I beg to differ very respectfully, sir. From t = 0 to t = 10, the displacement time graph needs to be a curve with an increasing gradient as the body is accelerating. Then from t = 15 the graph should be a curve positive with a decreasing gradient as velocity is decreasing at a constant rate.
This is just hilarious. I'm a huge BTS fan too! I didn't expect to find you guys in a physics video lol. Also, thanks Anil Kumar for this video; it is super helpful for studying for my exam tomorrow.
Hello sir I have two question 1- How can I find v-t graph from a -s ? in other way if given to me a-s graph and ask me to find v-t graph how can I doing that ? 2- How can I find s-t graph from v -s ? in other way if given to me v-s graph and ask me to find s-t graph how can I doing that ?
Thanks. Distance: Area under the curve is distance as shown at the end of the video 3:45 min Another video - at the end of this video ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-3FWuBAWyIIg.html
Yes I know that but if velocity is uniformly increasing(uniform acceleration) like in the graph, then the displacement-time graph equivalent should have a curve not a straight line... If you have some.doubt in this you can check it also... Think about it.. if the displacement time graph you made is correct then shouldnt the part where the line is straight indicate uniform velocity not increasing velocity. That means your graph is wrong.
