Should have solved orally. Area of Square - Area of Circle = Half the Area of White Part. Now Double the Area of White part and subtract from Area of Square = Area of Shaded Part [16 - 2*(16 - 4π)] x^2 = 8(π-2) x^2
Deaw 2 diagonal line and divide each side by 2, then shaded area will divide into 8 equal parts. In small square with s=2x, each shaded part has region is A = 1/4 circle - isoscales triangle with s = 2x A= (1/4 x π x r^2) - (1/2 x s x s) A= (1/4 * π * (2x)^2) -(1/2 * 2x " 2x) A = πx^2 - 2x^2 = (π-2)x^2 Then all shaded area is 8A = (8π-16)x^2 = 9.132x^2
I'm sorry, I'm a bit lost here. Why didn't you take 1/8th of the diagram, apply the area of sector formula A = ½ R^2 (Θ - sin(Θ)) A= ½ (2x)^2 (π/2 - 1) A= x^2 (π - 2) Then multiply by 8 A= 8 x^2 (π - 2) Are you TRYING to make it look harder?
No. I'm not trying to make it look harder. But your approach is correct. I could use the area of sector formula and get the answer in in less steps.. But I'm hoping to get into trigonometry in my future videos so until that I wanted to use an alternative method. Thank you for sharing the method ❤. It helps for everyone.
@kimba You are talking about area of segment and not area of sector Please try to be accurate when you are writing a public comment It can confuse people Good intuitive solution in the video
