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Thanks, though you have made a mistake at kcL B , because if you multiply -4(2-vB) You are supposed to get ( -8+4vB) So that you get =2vB-VA+vB-8+4vB If you solve further you get vA=7vB-8
I hate long video tutorial and yours is just so brief and simple easy to understand and fast to learn a big topic in less then 10 minutes thank you for this so helpful
In KCL - A you multiplied -6 by -va which you have as -6VA which should be +6VA . If it was -6VA you would not have 13VA but instead just have 1VA.. to get 13VA it has to be positive.
Hi, I like your teaching but i have one doubt in this video. I want to know why i3 goes on right side? can't it go to left too? Please reply! much appreciated
I just assumed a direction for i3, in this case it was to the right. When I drew it, it was an unknown, and I could have assumed either direction. If i3 ended up being a negative vale, then that would have told us that it was in fact pointing the other direction. However, in this example, we calculated i3 to be positive, so our assumed direction was correct.
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Can you do one based on wheatstone bridge? also it seems from other comments on other videos that professors leave specific details out to "appreciate how to get the right answer" people don't have time to mess around.
I dont understand why i3 on one side is traveling in and is respresented as a positive ? and on the other set on node be as a negative ??? what is going on??
it's quite easy, actually! it's elementary level maths; basically you single out all the numbers on the bottoms of the fractions, line them up and start dividing with numbers in hopes of getting each number to a 1. for example, if you have 1, 2, 4 like in the Vb portion of the video - you ignore the 1 because it's already a one, so you have 2 and 4 left. both are divisible by 2, which - when divided - leaves you with a 1 and a 2. then you divide them again with a 2 and the end result is three ones, with two twos you used to divide them with. then you multiply the numbers you used while dividing (aka 2 and 2 here) with one another, and the end result is your common denominator (4 in this case). hope i was able to help!
