

@jiinjung1445 4 года назад

Hi, professor Dave. May I ask you why the answer of the question is 89.3, not 90? I thought sig fig would be 1 since the one with the fewest sig fig is 100 (1 sig fig). Sorry if the question is too silly :( and I very apprieciate your well-made videos.

@jiinjung1445 4 года назад

if anyone else could reply to me, I would also very apprieciate.

@Zixxer_rider 7 лет назад

This is great work, but unfortunatley it would be nice if the problem showed how the understanding of dimensional analysis played a role. But other than that it helped me get to an answer!

@ProfessorDaveExplains 7 лет назад

i have a separate clip on dimensional analysis, take a look!

@poorna4424 4 года назад

Sir please please I beg your pardon infinite please video on equivalent concept in chemistry

@oliverlopez4236 7 лет назад

why did you round two sig fig, when calculating?

@ProfessorDaveExplains 7 лет назад

no reason, just to keep it tidy

@emilyfridman6308 6 лет назад

At, 3:59 is the chemical CO , Carbon and Oxygen or Cobalt?

@ProfessorDaveExplains 6 лет назад

CO is carbon monoxide! All elemental symbols have just one capital letter, so cobalt is Co.

@SummerDiablo 6 месяцев назад

Guys pls someone explain how to find the actual yeild if not given

@nonononononono8532 2 года назад

The biggest, ohhhhhhhhh that’s how it works, moment I’ve ever had

@markshere8965 3 года назад

Well i don't know how much he really knows since he reads off a prompter

@user-me1pw6zh1w 11 месяцев назад

when converting to moles in the ex. in 1:45, why can't I convert between the substances after I have just the first substance in moles? and also why do I get different result while doing it in comparison to just calculating it separately? 10g NH3* 1 mole NH3/ 17g NH3= 0.588 moles NH3 0.588 moles NH3* 1 mole CO2/ 2 moles NH3= 0.294 moles CO2 --------while calculating separately will give me 0.227: 10g CO2* 1 mole CO2/ 44g CO2= 0.227 moles CO2

@user-me1pw6zh1w 11 месяцев назад

ok so the answer is because if I do that, I will get the amount of the other substance in moles that will theoretically react flawlessly with the first substance and not the actual amount of the substance. I don't know if anybody needs it but there you have it