Part-1: Shell & Tube Heat Exchanger design with Example, Shell dia.& tube bundle dia., No of tubes 

Most welcome

Glad you liked it

Glad you liked it

Glad it was helpful!

Yes I will

sorry couldn’t

Sure I will

Regarding NPSH, performance already uploaded

Yes, that comes under mechanical designing.

Yes, This is the kern’s method.

Which is 0.013 how it is come??

​@@aniketkambli9581part3 dekho....😊

tube inside diameter kaha se aaya?

of course it is possible… many options there use of heat exchangers using cold stream on other side, integration approach with heat integration and many more

Will upload soon

Equations will be different to calculate heat transfer coefficients ( Density of both phase will be included)

The other fluid??

You may start with 200-300 (If liquid liquid fluid there)

Thanks for watching the video cautiously. But yes may b you're making a small mistake somewhere. Flowrate conversion : 450 L/m --->27 m3/hr ---> 23463 kg/hr ---> 6.5175 kg/s Cp : 2.1413 Kj/kg C Del T : 20 Q = m Cp Del T= 297 KW Hope this will help, let me know if still any confusion there.

@@chintanconcept Sir why you have not multiply 1000 m3/hr to get kg/hr?

Sir any source to take out the value of Cp?

No, If I will not assume U, Then how we gonna calculate available area, no pf tubes. Base on no of tube we calculate shell diameter Shell diameter is used in baffle spacing calculation and many more calculations are dependent on that. Basically this kern’s method is trail & error method.. Its not the straight forward method Hope that clears ur doubt

If you are here, means you forgot the above concept. So Better study😂

Its a generalised value, like organic , inorganic, viscous fluid etc