Projectile Motion - A Level Physics 

Very clear descriptions here that have really helped the students I teach. Thanks.

when i looked at this tutorial... the thought came to my mind was... "if i had such video 20 years back" learning would have been more easy and interesting.. i have always loved physics :) nice job..i hope kids of this generation make ample use of such great videos.

I haven't done these calculations in 20 years. My son is now in AP Physics and needed my help. This was exactly what I needed. It is very well done and I am truly grateful for the refresher.

Thanks. There is a full set of my A Level Physics Revision videos. I have put the link in the description above.

My Ib Physics test is comming up. All i can say is I love you for making this video

I absolutely love the way you teach- it's all very easy to understand because you explain each step in the working out of a solution. You earned yourself a subscriber! Keep it up!

Cameron Calder - Try ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-2vsAY-tp9js.html

For most questions on A-level physics projectile motion we make the assumption that there is no air drag or other forms of frictional resistance.

I'm less sure about that. I suspect I cover most of the material for any A level syllabus, but if there are particular areas of main physics (as opposed to biophysics) that you think are missing please let me know.

As level people where are you at 🌚

I love the simple, clear no fluff teaching style. It reminds me of how I was taught back and school and later in sixth form. Thank you for your vids.

I hope so. My videos cover the bulk of the syllabus of most of the A-level physics courses. But at present they only cover a small amount of the physics that would be taught at university. Thanks for your comments and good luck for the future.

This is my first quarter of physics (in college and never took in high school) and I was really struggling to understand or follow anything that was going on. In this 30 minutes video, you cleared so many things up for me, I can't thank you enough!!!

"And on that sad note, I hope that's been helpful." Haha, humorous and educative...thanks for the video!

You, my friend, are a life-saver! Thanks for creating and compiling all these videos together!! :)

I'm just starting out teaching AS Physics from GCSE, wow your videos are amazing! Clear, fully relevant and no nonsense. Thankyou and I look forward to watching more of your videos as I progress.

Yes. That is Newton's first law: a body continues in its state of rest or uniform motion unless acted on by an external force. So if no friction - and assuming the ground was flat - the ball would just continue to roll along the ground at uniform velocity since no forces would be acting in the horizontal direction.

29:10 RIP Harambe :'(

Many thanks. I'm delighted they have been of some help.

a powerful teacher....i always recommend my fellows to use this channel

I’m just starting on my engineering after a long years of gap, I find your videos very helpful. Thank you so much sir😊

so today i had a quiz in my AP physics class and i didnt know anything about the topic we were on because i was in the hospital for almost all of it and i watch this in the morning and i saw my grade after i took and i got a 14/16 and thats without the curved so thanks to you i got a good grade because of how well you explained this. so thank you so much for the taking the time to upload this video :)

Thank you so much! You've allowed me to understand in 10 minutes what I've been struggling with at College for a month.

Thanks for the kind comments. Stick with it. It's a great subject.

This is one of the best videos I've found on projectile motion. Great job and thanks.

This is an extremely helpful video! I'll surely go through this channel whenever I find difficulties in my A levels course. Thank you!

11 years later- still a legend.

For Jake Cosgrove: This would be for example if the trajectory were to go up and then over a cliff so the projectile ends up lower than it started. The equations still work as long as your signs are consistent. Up = positive and down = negative. So for example the net vertical distance change is negative.

Many thanks for your kind comments.

In the diagram I have, perhaps confusingly, called the initial velocity of the bullet from the gun - v. That can be resolved into its two component parts. Perhaps it would have been better if I had called the initial velocity u.

Thank you so much for these videos! I am a student at high school in the Czech Republic and I am taking leaving exam in a few days. Without you, I would be lost. I did nothing for last 4 years.. and now, I found my textbooks so uninteresting. Your videos don't give me just information, but also motivation to study. :)

A huge lifesaver, thank you so much for taking the time in making this video!

Thank you so much for this lecture, it is much appreciated. Projectile motion used to be my weak point for mechanics 1 in physics, but this video has helped me grasp it and now in mathematics mechanics 1 it's possibly my favorite topic!

Thank you for clarifying all of the formulas!!

Best physics teacher ever. You explain everything so clearly.

Can you tell me the time on the video where this arises please?

hi, I'm a junior in high school, and physics is my hardest class right now, for a number of reasons, but mainly because I don't have a very good teacher. Thank you so much for posting this video, it helped clear up a lot of my confusion in projectile motion. You've accomplished in 36 minutes what my insufferable physics teacher couldn't in three weeks.

I am a non physics specialist teaching A level physics for the first time this year. I'd be lost without your videos!!!! Thanks very much for such a great resource!

This guy is super good at explaining physics. HELPED ME A LOT. Thank you

Yes. I do not separate the two because the playlist attempts to cover material required for a number of different exam boards including AQA, OCR, Edexcel, CIE

You just earned yourself a new subscriber!

Got my exam tomorrow, this really helped to make me feel more confident

Thank you so much for helping me understand this! It really helps and the video is very thorough!

As others have said, in the SUVAT equations each one misses one of the 5 terms. Generally, the question you are asked to solve will enable you to determine which one to use. You will be given some variables and asked to find another. Find the SUVAT equations which covers that group.

I'm not sure which graph you are referring to but in general you identify the two variables one of which is dependent on the other.

Wow this has been helping people out for years. I remember my physics 1 course looking at this vid.

Thank you so much for this clear and easy to follow video. I'm taking the MCAT soon and my physics needs some refreshing.

My videos are intended to cover both AS and A2 courses in Edexcel, OCR and AQA.

Thanks, this kind of explanation is what I wanted to hear for a long time

the best youtube video you can ever find for projectory motion

There is a video on Geometric Optics - A Level Physics in the A Level Physics playlist.

This has got to be the best video for projectile motion! Thanks Sir

Thank you so much! Physics makes much more sense to me now.

Your explanation was clearly explained and included all the required details. Thanks very much.

Not sure which theta you want to calculate but if you know the vertical and horizontal components then vert/horiz = tan theta.

I am really thankful to you for giving lecture free of cost.It developed my concepts on projectile motion.Sir your lectures makes it an ideal foundation for those students who intend to take their studies to a more advanced level.Physics is my favourite subject.KEEP IT UP!

Thank you so much. I learned more from this 36 minutes than I did in 6 hours of physics class per week.

Not if you are talking about each being the same range (ie horizontal distance) from the source. The reason is that time taken is determined by the horizontal component of the velocity which doesn't change (since there is no horizontal force acts on it).

I would recommend this video to all my Physics classmates this clears up a lot of things, thank you very much :)

You are AMAZINNGG!! You have cleared all my doubts regarding Projectile Motion. My Physics teacher should watch your videos and learn how to teach. You are a life saver! Thank You so much! May God bless You! :)

Thank you so much for your videos, you explain it really well and everything is alot clearer now, thank you!

As the projectile describes the arc it has a horizontal and vertical component to its velocity. The horizontal component does not change. The vertical component gets smaller as the height above ground increases. So the tangent of the angle will decrease.

Amazing video. Thanks so much, you make it fun and interesting which I didn't think physics could be until I saw this video. You have restored my faith in this science subject.

Thanks for very kind words. Glad to have helped. Physics is fun.

I like your videos. Thankyou for sharing. Your generosity towards others is appreciated.

Thanks for your very kind words.

thanks you so much for this video :D it really helps that you sound a bit like sir bruce forsyth (in a good way) and so I now have your voice repeating this lesson in my head when I see one of these projectile questions, thanks again :D

Good question. I don't know. My guess would be that d might be confused with a differential eg acceleration = dv/dt.

Extremely Helpful

This was an amazing video, very well explained thanks a lot!

Ur video tutorials are the best..thanks dr physicsA

Just you tell me the time on the video where you got confused. I'll try to explain.

Very useful video!! Stuff I considered tricky is explained here step by step, helped me a lot, many thanks.

This is gold. Thank you!

ur r great sir i have been back of this chapter for a long time but nothing was going to mind but ur teaching helped me gain back intrest in physics

Do you mean when a projectile is moving over an inclined plane, so for example a ball is thrown into the air but lands on the slope with a particular angle to the horizontal?

The ads kept on saying, 6 year old math problems doesn't help. Well, for me 90% of the things i learnt was because of the old videos. ^^ THANK YOU MR.!

I don't follow any particular board's syllabus. I just try to cover the subjects which feature generally at A level in the hope that they may be of help for revision purposes.

the video is specifically clearand i understood the equations and the methods of it. i gradually thank you

Thank you soooooo much!!!!!! I finally get it now.....yassssss!!!!!!!! And I just subscribed too

you have explained the projectile motion to a very good depth and it has cleared all my the ambiguities that i had with this topic Sir thanks

best physics youtuber by far

You used v=u+at. I assume your vertical initial velocity is 7.07m/s. At the highest point v=0. So 0=7.07-9.8t. t=7.07/9.8 secs. So it takes 0.72 secs to get to its highest point.

Thank you soo much ! :) I understood more in 10 mins of this video than 2 hours in class. :)

My best compliment for the clarity of your tutorials. I've followed this video and it's everything crystal clear. You mentiioned that the distance is the same for all angle θ and (90 - θ). I stuggle to prove it mathmatically but I was unsuccessful. May you show me how to do so? Thank you very much, and thank you again for your video!!!

thank you very much! Love your videos

Thank you so much !!! you saved my life . Finally i understood it

Oh my goodness, what I can say is that they have not been of "some" help, but rather A LOT OF HELP! Thank you, thank you so much! I finally understand this topic! =D

Not sure which formula you are referring to but if all you have is an initial velocity (and not the angle) you cant really calculate anything.

You are fantastic. This is helping me pass my physics subject at Sydney university. Many thanks.

Thanks. There is some material in the video on Simple Harmonic Motion.

amazing videos on the topics in physics and i have learnt a lot but could you please make more

I don't follow a specific Board - but the A level videos on this channel are intended to cover broadly the topics in an A Level Physics syllabus (both AS and A2) in the UK.

5 years late, but this has helped me so much. THANK YOU SIR

This massively helped me tonnes, I'm resitting AS but I found your channel literally days before the exam! Gutted was an understatement. There's a question type bothering me at the moment with projectiles, where the horizontal range is extended by the height of the drop being longer on the second side of the parabola. If you or anyone else can help it would be immensely appreciated. There are 3 parts to the question, a) and b) I have covered, it's c) An Athlete is performing the long jump. Horizontal Velocity= 8 M/S Vertical Velocity= 2.8 M/S a) Show that the total time the athlete spends in air is around 0.6s (assuming his centre of gravity is at the same height as it was at take off) b) Calculate the horizontal distance jumped by the athlete. c) In reality, when the athlete lands his centre of gravity is 50cm lower than its position at take off, calculate the extra horizontal distance this allows the athlete to jump.

I have a video on vector addition, subtraction and multiplication which uses vector triangles to do addition and subtraction,

Thank you so much for these videos they are really helpful. i was wondering if there is any exam technique advice u could give. thanks

Well the same principles apply but are much more difficult to calculate. It depends on the motion of the ship. Basically the velocity of the projectile as measured on board the ship must be added to the velocity of the ship to get the position from the person observing from the shore.

dude u r awesome. I understood all... thanks to u.

Are you given the angle at which the body is projected? For example if the body were projected vertically up its momentum when projected = mv = 2x20. When it reaches ground again its momentum = mv = 2 x -20. So change in momentum = 40 - -40 = 80. That's not an option.