I feel so lucky ❤️ to have this vidoe in RU-vid.....Even after joining classes also no one taught us in this way ....My doubt are getting clear thanks u so much @neso academy. Really appreciating your efforts and continuity....
no because power is delivered so you cannot put positive sign with it as it shows power sink.... which is not true in this case as power is being delivered. Current is leaving node v2 and entering in the 2V Voltage source.
Wow. Failed on my first attempt (due to my not sticking with arrows leaving node ALWAYS and botching final KCL) Don't overthink it, it will work out with that convention.
@Neso Academy Sir as per your previous lectures power absorbed is +vi because it is leaving the - ve terminal and power delivered or supplied is -vi because it's entering positive terminal...here it should be -70w in this case .please do clear this ASAP
See video by gate academy maybe you'll understand coz it's the direction of current which decides the value. The same souce and deliver the power as well as can absorb the power
Sir at 6:24 we have to write the kcl,so in the current towards 3V which is dependand source why u didnt considered the resistance which should be zero so the equation will be 2v3 - v2 - v1 = 0 . Could u explain this
see because in current sources the internal resistance is considered infinite and not 0 (parallel connection). First things first I think you misunderstood that this is a current source and not a voltage source. The current that it provides is 3 times the Voltage across the resistor that says above it in the schema provided. say if the voltage across that resistor happens to be 10V the VCCS source will provide to branch 3*10 = 30A. Hope it was helpful but it has been 2 years...
sir in the previous question you said when the voltage source is between the reference node and the non reference node then we dont need to find the kcl equation for that and then you just wrote the value for v1 =0 therefore in this question also we can clearly see that the 5 v voltage source is between the reference node and the non reference node (that is the ground one) therefore why didnt we said the value of v1=5 v. Does that means that this rule is only applicable when the reference node and the non reference node contains voltage source in between but no any resistor????? pls reply at the earliest sir!
Can't you just solve the equation after finding nodes?? What will you do by saving 5 mins?? I really like your explanation but please explain that also
Sir isn't it p=-i.v ??? Because current is entering into the -ve terminal of the volt srce (2v)??? I know power can't be negative but as per your previous class explanations u told that if the current is entering into the -ve terminal then it acts as source, if it enters +ve terminal then it acts as deliver. I'm a bit confused...
I think you are right, power in this example is -70 W. But he is talking about Power delivered, and we know that power delivered is a negative quantity AND power absorbed is a positive quantity. Meaning that saying that P=-70W is similar to say that the power delivered is 70W.
- 70W means 70W power is being delivered. So, he is right. and when you get positive value of power that means the power is being absorbed by that component. Thanks
why at node 2 we didnt performed higher potential i.e V2 - reference node i.e 0v = 2v ans hence voltage at node 2 will be 2 v. Instead of this why you have applied kvl in it when similarly you have done in node 1
tricky question its "power delivered" and not "power produced". So you don't care what direction it is. You just wanna know how much power is there at x point in time. So ireelevant which side you chose
So from combining eq 2 and eq 1 you get the eq 4 which initially is 5/2(V1) - (V3) = 4 you 2x both sides and you get 5V1 - 2V3 = 8 (eq4). What you have written here is equation 1 and you wrote it wrong too. Go slow and methodic so you don't make these mistakes
Hello sir To be very honest I want to inform you that on RU-vid many resources are already available for preparation of network theory and basic Electrical engineering We know your capability , please complete the course of power system first , since on RU-vid no authenticated resource is available for it's preparation
i got currrent in 2V source as 17.5 amps. i cross checked it multiple time.i.m still geting the same ans. do any one have the same ans? power delivered will be 35 watts.
You don't need to use KCL at Node2 at first go around. You are trying to find the voltage potential at all nodes. At Node2 specifically, you can get the voltage directly because the 2v independent voltage source lies between Node2 and ground (without a resistor in the branch providing a voltage drop.)
