Probability Super Trick | Dice Problems | NTSE | Mathematics | ATP STAR 

Always comment like this. You save my time

thank you dear @@HimanshukumarRai-kr4zy

Thanks bruh... ✨✨😂😂✨

Thanks bro❤ save my time

Thanks bro❤

Thank you so much bro😅

Lekin bhai isko subjective me kaise karega mountain banakar

Murkh baalak dice me 15 kabse ane lga

@@uresports Ullu ho kya when three dice will toss what will be the favorable chance to come out of the sum of 15

@@dmkindian3398 3 dice nhi aayega bhai sirf 2 dice

@@uresports Mere me three dice ka question Aya hai

@@dmkindian3398 bhai preboard me aya hoga board nhi ayega baki dekhlo uski bhi ek trick hai

I'm assuming that you mean 2 die are rolled. Solution:If the product of the appearing numbers is even, this means at least one of the appearing numbers is even Hence from the "sample space of two dice" (google it for reference) we get 27 favourable cases. Total number of outcomes is 36 Therefore the probability=27/36=3/4 Hope this helps 🙂