The algebra/proof is well explained here. I'd like to point out that you can use geometric reasoning. To get the max area then the width would be two times the height. i.e 2H = W. Using your perimiter(p) relationship, you get P = 2H + W+ .5*pi*W, substitute the 2H for W and you get W = 2P/(4+pi). Since we said W = 2H, then H = P/(4+pi).
he factors out the w basically, (1w+1/4pi w)=8 > w(1+1/4pi)=8 you can think of the w=1w, 1 is a constant which is never really written but its always there..... hope that makes sense
+Neki Haig You may be able to determine the area alone, but you need the derivative to determine the dimensions of a maximum area given certain thresholds; in this case, the threshold is the maximum perimeter of 16 allotted in the problem