Introduction to Finite Element Method by Dr. R. Krishnakumar,Department of Mechanical Engineering,IIT Madras.For more details on NPTEL visit nptel.ac.in
@@Akash-xw4wt this is the net displacement of the nodes since 2 ends have different displacements,hence the net displacement has been taken into account
Within the short span of time, Sir you have covered a lot of concepts very effectively. Your students are fortunate to have you as a mentor. Thank you, sir.
I was slightly sceptical of the quality of teaching in the video, but i was proven very wrong. I am a student in Australia and I was super happy with the way that the professor taught. Thank you very much for posting such videos for free.
Folks...He is professor at IIT - Premier institute in India. It is very coveted position in India and competition is fierce. Most of the time, these professors complete their PHDs in US and come back. I studied at IIT. Students from IITs go on to have very successful careers due to the solid foundation.
If you write u1 and u2 instead of ui and uj, and write F1 and F2 instead of Fi, Fj, you can easily interpret the physical meaning that " kij is the force that has to be applied at j in order to have unit displacement at I"
But when we took an element we considered the forces acting on that element, then why in the end while forming matrices we took F2 = 0 (why we take only external forces, while when were analyzing we had considered the forced on single element????)
Question : at the end of the day isnt the fixed point just having an equivalent force to the opposite side of the force ? Why can't we put the force there ?
He clearly stated that only the external forces are considered in the force matrix. (bcz internal forces are created and balanced itself by the system)
The Fj he showed by arrow is the force on the node 2 by the element. But the Fj he mentions is the reaction force by the wall on the node 2 (opposite direction)
there are no external forces applied at nodes 1 or 2 - fr this reason f1 and f2 will both be 0. the only external force is applied at node 3 which is why f3=p
Ui & Uj have taken based on one end fixed condition - @ 11:50 And @13:20, professor took a force matrix, for stepped shaft and told the above forces to be super positioned, If we apply super position principle Ui & Uj have to take positive as they are not resistive displacements. Can anyone please explain clearly? Thanks
Sorry all, i know my question doesn´t fit FEM matter but what is the name of the song at the beginning?. My Indian Yoga teacher was used to sing it at the beginning and at the end of all lesson.
Because node 1 was fixed so there could be zero displacement in position of node 1. So displacement u becomes 0 and when u solve the matrix 1st row and column do get multiplied with 0 that gives the ans 0 only. So to save time we just eliminate the row n column as it's no use to continue with them