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Rotational and irrotational flow [Aerodynamics #7] 

Prof. Van Buren
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In this lecture, we discuss the concept of flow rotation, which is different from our normal point of view of looking at only the translation of a fluid element. The measure of flow rotation is vorticity, which we derive from scratch, and this is related to a useful tool called Circulation which we will use to estimate Lift later in the course. Then, we consider what happens if flow is Irrotational, meaning the vorticity is zero everywhere, and that lets us build a Potential Velocity (similar to the Stream Function from the last lecture).
Free downloadable notes (PDF with white background) can be found at my website: sites.udel.edu...

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6 сен 2024

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Комментарии : 29   
@tom_winguill
@tom_winguill 11 месяцев назад
"irrotationality implies viscosity" I have a doubt here. If the flow is irrotational, then vorticity is zero, meaning the gradients cancel each other or there are no gradients at all. In the case, where the gradients exist, but cancel each other as explained in 4:53, the viscous force need not be zero. Because the gradients exist. But the flow is irrotational because they cancel each other. So we cannot say irrotational flow always means inviscid flow, Isn't it?
@prof.vanburen
@prof.vanburen 8 месяцев назад
Hi and sorry for the late reply! The semester got a way from me. Not sure I fully understand the comment, a main statement in this video (towards the end, unless I'm missing something) does say that irrotational flow implies inviscid. I'd like to help, can you clarify?
@hesokaheso855
@hesokaheso855 2 года назад
Glad to find this series, been a great help. thank you!
@prof.vanburen
@prof.vanburen 2 года назад
happy to help!
@ajaykumar-ij9jx
@ajaykumar-ij9jx 2 года назад
i never had so clear understanding..........thanks thanks thanks a lot
@prof.vanburen
@prof.vanburen 2 года назад
Awesome!
@satyamtripathi2234
@satyamtripathi2234 2 года назад
Thank you sir , may God bless you 🙏
@prof.vanburen
@prof.vanburen 2 года назад
Thanks!
@bensonotiero9022
@bensonotiero9022 3 года назад
Thanks alot..your video is the best Simple and clear
@prof.vanburen
@prof.vanburen 3 года назад
Thank you!!
@hectorbrizuelavega9214
@hectorbrizuelavega9214 Год назад
Brother you are the GOAT thank you
@prof.vanburen
@prof.vanburen Год назад
Thanks!!
@brajessingh184
@brajessingh184 8 месяцев назад
Badi maar marenge tumko, Tu hai kon re
@blantonvego4016
@blantonvego4016 3 года назад
Good evening professor. I don't know if you intend on making more videos or not, but if you wouldn't mind to use either a smaller pen diameter or slightly more penmanship it would make differentiating some of your variables a bit easier. Love the lectures.
@prof.vanburen
@prof.vanburen 3 года назад
Thanks! Definitely will try and be more careful in the future, unfortunately my handwriting has always been terrible.
@razorx6472
@razorx6472 2 года назад
Hi Professor, first of all, thank you for all these series, its definitely best on youtube 2- Can you please make video with solving questions about the topics that discussed, that will be awesome, thanks a lot again
@prof.vanburen
@prof.vanburen 2 года назад
Definitely something to consider moving forward, thanks!!
@arashjitsingh5828
@arashjitsingh5828 3 года назад
Thanks, Sir, cleared my concepts
@prof.vanburen
@prof.vanburen 3 года назад
Thanks, glad to help!
@islamseifformechanicalengi8957
Great explanation. Thanks
@prof.vanburen
@prof.vanburen Год назад
Glad you liked it!
@crosshama1
@crosshama1 Год назад
Hi professor Thanks for your series videos 🙂 18:41 I'm confused. If it needs to add minus to grad stream function for v velocity at y direction?
@prof.vanburen
@prof.vanburen Год назад
Hello! I'm afraid I don't follow the question, could you perhaps reword it?
@RahulKumar-bx7my
@RahulKumar-bx7my 2 года назад
sir I have a doubt why is the angular velocity the average of both the rate of change of angles ?
@prof.vanburen
@prof.vanburen 2 года назад
Hey Rahul, this one is tough to explain through a comment. Maybe it's helpful to think about the extremes. In the case where both angles are the same, that indicates rigid body rotation and the angular velocity of the element is the same as the sides. If the angle change is equal and opposite, the particle deforms and doesn't rotate (the average is zero). Not sure if I helped or made it worse!
@prashantbisht3786
@prashantbisht3786 3 года назад
Amazing 👍👍
@prof.vanburen
@prof.vanburen 3 года назад
Thanks!!
@furkandugeroglu7187
@furkandugeroglu7187 2 года назад
Hi, in 11:53, average angular velocity should be written in (1/3)*(.......) , doesn't it?
@prof.vanburen
@prof.vanburen 2 года назад
Hi! In this case, I don't think so. What we're doing is taking the average angular velocity of each component, where the definition of a mean is (1/n)*sum(x_1:n). So, you will notice shortly before 11:53, omega_z = 0.5*(angular velocity_1 + angular velocity_2). At 11:53, we've just put all three components together and then pulled the 1/2 out front.
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