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Plot IDS vs VDS for the circuit : Interview question for "Analog Circuit Design in a MNC" 

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In this video we will solve the question without using equations.
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2 окт 2024

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Комментарии : 13   
@vlsiorg
@vlsiorg 3 года назад
Correction to the last part of the graph : For VX > 1V , Vx will be the drain , So VGS will be 1V and the mos will be on . Under this condition , for VX >=1V MOS will be in saturation. *For VX=1V IX=0 , VDS=0 here. *For VX < 1V , Vx wil be the source , under this condition , as rightly pointed out by you, we are at the edge of saturation. So for VX
@praveenkumarmaddeti6668
@praveenkumarmaddeti6668 3 года назад
For Vx>1V --------> Ix = 0. For Vx
@vlsiorg
@vlsiorg 3 года назад
Hi Praveen , thank you for pointing out. There is a correction needed in the last part of the graph. *For VX > 1V , Vx will be the drain , So VGS will be 1V and the mos will be on . Under this condition , for VX >=1V MOS will be in saturation. *For VX=1V IX=0 , VDS=0 here. *For VX < 1V , Vx wil be the source , under this condition , as rightly pointed out by you, we are at the edge of saturation. So for VX
@skyhawk3300
@skyhawk3300 5 месяцев назад
@@vlsiorg For Vx>1, the MOS is in saturation, but (Vgs-Vt) = 0, so by the square law, Ix should also be 0
@vlsiorg
@vlsiorg 3 года назад
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@pavankori6986
@pavankori6986 2 года назад
Hey when you make regarding this for correction in last paragraph??
@GeekSlayer72
@GeekSlayer72 Год назад
If Vx is really high, we agree that the VDS is high and the MOS would be at saturation. However, VGS-VTH = (2V-1V)-1V = 0V, hence, shouldn't Ix= 0A?
@vlsiorg
@vlsiorg Год назад
Hi. I am not use if i understand your question correctly. For VDS > 0 and Vgs-Vth =0(saturation) . There will be current . You can also look at it from the I-V curve perspective . Thanks
@praveenkumarmaddeti6668
@praveenkumarmaddeti6668 3 года назад
This plot is incorrect. Check once..
@vamsigirish4790
@vamsigirish4790 2 года назад
Nice
@VishalKumar-ii7jy
@VishalKumar-ii7jy 3 года назад
Re-check please.
@vlsiorg
@vlsiorg 3 года назад
Hi vishal , i have written the correction in the comments. I will soon make a update on this in my next video. Thank you 😃
@dhaneshprabhu72
@dhaneshprabhu72 2 года назад
@@vlsiorg since the gate to source voltage is not more than threshold, will there be any current. That's my doubt
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