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Nyquist 2 - sketching from gain and phase information 

John Rossiter
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6 окт 2024

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Комментарии : 44   
@qawsed9260
@qawsed9260 7 лет назад
Nice video! It's the best video on the internet which explains how to plot nyquist from bode diagram.
@rick_er2481
@rick_er2481 6 лет назад
True!
@Fireflyepic
@Fireflyepic Год назад
If I had found you sooner I'd be killing it in control systems. It's a shame that, at university, these topics are taught often by researches who begrudgingly teach. By the end of the quarter, only about a third of the students in my control system class were even attending lectures anymore. Thank you for putting videos like this on RU-vid.
@StasionSpasski
@StasionSpasski 5 месяцев назад
The best video on this topic by far and I am not joking. I swear you can't imagine how much stress and time I spent on trying to understand but only your videos have finally managed to help me. Bless you
@foolishbear8329
@foolishbear8329 6 лет назад
thank you sir, as a French student it was clearer than the French videos!
@chiaraferrari3461
@chiaraferrari3461 6 лет назад
Very good video. I think it illustrates very clearly how to obtain the Nyquist diagram from Bode and clarifies several things along the way. It is also very easy to follow, even for someone who is not a native English speakers like me.
@buckeyefan635
@buckeyefan635 6 лет назад
Thank you, sir! Very helpful insights on a poorly taught topic.
@davidjara7032
@davidjara7032 4 года назад
seven years ago and this video is very helpful thanks you and I'll subscribe
@wuffi178
@wuffi178 8 лет назад
Thank you for this explanation, exspecially for the guidline for quick sketches :)
@rounakparekh1321
@rounakparekh1321 9 лет назад
very very useful and informative video. all my doubts and queries are cleared watching this vid! hatsoff to John Rossiter for this awesome explanation :)
@Andrei-ds8qv
@Andrei-ds8qv 6 лет назад
One of the best videos I-ve ever seen! beautiful voice, very clear explination, very nice how you go from easy things to hard things and explain SO WELL EVERYTHING!! THANX
@xMrJanuaryx
@xMrJanuaryx 7 лет назад
Not sure if you forgot to mention or if I missed it but the plot he derives you need to reflect that about the real axis for the full Nyquist plot. Super helpful though here ive been trying to figure it out through Nyquest criteria and that is painful to say the least when all you want to determine is regions of stability...
@MrsChocolock
@MrsChocolock Год назад
How can you calculate or estimate 6/4*sqrt(3) = 0.9 so quickly?
@curtorepe3626
@curtorepe3626 Год назад
Perfect video
@foysalahmmed2586
@foysalahmmed2586 6 лет назад
thank you very much ... the turorial was useful and understandable...
@GermainRufio
@GermainRufio 11 лет назад
really, really helpful. I whis my teacher could exaplain like you do sir. Thank you!
@rammohanty6373
@rammohanty6373 7 лет назад
how can draw bode plot easily ,to find out inwhich gain verus corner frequency
@ivancalvimoreno629
@ivancalvimoreno629 8 месяцев назад
Excelent! thanks!
@mohamedquabbou5253
@mohamedquabbou5253 7 лет назад
thank you man you helped me so much
@benjamindeworsop8348
@benjamindeworsop8348 5 лет назад
Saviour thank you!!
@marcocardona4258
@marcocardona4258 5 лет назад
Thank you!
@abdallahbukhari4382
@abdallahbukhari4382 4 года назад
Thanks a lot
@adelsalam9735
@adelsalam9735 2 года назад
nice and helpful thanks
@mohamedmarei6571
@mohamedmarei6571 11 лет назад
This has not been incredibly obvious for me from the start, but the gain and phase "arrows" are meant to be perpendicular to each other, right?
@alisirte1
@alisirte1 4 года назад
Great explanation, but please correct 6/square root(4*7) this instead of 4*12
@blackcat-mp7kh
@blackcat-mp7kh 2 года назад
6/square root(4*6)
@blackcat-mp7kh
@blackcat-mp7kh 2 года назад
it should be 6/square root(4*6) at 11:20, right ?
@johnrossiter2323
@johnrossiter2323 2 года назад
Sorry some obvious typos are in some videos.
@db5112
@db5112 9 лет назад
sorry if i don't see it, but how did you get sqr(4*12)?
@johnrossiter2323
@johnrossiter2323 9 лет назад
+Diego Ballesteros sqr(4*12)=sqr(4*4*3)=4*sqr(3)
@lorenzcinema
@lorenzcinema 8 лет назад
+John Rossiter Where does the 4 come from?
@abhideepsingh4484
@abhideepsingh4484 8 лет назад
+lorenz ed I had same problem also. check previous video for details. G(jw)=6/sqrt((w^2+1)*(w^2+3)). Then just put w=sqrt(3). enjoy.
@abhideepsingh4484
@abhideepsingh4484 8 лет назад
+lorenz ed I had same problem also. check previous video for details. |G(jw)|=6/sqrt((w^2+1^2)*(w^2+3^2)). Then just put w=sqrt(3). enjoy. discard my older comment.
@tex-xm6id
@tex-xm6id 8 лет назад
Hello,sorry what is the method to get 2 at the y axis at the moment 10:00? Thank you very much!
@johnrossiter2323
@johnrossiter2323 8 лет назад
This is not in dB but just the steady-state gain ( that is 6/3)Anthony
@tex-xm6id
@tex-xm6id 8 лет назад
I understood.Thank you!And have a nice day!
@fatimas9801
@fatimas9801 8 лет назад
I still do not know how to use the frequency while graphing?
@steffandall5785
@steffandall5785 5 лет назад
The frequency is omega, we define s=j*omega. Then s is defined, in this paticular example as s=sqrt(3)*j. When you calculate the gain and phase you exclude the j.
@OlafvanBuul
@OlafvanBuul 8 лет назад
Hello, At 10:43 how do you get so quickly at sqrt(3) as the middle? Regards, Olaf Thx for sharing these videos
@johnrossiter2323
@johnrossiter2323 8 лет назад
+Olaf van Buul Because there are only 2 poles it is easy to show that the phase of (s+a)(s+b) = 90 degrees when w^2=ab.Anthony
@persianshawn92
@persianshawn92 8 лет назад
where did you get the square root from in the calculations you do at 11:24?
@johnrossiter2323
@johnrossiter2323 8 лет назад
A well known result (obvious from right angle triangle) is that atan(w/a)+atan(w/b)=90 when w^2=abAnthony
@tomahan044
@tomahan044 7 лет назад
i like this
@adrienguidat2214
@adrienguidat2214 8 месяцев назад
belle perf
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