Limits, But They Keep Getting Harder! 

That's funny how in France we don't teach L'hospital rule (i learned about it on internet after i got my PhD in maths for example) because we believe it doesn't help students understand what they do, while it's so commonly used as one of the primary calculus tools elsewhere

Once you learn that you can divide by the highest degree term, you also learn that you can just consider that. For example for limit 10 (lim x->inf sqrt(x^2-9)/(2x-6)) you just take sqrt(x^2) on the top and 2x on the bottom, and simplify that to |x|/2x. Now since x approaches positive infinity both |x| and 2x will be positive, so we can just ignore the absolute value and write x/2x = 1/2. That's how they teach it in Italy anyway, IDK about the rest of the world

for level 9, split it into left and right limits then substitute x=1/t for t-> ±infinity to recover usual exponential limit.

9 is harder than 10 😂

limits of polynomial fonctions are all around easy no matter the difficulty

Love love love this video! 🙀😻

For 9 pull the to the seventh power outside of the limit which is possible bc the function is continuous. The limit inside is then actually defined as e so it will be e^7 as a result

I'm here looking for direct/inverse limits

Where is the one-sided limit method?

why no 2,3 dim integrals and lims:(

Level 10 is way easier if you just consider that x^2-9 approximates x^2 and 2x-6 approximates 2x at large numbers. It simplifies to sqrt(x^2)/2x which is just 1/2

😡me when the limit is level 10

I solved the 10th one orally in 3 seconds.