I wish you had talked about and even showed how you calculate the current from the voltage value being read so that you don't have to rely on your library...just one line of code. You didn't talk about this and that is the secret sauce to this whole subject.
Won’t work like that. I have another video which explains how to get the current by calculating it here ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-DVp9k3xu9IQ.html but the library will make it clean and easy.
of course it won't work. ESP32 is different. you may learn it from this lesson on ESP32 which shows how to measur voltage of potentiometer ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-QSYTEytRKHI.html
Under this video click "Robojax" and then search for temperature. Or click here ru-vid.com/show-UCkcBSig_Iu4ZnAIeCeG1TVgsearch?query=temperature Thank you for not skipping the ads and keep watching them. This will help me a lot.
You are welcome. you can learn how to use more than two sensor from this video showing how to use two LCD ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-L6ekl2ABcuY.html
I am not understanding how to make the low pass filter. Could I use a ferrite core? I don’t have access to a oscilloscope. Any suggestions on what components and sizes for a general filter that would be sufficient.
Any recommendation on displaying the getaverage function on an oled display? I get it to work just fine on 16x2 lcd, but 128*64 oled it does nothing. Using the adafruit library.
I figured out the issue. The current sensor library uses too much SRAM and the OLED display will not work. I removed all the variables except the one I needed and the display now works.
Hi Thank you I want to use of this type of sensor for 400A This current is very high and I don't know what is right connector and rote in PCB for it. Please help me.
Hi, using crimp or nut and bolts connect two wires to the sensor and then solder or use bunt and bolts to connect them to your project. If you try to solder to this sensor, the excessive heat will kill the sensor.
Hi, I just noticed that you posted this comment in 2 more videos. for the other two videos, it made sense. but for this video, have you watch the video? if you did not. then do watch it and let me know. you can delete this comment if you thing this is excess.
this library is for Arduino. Before writing the library, I had simple code to calcualte the voltage acrosss this sensor which is proportion to the current. Here is rthe video which I explained it fully. so watch, learn and write your own code for STM32 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-DVp9k3xu9IQ.html
is your question anything to do with this current sensor? if no please post it under relevant video and I will replay. this way other people will learn. I have video on L298N. I don't miss any comment. Post it on any video and all comments are shown in one page where I read and replay.
it is half power supply. at 5V you will get 2.5V. I have explained it here how the calculation is done and how it works . this is without library ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-SiHfjzcqnU4.html
your question made me watch the video because I thought I've answered it. Indeed I have explained it at 10:25 (click on 10:25 to watch it). 0.5% error. Now depending on your module either 50A to 200A the 0.5% has different meaning .so find 0.5% of 50A and you know that you will get that much error. Besides why would you use a 50A (50000mA) sensor to measure 100mA? I would suggest using 3A or 5A module so you get better accuracy. Watch this module which works with 5A. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-3C33DpcSwIw.html but even with 5A you won't get correct value. you should use something with maximum of 1000mA so you can get 10 times smaller like 100mA with better accuracy. with 200A (200,000mA) version you can't even measure anything below 10A (10,0000). Good luck and I hope you reply back if you value this comment. Thanks.
Which part? On the datasheet robojax.com/learn/arduino/robojax_Alegro_ACS770_Datasheet.pdf on page 7 it show ±0.5% error at 25 ° and ±1.5% in higher temperatures. so 0.5% at 50A is 250mA which is withing the range. Also if you noticed, as we approached to above 20A and higher it got much better.
باید ولتاژ بدست آمده که متناسب با جریان است را بخوانی و عملیه ریاضی را انجام دهنی تا قیمت مطلوب به آمپر بدست آید. در ویدیوی دیگر اینمراحل را توضیح داده ام. اما فکر نمی کنیم بدون یک پردازشگری چون اردیوینو یا راسپیری پای این کاررا کرده بتوانی . خلاصه ممکن نیست. سلامت باشید. احمد از خراسان کبیر
@@robojax سپاس فراوان احمد جان من اردینو و برنامه نویسی نمیدانم اما گفتم شاید بتوان به عنوان یک شنت ساده از آن استفاده کرد. در ضمن زندهباد خراسان من هم اهل خراسان هستم ویدیوهای شما را دنبال میکنم همیشه موفق باشید.
you are missing dash at the end like -100U which would be ACS770KCB-100U Look carefully at the sensor that number after dash it the current rating. 100 means 100A 10 means 50A. If I repeat everything I said in the video, then it would be waste my time. ///ACS770 11,// for ACS770x-050B /// 12,// for ACS770x-050U 13,// for ACS770x-100B 14,// for ACS770x-100U 15,// for ACS770x-150B 16,// for ACS770x-150U 17,// for ACS770x-200B 18,// for ACS770x-200U
ما شاء الله .فيديوهاتك جدا جميلة لكن يصعب علينا فهمك باللغه الانكليزيه اذا تسطيع ان تضع ترجمة على الفديو يكون جيدا وشكرا للك. Thank you for every thing
السلام علیکم اشكرا جزيلا. لقد كتبت للتو الترجمة الإنجليزية وقمت بتصحيحها واستخدمت Google لترجمتها إلى العربية. إذا قمت بتعيين لغة الكمبيوتر إلى اللغة العربية ، فسترى وصف الفيديو باللغة العربية. سلام
