@carta_13just consider paying for Patreon a thanks for his work, one view = 0.0026 dollars or less. That means you're just paying that amount and you're paying for your school tuition yet you're learning more from him?
Thank you so much! I have a test soon and I couldn't go to school for two weeks because of Covid, so I missed half of the Unit, but thanks to you I understood everything in an hour and it is going to help me a lot. You saved me and I owe you a lot lol. Thanks!!
Professor Organic Chemistry Tutor, thank you for an exceptional explanation of Molarity, Molality, Volume Percent, Mass Percent and Mole Fraction in AP/General Chemistry.The practice problems uses conversions and well known formulas to calculate Molarity,Molality, Volume/Mass Percent and Mole Fraction. Conversions is very important in all levels of Chemistry. This is an error free video/lecture on RU-vid TV with the organic Chemistry Tutor.
I’d learned a lot.. This pandemic made me idiot but this video helped me in my subject promise. I even answered some critical solving problem in our chemistry this time.. I automatically subscribe to your channel 👍 💯❤️🤟🏻
I hope you will read this, but I would like to know (14:09) why is the 150mL of H2O was the solute? From what I have solved from that problem it is supposed to be 19.8g of methanol instead of the water so the mass percent of the water is supposed to be 11.7% not 88.3%. I am a fan of your videos I hope you could correct this for us.
It's not that the water really becomes the solute, The mass percent could also be of the solvent rather than the solute. Water will not be solute. The solute is always the one in lower quantity. Don't write it in the exam that water becomes the solute
At 9:16 he says that you have to add the two volumes to know the volume of the solution, but in my chemistry class our professor said that we are not allowed to add volumes of solute and solvent, i am now even more confused hahah.. can someone explain?
You have no idea the relief I felt when I type the topic which I didnt even really know the exact title and your video appearing at first place one night before my exam Thank you
Why did you delete your old videos man :(( ?? Some of those have a lot of examples and concepts that you did not mention in the updated videos. I get it that you have to transfer those videos in your patreon and we have to pay for that. But why man? :((
I have a question, in number 7 , i paused the video and solved it by myself, i got the molarity : 0.0013 , but i went over my solution a couple times and I can’t find my mistake , why did you consider the mass of solute 15 and mass of solution 100? Isn’t possible to be other values?
watching this the night before an important quiz, i really don’t want to fail nor can afford to but my brain just refuses to absorb information in class
Hi, what if the problem is like this. A solution was made by dissolving 20.0 grams of potassium chloride in 200 grams of water. How many moles of each compund were used?
At 27:54 He said 15 over 100 g then said 30 over 200 g then again he said 30 over 100. Can anyone explain this problem ? Should we divide 30g with 100 or should we divide it with 200 g of soln?
Man you should use questions that are more easy with numericals like not easy but likely solvable cuz rn everyone here comes to learn the concept and when you use Question with more calculator use most of us stop following your video cuz now its just mess in our notes of calculation which is not needed when you are learning a concept
Thank you, sir, for this tutorial. It really helped me. However, I do have one issue, which is that I'm a bit confused in the section concerning the decimal places you utilized in your answers.
To get the v% ,you have to first get the volume of solution.which is volume of solute + volume of solvent,i.e 150ml volume of solvent plus 25ml volume of soulute.. although methanol and water are substances that can be used in dissolving i.e they can both be seen as solvent.But, since the volume of water in this case is higher than that of methanol,he simply made methanol the solute and water the solvent.
1. Find mole fraction of glucose in 5% solution which is used as normal saline. 2. There are two solutions of one substance. The osmotic pressure of the first one is less than that of the other one. Which solution freezes at lower temperature? 3. What is the depression in freezing point of 1% albumin solution? The molar mass of albumin is 68000 g / mol.
Thanks for the videos. I have been following you a good number of times. And I must admit that you are the best. But have a little concern about the second problem of the lesson. Calculating a volume percent. I was told that mass is additive when you are working with percentage concentrations. But volume is not. But I noticed problem 2 while finding V% you added the 25 ml plus the 150 ml to give you 175ml. Why is that so? If the v% formula is V% is the volume of solute divided by the volume of solution. I am not challenging you but just a concern and I want to learn. Thanks.
Agreed--masses are strictly additive while volumes are only approximately additive. The density of the final solution is needed figure out this problem.
I don't understand what you did in the 5th question, in the fourth question you used the molar mass of the elements to convert grams into moles, but in the 5th question you used atomic mass to convert grams in to moles. Why?
0:51 "The solvent is da stuff that is doin da dissolvin" I am not even joking when I say this: the way you talk literally makes in easier to listen too, and easier to learn. I love it! Everything about you videos is MUAAAH! *chef's kiss* "perfect"
Anyone knows what's the topic for this question. I missed some classes and im trying to catch up, but i got no clue what shes teaching. What volume carbon dioxide, measured at stp, would be produced if 3.65 g of magnesium hydrogen carbonate reacts with excess nitric acid, as below: (5pts) Mg(HCO3)2(s) + 2HNO3 (aq) → Mg(NO3)2(aq) + 2CO2(g) + 2H2O (l)
" A mass of 3.3214 g of sodium bicarbonate was dissolved and diluted to 250.00 ml of aqueous solution. A 29.55OX mL of sodium bicarbonate solution was used to neutralise 25.00 ml of H2SO4 solution during a titration. Calculate the molar concentration of H2SO4 solution. " Can u please help me with this one 🥺
Teacher pls help I have questions about molality my teacher gave the both sloute and solvent by gram I mean he gave the solute as gram and also the solvent as gram in here is it imp to change solute to kg to be match with molality because all we know that molality is mol over kg did I need to convert it to kg and also do I need change mass of solvent to kg ?
suggestion: if you could not have the question written at the very top of the screen and move it down a bit. They become completely invisible if you pause to solve them on your own
I can do this. The problem is when it asks me something where I have to use like every single one of these formulas but my teacher never showed me how to do so
