Тёмный

Scale Invariant Feature Transform 1 (Feature Detectors) 

Pratik Jain
Подписаться 6 тыс.
Просмотров 22 тыс.
50% 1

Опубликовано:

 

27 окт 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 31   
@supreetkurdekar5726
@supreetkurdekar5726 4 года назад
Hey buddy. You have a really nice explanation style and it comes from the fact that you have a very in depth understanding of the subject matter. This was my first time learning SIFT and I understood it completely. Good job. If you continue to post technical content like this, ill definitely subscribe. Hope your interest in computer vision stays the same!
@pratikian
@pratikian 4 года назад
Thank you so much for the feedback. Yes I will keep uploading videos .. 😊✌
@deeps-n5y
@deeps-n5y 10 месяцев назад
you are gifted man! this was so much fun :)
@michelpohl1019
@michelpohl1019 Год назад
I don't understand why we do scale space extrema detection and not just space extrema detection. In a previous slide, you show a 1D example with convolution with the laplacian of Gaussian, but there are not several values of sigma in that slide...
@pratikian
@pratikian Год назад
If you see the slide titled (Coming to the point) you can see that the concept works only when the size of the blob is similar to that of the sigma value of the laplacian. Hence its important to serach within a range of different sigma values
@piyushkumar-wg8cv
@piyushkumar-wg8cv Год назад
Is there any implementation available for this from scratch i.e. without using the library?
@arpitaingermany
@arpitaingermany 2 года назад
Loved the way you explained it. Thanks a lot. I have one question. In scale-space extrema detection, do we need to always compare the middle pixel of the second(intermediate image)? I don't understand that part.
@pratikian
@pratikian 2 года назад
Thank you for your feedback. 😇 To answer your question, it's not necessarily the second image it can be any image from the second image to second last image. Basically the pixels should have 26 neighbours in total. 9 above 9 below and 8 in the same plane.
@shunnoysarkar6906
@shunnoysarkar6906 2 года назад
Wow quite lucidly explained! At 28:05 how does the transpose of the inverse multiplied with the original matrix become identity matrix? Inverse multiplied with the matrix itself gives an identity right? Anyway thanks for the video!
@pratikian
@pratikian 2 года назад
Thanks for the feedback. Since Hessian matrices are symettric tye transpose of inverse is equal to the inverse matrix.
@jayasimhayenumaladoddi1602
@jayasimhayenumaladoddi1602 2 года назад
Can you please make a video on OLPP?
@silverlordboy
@silverlordboy 4 года назад
Very well described and shown, the best!
@cskarthik9909
@cskarthik9909 3 года назад
Awesome explanation
@anupambanerjee5222
@anupambanerjee5222 3 года назад
Great explanation Sir.
@ximingwen2542
@ximingwen2542 2 года назад
why this is a derivative of guassin?
@pratikian
@pratikian 2 года назад
I did not understand your question. Is your question why is the laplacian of gaussian a derivative of gaussian ?
@iampossibledude
@iampossibledude Год назад
Gaussian simply blurs the image (or we can say cancels the white noise). Besides, derivate of gaussian determines the changes in pixel values/edges. Therefore, for detecting edges it's necessary to use the derivative of gaussian.
@ExploreElectronics
@ExploreElectronics 3 года назад
Very nice explanation
@ExploreElectronics
@ExploreElectronics 3 года назад
How to contact you. I need bit of clarification on SIFT
@ExploreElectronics
@ExploreElectronics 3 года назад
Can I use haris corner detector and then SIFT descriptor far face?
@sathblr
@sathblr 4 года назад
Thanks for the nice video. I have a doubt in the step 'scale-space extrema detection'. For an octave: (considering 5 different scales of images created using Gaussian blur), we would be having 4 resulting DoG images from the previous step. So it's understandable to compare pixels from the 2nd DoG image with its neighbors from the 1st and the 3rd DoG images. Similarly, we could compare pixels from the 3rd DoG image with the 2nd and the 4th images. But how about the pixels in 1st and the 4th (topmost in that octave)? With whom should those be compared? Or we just consider only those in the middle (2nd and 3rd from the four DoG images from the previous step!!)
@pratikian
@pratikian 4 года назад
We only consider those that are in middle . For more better understanding you can see the description i have put a link of visual interaction and explanation of algorithm please check that.
@renjithnano5425
@renjithnano5425 3 года назад
Great work man
@Capt.Cooking
@Capt.Cooking 4 года назад
Thank you man for this video. It's really helpful
@Capt.Cooking
@Capt.Cooking 3 года назад
@Kaleb Omar nice try guys you are so believable omg..
@yashikabarike72
@yashikabarike72 3 года назад
excellent explanation!! Thankyou
@bijjalanaganithin3798
@bijjalanaganithin3798 4 года назад
Thank You so much very well explained
@jpssasadara3624
@jpssasadara3624 4 года назад
very nice explanation thanks sir..
@haiderabbasi145
@haiderabbasi145 4 года назад
impressive man , thumbs up
@toohinabarua4182
@toohinabarua4182 4 года назад
WOW
@jevenrichard4251
@jevenrichard4251 4 года назад
讲的挺好的,就是印度口音听着有点别扭
Далее
Lecture 05 - Scale-invariant Feature Transform (SIFT)
1:11:59
Corner Detection | Edge Detection
14:58
Просмотров 84 тыс.
SIFT (scale-invariant feature transform)
23:40
Просмотров 12 тыс.
SIFT Detector | SIFT Detector
9:32
Просмотров 80 тыс.
Edge Detection Using Laplacian | Edge Detection
12:39
What are Genetic Algorithms?
12:13
Просмотров 51 тыс.
SIFT - 5 Minutes with Cyrill
5:12
Просмотров 74 тыс.
SHA: Secure Hashing Algorithm - Computerphile
10:21
Просмотров 1,2 млн
Fourier Transform | Image Processing II
16:32
Просмотров 95 тыс.