Parallel Impedance

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Calculate the impedance of an AC circuit when resistors, capacitors, and inductors when connected in parallel. This video shows that the total impedance of parallel components is equal to inverse of the vector sum of the inverse of the impedance of the individual components.
David Williams
www.elen.ca
Outro Song Credit: Hexbug Racer by Rachael Pauls

Опубликовано:

13 сен 2024

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Комментарии : 9

@dariankavu8386 4 года назад

Wonderful video

@dalenassar9152 2 года назад

LEARNING A LOT HERE!! I need a simple formula for the "resistance" of a standard parallel LC circuit at resonance. I know that changing any of these values (L and or C), changes the resonant frequency according to: Fr=1/[2pi sqrt(LC)]. I have seen that it is given as simply: SQRT(L/C). Is this correct? THANKS MUCH... and thumbs up!

@ElectronXLab 2 года назад

You are correct for your resonant frequency equation. The 1/sqrt(LC) equation (note that it's not L/C) gives you the resonant frequency in radians/second.

@dalenassar9152 2 года назад

@@ElectronXLab Thanks for the reply, but I was speaking of the formula for the resistance or impedance (not frequency) in order to calculate the current in the parallel LC circuit. I have seen somplace SQRT(L/C) gives impedance. I need to be able to calculate current flow in the LC tank WHILE it is oscillating at it's resonant frequency. Thanks again...

@marcthibault2978 5 лет назад

your calculations for converting into rectangular coordinates don't check out if your conversion is what you said it was. for the first 2 its off by 2 decimal places and the third just is not correct

@spelunkerd 2 года назад

I did this independently before reviewing his result, and got a similar result to what the author found. Rounding of multiple sequential data points can cause variance. If your results are way off, check your work. It's very easy to make a housekeeping error, and it can be frustratingly hard to find.