Math Olympiad | A Very Nice Geometry Problem 

You are really an experet in solving geometry problems is very simple way. Congratulation.

Before I played the video I thought the segment between the 2 circles was 3 units, but when I played the video I saw that 3 units is the length of CD, and the problem looked more realistic. I obtained the same answer for E, 4 - 2*sqrt (3)

That is a problem that I SHALL practice bc I this is a combination Pythagorean Theorem, circle theorem, and quadratic equation. Nice!

R=4-2√3≈0,536≈0,54

❤❤🎉🎉😊😊

No way that's a Math Olympiad question. Far too easy.

(2-r)²+(1-r)²=(R+r)² (2²-4r+r²)+(1²-2r+r²)=(1²+2r+r²) r² - 8r + 4 = 0 r = 0,536 cm ( Solved √ )

R = 2(2 - √3) - math olympiad - really?

3-1-R=2-R (2-R)²+(1-R)²=(1+R)² 4-4R+R²+1-2R+R²=1+2R+R²　　　　　2R²-6R+5=1+2R+R² R²-8R+4=0 R²-8R+16-12=0 (R-4)²-12=0 R-4=+-2√3 　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　0