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Position or displacement time and velocity time graph relation 

Anil Kumar
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Sketch Displacement - Time Graph from Velocity - Time Graph
Velocity is rate of change of displacement
Acceleration is rate of change of velocity
Displacement is Area Under Velocity - Time Graph
Velocity and Displacement Relations with Graph: • Position or displaceme...
/ @mathematicstutor
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Displacement Velocity Acceleration Graph : • Position or displaceme...

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24 авг 2024

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Комментарии : 130   
@ghsjgsjg53chjdkhjydhdkhfmh74
@ghsjgsjg53chjdkhjydhdkhfmh74 4 года назад
Thank you! I came for a level mechanics and this is the best one yet explaining motion of displacement time graph😍
@MathematicsTutor
@MathematicsTutor 4 года назад
Thanks for appreciation. Here is related playlist: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE--Yr3hK26CzI.html
@am-cb8vn
@am-cb8vn 4 года назад
@@MathematicsTutor thank you
@hirunisiriwardhane4361
@hirunisiriwardhane4361 3 года назад
i am in sri lanka and i had many smALL but too much necessary points to know but i never found solutions untill i watch this vedio so absolutly thanks sir anil kumar for delivering succh sort of useful clip
@erumfawwad1464
@erumfawwad1464 5 лет назад
Excellent demonstration. I always come back whenever I'm going kinematics graphs.
@MathematicsTutor
@MathematicsTutor 5 лет назад
Thanks a lot. All the Best!
@joytighosh2314
@joytighosh2314 4 года назад
@@MathematicsTutor thank you
@buikhanhlinh1145
@buikhanhlinh1145 4 года назад
You have made my studying SAT physics easier!!! Thank you!
@ajibolaekunola
@ajibolaekunola Месяц назад
Very informative
@Googlegoogle-cr7pu
@Googlegoogle-cr7pu 6 лет назад
voice and video super sir
@Master-vd4qd
@Master-vd4qd 5 лет назад
Outstanding... Sir
@Aadi_7779
@Aadi_7779 2 года назад
Gd
@zerog1064
@zerog1064 2 года назад
Thank you so so so so soooooo much!
@hitesha699
@hitesha699 2 года назад
Just wowwwwwww wow amazing explanation sir....amazing!°!!!!!!
@MuhammadUsman-sk8uz
@MuhammadUsman-sk8uz 3 года назад
Grt Work Sir
@corneliusharris152
@corneliusharris152 3 года назад
Explained it better than my teacher thanks
@tanmaysharma3335
@tanmaysharma3335 6 лет назад
Nice explanation
@khalidibrahim4232
@khalidibrahim4232 11 месяцев назад
🔥🔥
@norhanaambel531
@norhanaambel531 Год назад
Thank you, sir!
@dhruved.
@dhruved. 2 года назад
Can't express my feelings sir... ThaNK You so much i required this urgently!!!! 😭❤️🙏
@javien-dn9ps
@javien-dn9ps 7 месяцев назад
thank you for your help w my physics homework!!! god bless u
@MathematicsTutor
@MathematicsTutor 7 месяцев назад
Best Wishes
@jeetendrapratap5050
@jeetendrapratap5050 3 года назад
Awesome explaination sir
@ashizafar6553
@ashizafar6553 4 года назад
Awesome 😇
@shantot.a7874
@shantot.a7874 3 года назад
Thankyou
@DailyMovieClipsAI
@DailyMovieClipsAI Год назад
anil kumar the GOAT
@hafizfakharudin4557
@hafizfakharudin4557 3 года назад
It was a beautiful lecture...Indeed
@abhi.j7780
@abhi.j7780 2 года назад
Great teaching sir, thank you so much
@rapbeats162
@rapbeats162 Год назад
Thank you very much
@clintn.kildepstein1656
@clintn.kildepstein1656 3 года назад
Thank you so much sir for helping me
@StephenTech
@StephenTech 6 месяцев назад
Absolutely amazing explanation, was struggling with this in both A-Level Maths & Physics, this video has helped me understand better than any of my teachers (:
@madhubalazinta6730
@madhubalazinta6730 4 года назад
Thankyou sir for making it easier for us.
@JeanCloueLBacho
@JeanCloueLBacho 3 года назад
Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺
@rahanata7829
@rahanata7829 4 года назад
Really helpful sir Thank u May God bless u
@SOMESHWARKANDREGULA
@SOMESHWARKANDREGULA 6 лет назад
Thank u sir u really cleared our doubts, voice was really apperciable....& pls explain with any numericals...
@hohahehi
@hohahehi 4 года назад
perfect teaching
@ashatv9452
@ashatv9452 3 года назад
Superb class understood very well Thank you so much sir❤
@aartisorout2416
@aartisorout2416 3 года назад
Good sir
@inokarathnamali8251
@inokarathnamali8251 3 года назад
Thanks for the video Thank you
@Rk95122
@Rk95122 Год назад
Thank you, Sir.
@samarbandodkar12
@samarbandodkar12 6 лет назад
Excellent
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks for appreciation. All the Best!
@samarbandodkar12
@samarbandodkar12 6 лет назад
Anil Kumar thank you
@VK-il9kv
@VK-il9kv 4 года назад
v useful thanks
@patricksilvestri2406
@patricksilvestri2406 5 лет назад
Amazing Video!
@magalin1442
@magalin1442 4 года назад
VERY HELPFUL!! THANK YOU SIR
@fawlen_eynjuhl
@fawlen_eynjuhl Год назад
thank you sir
@_.aintforu_2
@_.aintforu_2 7 месяцев назад
Thank you it helped me a lot
@AhmedHassan-vj6hz
@AhmedHassan-vj6hz 4 года назад
many thanks
@ritika_bhattacharjee
@ritika_bhattacharjee Год назад
thank you! this really helped
@myousaf634
@myousaf634 4 года назад
Thanks sir u understand 👍
@thiliniwijesinghe7739
@thiliniwijesinghe7739 2 года назад
Thank you so much sir!! Very helpful 🙏❤
@kerryloh5285
@kerryloh5285 3 года назад
sir,so the zero in velocity-time graph is just a turning point and not mean the object stopped when at zero? unless no line is drawn behind the zero in velocity-time graph?
@larafalls4329
@larafalls4329 4 года назад
Super informative. Thanks!
@ericadixon9400
@ericadixon9400 3 года назад
THANK YOU!!!!!!!
@user-yp2dr8ny6f
@user-yp2dr8ny6f 9 месяцев назад
Thank you a lot man!!!!
@anilkumarpathiyadankesavan6698
Thank U sir...osm explanation.
@KaushalKumar-ti3kz
@KaushalKumar-ti3kz 3 года назад
Thank you 🙂
@BIDEN-re7ry
@BIDEN-re7ry 3 года назад
thanks!
@Butterscotchbutt
@Butterscotchbutt 6 лет назад
very nice!
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks for your time and appreciation.
@abigailgiles7451
@abigailgiles7451 5 лет назад
Very helpful!!
@AmanSharma-wn8qh
@AmanSharma-wn8qh 5 лет назад
Sir veryyyy thank you . I don't know how much I facing problem with that .
@amyalexander7360
@amyalexander7360 4 года назад
makes sense sir, thank you!!
@milaspalmer8036
@milaspalmer8036 5 лет назад
Draw a displacement time graph and velocity time graph of a ball released at height of 8m and bounces on the group 3 times and each rising half the previous height
@damodarpadhy794
@damodarpadhy794 3 года назад
It will better ,if example for each graph were given
@MathematicsTutor
@MathematicsTutor 3 года назад
Check this playlist: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-3E4QIFGHijE.html Thanks
@10perkara
@10perkara 4 года назад
thank you... it's very fun learning... it also makes me understand more
@ayushagarwal016
@ayushagarwal016 5 лет назад
Awesome could have been more amazing if added a t graph in all cases , BTW Awesome.
@anilkumarsharma8901
@anilkumarsharma8901 11 месяцев назад
make calculator over it for more easy calculation and direction 😎😎😎😎
@jayantideshpande8459
@jayantideshpande8459 2 года назад
Sir in 2nd graph how the slope is positive?? The slope is going towards the origin.. So how the slope is positive??
@sreyaunni6155
@sreyaunni6155 6 лет назад
Excellent class sir...😊👌.Hope more from you...😊
@mastan7846
@mastan7846 4 года назад
It is better to explain how slope is positive
@irfankobber7097
@irfankobber7097 6 лет назад
best explaination by far! Can u do a vid on bouncing ball accelation time graph
@swarajsarangi3120
@swarajsarangi3120 5 лет назад
❤️❤️❤️❤️💯
@sallyko__2807
@sallyko__2807 3 года назад
May I ask the name of the black pen your using?? Thanks!!
@er.imransheikh
@er.imransheikh 3 года назад
HOW TO FIND SLOPE POSITIVE & NEGATIVE IN NATURE IN CASE OF LINE? pl explain
@ermiasestefanos4195
@ermiasestefanos4195 6 лет назад
I Like it, but isn't it "accelerating" , which is non-uniform/ not constant, if the line graph is Parabola?
@MathematicsTutor
@MathematicsTutor 6 лет назад
at 6:12, The slope of a curve is constant; Curve is Velocity; Slope of this line is the acceleration. y = mx + b, m is a constant. Hope now you can see that the acceleration is constant for the parabola representing displacement. Thanks
@nkitydv
@nkitydv 3 года назад
What is the difference between uniform and constant velocity please help me
@pritam1210
@pritam1210 3 года назад
@@nkitydv both are same 🙄
@hafsa9512
@hafsa9512 5 лет назад
no curve is formed in any v-t graph?
@hirunisiriwardhane4361
@hirunisiriwardhane4361 3 года назад
why not when the velocity increasement(accelaration) increases with time we could get curves in v-t graphs too
@__.nahaan.__2509
@__.nahaan.__2509 5 лет назад
Plz give example for each cases
@MathematicsTutor
@MathematicsTutor 5 лет назад
Sure, will post a video on that soon. Thanks
@vodanh652
@vodanh652 6 лет назад
well explained. thank you.
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks for appreciation and your time. Appreciate your name -- Eager to Learn, a true student!
@ajinkyakale3353
@ajinkyakale3353 6 лет назад
What would be the vt graph if acceleration is non uniform??
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks. Will post a video for that. Here is some concept which can help: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Ge4b8OM5ymY.html
@MathematicsTutor
@MathematicsTutor 6 лет назад
Here is an example for non-uniform acceleration: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-uhP293VovJU.html Let me know if that helps. Thanks
@xmariacelestex
@xmariacelestex 3 года назад
is a position and time graph the same as a distance and time graph?
@Madeeha_
@Madeeha_ 3 года назад
I might be late but yess
@dyanmofitnessandcalistheni1016
Thanku sir
@Gleza519
@Gleza519 Год назад
What pen was used
@ObeyAmmalol
@ObeyAmmalol 3 года назад
11:53
@MathematicsTutor
@MathematicsTutor 3 года назад
Let me know if all was clear. Thanks
@maabetikijodi1116
@maabetikijodi1116 3 года назад
Sir of this answer2. Draw a plot between displacement v/s time for the retardation motion
@Maria-ph6wb
@Maria-ph6wb 4 года назад
A special case where a body moving with constant velocity has constant acceleration. Is this true? My teacher said: It is true bcz acceleration=0 is also a constant quantity for acceleration and where a=0 velocity is constant But I don't get it....so plz explain...
@teresamariconda964
@teresamariconda964 4 года назад
Maria hi because acceleration is change in velocity so if the body maintains a constant velocity of 0 then acceleration is 0 as there's no change in velocity so that is still constantly 0
@zaheenkhan3770
@zaheenkhan3770 5 лет назад
Sir why the displacement and velocity time graph scatch are different from each other plz sir i have big confusion
@MathematicsTutor
@MathematicsTutor 5 лет назад
Velocity is rate of change of displacement. So they should be different. Hope that helps
@thethuglife10
@thethuglife10 3 года назад
@@MathematicsTutor amount of change in position is called displacement Velocity is rate of change in position
@deeptibarmandeka6254
@deeptibarmandeka6254 4 года назад
How many pens u have?😄😄best video 👍👍👍
@TaurusWhat
@TaurusWhat 6 лет назад
Great explanation!
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks a lot for appreciation! All the Best!
@roddamapm8401
@roddamapm8401 5 лет назад
Very good explanation
@frankcarey250
@frankcarey250 5 лет назад
Sir please clear my doubt. To get distance traveled we calculate the area under Velocity Time curve, which we usually do considering curve above X axis. But we could have compute the area under that curve with respect to Y axis. But why don't we do so? Please reply.
@MathematicsTutor
@MathematicsTutor 5 лет назад
We could do either way. Why we don't normally do - x is treated as an independent variable. Time is independent variable by default. Velocity is defined as rate of change of distance with respect to time -- so that explains. Hope it helps.
@kausarmalik9258
@kausarmalik9258 5 лет назад
@@MathematicsTutor sir you ate amazing
@saiprasad5599
@saiprasad5599 3 года назад
Sir the last vt graph is not correct I think sooo
@MathematicsTutor
@MathematicsTutor 3 года назад
It is correct. Please check again. Thanks
@skumar2664
@skumar2664 4 года назад
Online class hota hai sir
@MathematicsTutor
@MathematicsTutor 4 года назад
Yes, send e-mail for details
@anilkumarkumawat1693
@anilkumarkumawat1693 6 лет назад
What is meaning of -disp, and - velocity
@MathematicsTutor
@MathematicsTutor 6 лет назад
Thanks, will make a video on this soon. displacement is change in position velocity is rate of change of position.
@carultch
@carultch Год назад
Negative displacement means that the object is located in a direction from the starting point, that is opposite what we arbitrarily define as positive. Negative velocity means that the object is moving in a direction, that is opposite what we arbitrarily define as positive.
@YL-ii3vy
@YL-ii3vy 5 лет назад
hi,i have a question, for the fourth d-t graph,the object returned back to the original position twice(displacement=0m),but in the v-t graph,the velocity of the object is at zero when the d-t graph is in its minimum point(displacement is negative,but not zero),why is that so? And why the v-t graph was not drawn in a way that the the line touches the x-axis twice?(which means that velocity=0m/s)
@kakaliray4721
@kakaliray4721 5 лет назад
You have not at all understood the video..
@TheMarko7766
@TheMarko7766 3 года назад
some graphs are WRONG
@shabanaanjum6675
@shabanaanjum6675 5 лет назад
Nice explanation
@MathematicsTutor
@MathematicsTutor 5 лет назад
Thanks
@JeanCloueLBacho
@JeanCloueLBacho 3 года назад
Thank you so much, I really love the way you explain it, now I understand our lesson, Thank you☺
@harshapasagada8590
@harshapasagada8590 5 лет назад
Good sir
@5aleddss
@5aleddss 3 года назад
THANK YOU!
@vishalsinghjat1916
@vishalsinghjat1916 5 лет назад
Thanks sir
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