Тёмный
No video :(

Prove that if (x-a) is a factor of the function f(x), then f(a) is zero. 

Helen Maths Tutor
Подписаться 1,3 тыс.
Просмотров 623
50% 1

This video shows how to prove that if (x-a) is a factor of the function f(x), that is if (x-a) divides into f(x) exactly with no remainder, then the value of the function at point a, f(a) is zero. This is an example of algebraic proof.

Опубликовано:

 

25 авг 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 5   
@highdry6646
@highdry6646 Год назад
Remainder theorem that if a polynomial which maybe represented by f(x) has a factor of (x-k), then the remainder is f(k)=0. If a factor is (ax-b),then the remainder is f(b/a)=0.(as ax-b=0 ,x= b/a)
@helenmathstutor
@helenmathstutor Год назад
👍
@hefesan
@hefesan Год назад
Why must x be equal to a though?
@helenmathstutor
@helenmathstutor Год назад
Thank you for your question. We've let x=a because we are working out what f(a) is (and proving that it is 0)
@lythd
@lythd Год назад
it does not have to equal a (its a function so x can take any value) but u can still check the case where x does equal a
Далее
Year 1 / AS Maths - Sine Rule Proof
2:14
Zero divisors will change your view of arithmetic.
15:01
Cristiano ronaldo VS Tibo Inshape ! 😱😱
00:20
ПАВЕЛ ДУРОВ АРЕСТОВАН
1:45:21
Просмотров 111 тыс.
Fool-Proof Test for Primes - Numberphile
3:43
Просмотров 891 тыс.
Learn Functions - Understand In 7 Minutes
9:43
Просмотров 1,9 млн