RCD:- One way slab design / design of a one way RC slab. 

Thank you genius for viral your video on design of beam on youtube and solve my problem in some steps Allah give u to long life tnx

Expertise civil engineering here

Thanks for sharing such good information regarding reinforcement plan.

v good sir.bohat acha hain.

this video made me learn somrthing with lots of cheers....simply awsome

Mashallah sir g der zbr10. ao der simple teaching

Sir Thank you very much for making videos.

Awesome information

Nice Video! Keep it up. Btw, Im just gonna ask if designing reinforced concrete slab is the "same" as the designing of reinforced concrete beams? What I mean of the same is, Beams are like trial and error process related to it reinforcement ratio right? Is that the same with slabs???

Thank you sir! ❤️

Take my salam sir, Can you make a video of design one way slab with beams (50*80 hall)

Very good explanation! Thank you for posting it!

Thank You Sir, that is really useful.

Very nice. Great job.

GREAT SIR PROUD OF U.....

Dear Sir, Very good lecture thank lot for

Please make a video on design of two way slabs.

this video really helpful, but don't we need to check the required depth??

Thank you sir for this videos you know it's a very helpful especially when you have exam in the next day and being so lost. Nice work

well done

thank u sir its was very intresting lectre for me

thanks for these nice lesson.

Hi, Is there a maximum span for a one way slab, can I consider a 36f x12f a one way slab, and can I build a 9 feet high wall in top and along the span without beams under neath it? Thanks

thank you rora.... abad osa ... zra de rala khushala kro

JAZAKALLAH

Thank so much sir!!

Sir Can You Please explain that why you did not consider 10' when you was calculating volume for Dead Load. Please tell me Sir..

wow great explanation

For those who took out time making fun of his accent, get a life guys! Thanks SL Khan for this wonderful video. Just what I needed. One small suggestion, please refer to original codes and clauses from codes if possible rather than the book. That would make our lives easier and your slides more interesting. Thanks once again.

nice

Sir kindly upload a lecture on design of two way slab by aci codes

V nice

excillent

nice and good lecturers

I think i would have chosen the #3 bar for both main and temp for ease of manufacture and less chance of mistake.

thanx sulaiman khan

Thank you Sir.

sir if slab is 8feet*17feet where as supports are at 8feet span so can it be designed as one way with main rod at longer span

Simple & perfect presentation can you do two way slab?

How can she slab?

salam aleykum sir. Awe thanks for your videos information and about books H.Nilson.They're so useful. Can u explain pls when u calculate D.L how did u solve 150 ?

Execellent explanation and video. how do you make your images, or what program you use?

Hello, can you reference where you got the long formula to find the "required reinforced concert ratio" please.

can u pls tell me book name

Hello sir, Thank you for the video. I am using Australian/New Zealand stabdard for the design of slab, and it uses the same method as you have explained. Could you please explain what im supposed to do when cover is larger than half depth of slab. Here is the problem: The slab is 100mm thick and located near the coastal area. According to AS/NZS, the cover should be 55 mm. After calculation, I found that I needed to use D20mm steel bars. My question is, how will this reinforcement be located in the slab? is it even possible to put reinforcement in slab with such deep cover? Thank you

sir what is the #4 and #3 can u pls tell me dia of bars

design table available in is 456:2000

multiple span example required pl...one way slab

I like your straggle

Thank you brother

Question: Consider a slab with L/B=2. And you are to support it on 2 edges only. Where do you put those supports or beams? on L or B?

Thank you sir

thank you, thank you, thank you

Please brother tell me also the name of slab?? if slab supported on 4 sides and the length of slab greater thenL/2...

turn you notification on for more...

very nice video

very nice sir

Pls share the design of cantilever slab by ACI code. Your video is so helpful.

A reinforced concrete floor system consists of a 100 mm thick slab cast monolithically with beams having an effective span of 6 m and spaced 3 m centre to centre. The superimposed load on floor is 6 kN/m2. Design the beam using M 20 grade concrete and Fe 250 grade of stee (working stress method) ? Isko solution dikha do krke

Very well explained

thnqq sir. this is which country code book. ...

thanks, how can i calculate the size and number of reinforcement, require and provide reinf?

By your video, i got 93 number on RCC ,without using any code. My teacher also shocked , because they was gave me 21/50 number. ❤

Hi Sir, after watched and learnt this video, can i check with you a question? Q1) with referenced to your final design (as shown at time: 17:36) , the Main Steel is #4@9"C/C. This means the whole RC Slab (10ft long) estimated having 15 units of #4 Main Steel Bar with 9" spacing between each bar? My Calculation: Span length : 10ft x 12 = 120 inch Main Steel C/C Spacing = 9 inch Number of Main Steel Bar in 10ft Span Length = (120 inch / 9 inch) = 13.333 + 2 (Most Left & Most Right steel bars) = 15 units Main Steel Bar Please correct me if my calculation is wrong. Thanks

Can't you make a video for designing two way slab

Don't you need any rod in slab top? You are placing only in bottom layer.

Is it the same approach for calculating composite slab?

idont understand what means ksi and psf and how to conversation inches to meters

Also , why we design the slab for 1 feet breadth.

sir kindly use SI units like m, N. these will make ur video more student friendly

sir Hindi video post

waley cum aslam

nice video. can you also provide the same for a two way slab, supported on four sides and garage style with columns? how about waffle design? ( in the same imperial units) thanks in advance

please upload the video to calculate the unit weigth of equal angle iron.

"Sleb" :D

Thank you

What about the design of continuous one way slab ?

so temp bars are distribution bars ?

Very good lecture I have a request I am in my second year of civil engineering in London I have exam next week Can you tell me what are the basic things to learn for exam ? Thanks Deera manana wrora

Kindly upload two way slab in Feet inches System...There is no auch video on Whole RU-vid

Walekum Assalam.. Can u posted videos in Hindi or Urdu.

I m confuse (longer dimension / shorter dimension =2) then one way or two way ? What is it please clear Because mostly teacher considered two way slab when dimension ratio equal to 2 but u r considered one way slab

Two way slab ?????

How does it become 8 in the denominator of wL²/8?

What would be the benefit, if I choose to provide some re-bars 20 mm below the top of the slab?

What´s the software you use for make this video,please?

pls use meter and KN so that everyone can understand including me.

love u .lala

can u pls tell me book name sir

If you are designing a slab and a beam would you design the slab first and then the beam, and for dead load and live would be same from beam, let’s say you have slab of 16” and b 48 the building is a theater how would you find the dead load and live load

Taper beam cutting lenth in stiirup

hy man what about roof treatment in dead load like brick tiles , mud , plaster.? .u did'nt consider these things in dead load :)

but how to design dia of a bar.

Could you explain the one end continuous and both end continuous?

U SHOULD EXPLAIN IN INTERNATIONAL SYSTEM OF UNIT

Are you using eurocode 2 ??

سلام انجنير صاحب محترم ديره مننه ښايسته ويدوګاني مو کړى دى ،،مننه

Sir what should we do when we have to teach the deisgn of slab for international students. I am teacher for malaysian students but now i am confuse which textbook i should follow. I wanted to know alry from code book the tect books are same for every country or not sir please guide me

Sr where do you get 12 inches in slab?

DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTS FF SLAB DESIGN PANEL No : Input Data: Slab Dimensions Short Span = 10 ft Long Span = 20 ft Span Ratio = 10 / 20 = 0.5 Slab Thickness (reqd) = 2 x (10+20) x 12 / 180 = 4. in Slab Thickness (prvd) = 6. in in Edge Conditions Short Span Edge Condition = One Edge Continuous Long Span Edge Condition = One Edge Continuous Applied Loads Slab self wt = 75.00 psf Service Dead Load = 0.075 psf Service Live Load = 220 psf Material Strengths Concrete Strength = 4 ksi Steel Yield Strength = 60 ksi Design Moments Loads Total Ultimate DL =1.4(75 + 0.075) = 105.105 psf Total Ultimate LL =1.7(220) = 374 psf Total Ultimate Load =105.105 + 374 = 479.105 psf Short Span Moments Postive Short span Moments = 1/11 x 479.105 x 10^2 = 4.356 k-ft Negative Moment on Discontinuous Edge = 1/24 x 479.105 x 10^2 = 1.996 k-ft Negative Moment on Continuous Edge = 1/9 x 479.105 x 10^2 = 5.323 k-ft Long Span Moments Postive Long Span Moments = N.A. Negative Long Span Moments = N.A. DESIGN OF TWO-WAY SLAB BY ACI-COEFFICIENTS FF SLAB DESIGN PANEL No : Reinforcement Calculations Along Short Span Positive Steel Mu=4.36 k-ft ; b=12 in ; d=5.313 in ; fc'=4ksi ; fy= 60 ksi As+ = 0.85 x 4 / 60 x [1 - [1-2 x 12 x4.356/(0.9x0.85x4x12x5.313^2) ]^0.5 ] x 12 x 5.313 = 0.187 sq.in. Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As+ = 0.187 sq.in. (#3 @ 7 in ) Negative Steel Mu=2 k-ft ; b=12 in ; d=5.313 in ; fc'=4ksi ; fy= 60 ksi As- = 0.85 x 4 / 60 x [1 - [1-2 x 12 x1.996/(0.9x0.85x4x12x5.313^2) ]^0.5 ] x 12 x 5.313 = 0.084 sq.in. Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As- = 0.130 sq.in. (#3 @ 10 in ) Negative Steel Mu=5.32 k-ft ; b=12 in ; d=5.313 in ; fc'=4ksi ; fy= 60 ksi As- = 0.85 x 4 / 60 x [1 - [1-2 x 12 x5.323/(0.9x0.85x4x12x5.313^2) ]^0.5 ] x 12 x 5.313 = 0.230 sq.in. Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As- = 0.230 sq.in. (#3 @ 5.5 in ) Along Long Span Positive Steel Mu=0 k-ft ; b=12 in ; d=4.938 in ; fc'=4ksi ; fy= 60 ksi As+ = 0.85 x 4 / 60 x [1 - [1-2 x 12 x0/(0.9x0.85x4x12x4.938^2) ]^0.5 ] x 12 x 4.938 = 0.000 sq.in Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As+ = 0.130 sq.in. (#3 @ 10 in ) Negative Steel Mu=0 k-ft ; b=12 in ; d=5.313 in ; fc'=4ksi ; fy= 60 ksi As- = 0.85 x 4 / 60 x [1 - [1-2 x 12 x0/(0.9x0.85x4x12x5.313^2) ]^0.5 ] x 12 x 5.313 = 0.000 sq.in Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As- = 0.130 sq.in. (#3 @ 10 in ) Negative Steel Mu=0 k-ft ; b=12 in ; d=5.313 in ; fc'=4ksi ; fy= 60 ksi As- = 0.85 x 4 / 60 x [1 - [1-2 x 12 x0/(0.9x0.85x4x12x5.313^2) ]^0.5 ] x 12 x 5.313 = 0.000 sq.in Asmin = 0.0018 x 12 x 6 = 0.130 sq in use As- = 0.130 sq.in. (#3 @ 10 in ) Shear Check Total load on the panel = 10 x 20 x 479.105 = 95.8 kips Shear Capacity of the section fVc = 0.85 x 2 x ( 4000 )^½ x 12 x 5.25 / 1000 = 6.77 k/ft Shear along short side Vua = ( 0.06 x 95.8 ) / (2 x 10 ) = 0.28 k/ft