How to solve a quadratic equation. 1. by factorization and then equate to 0 2. by using the formula I used 1. so after factorization. I have (y-5)(y+10) = 0 so, I still have to find the value of y... so, equate to 0 (y-5) = 0 and (y+10) = 0 so, sending the constants to the other side will change their signs y = 5 and y = -10
Question: Triangle B (object) is mapped onto Triangle C (image) ✓ Transformation Matrix = *Matrix of image* multiplied by *Inverse of Matrix of object* • Take any two corresponding points i.e for image if we take (7,2) and (8,2) then for object we can take (-1,2) and (-2,2) • Take the inverse of object points • Put the points in the formula above
The value was in cents and we were supposed to give in dollars. To convert cents into dollars we divide the value by 100. And to convert dollars into cents we multiply it by 100
Great work sr, this is helping so much!!!🙏 I have a request please, if you can solve physics and chemistry yearly past papers as well, I will be grateful 😭 it will help A LOT PLEASEE
Sir in the last question, in which we had to find a matrix. Is that still included in our syllabus because wasn't that matrix representing shear or stretch?
The question says: *half* of the red beads have a yellow spot • We have found the number of red beads in part (iii) which is 12 so half of red beads would be 6 • The total number of beads in the bag is 20 (12 red and 8 blue) • This means that beads which have a yellow spot are 6 out of 20 Back to question, they say *two* beads are chosen and *neither* has the yellow spot • Beads which don't have yellow spot = 20 - 6 which is 14 • Probability of first non-yellow bead = 14 out of 20 Probability of second non-yellow bead = 13 out of 19 (reduced as we are not replacing the beads) • Total probability = 14/20 multiplied by 13/19 (We multiply as we have to find probability of first bead AND second bead)
