Solving 3×3 magic square 

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23 is the middle number in the given series, do 23 will go in the middlemost square. Place smallest number i.e. 19 just above 23. And place 20 at the right most bottom corner. Magic number will be 23×3=69 You will be able to solve now

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Pankaj

When you are given a series of numbers Always put the middle number in the middlemost square Here 13 is the middle most number. Then start putting the smallest number above 13 That is place 9 above 13. Then place next number 10 at the rightmost bottom corner. Now 13×3=39 is the magic number And now you will be able to fill up the remaining numbers

Sum of the numbers in first row is 15, so central number k=15÷3=5 and sum of opposite numbers is 2×5=10...so 6+l=10, so l=4 and p+8=10, so =2

So p*=2

There are some more complicated algebraic ways of explaining that tactic, but if you multiply the middle number in a 3x3 magic square by 3 your answer will give you the sum for each row, column, and diagonal.

Also I like your name. Does it always tell the truth? ;)

@@goddess_of_fire287 most of the time yes and thanks for answering my question :)

@@aran2150 You are welcome!

Proceed as per my explanation.... You will get -6(negative 6) between 22 and 20, while 30 as middle number in top row

Same technique....find the magic constant,i.e the sum of the row....0.4+1.4+1.2= 3.0 So you get the central number 3.0÷3=1.0......so the sum of opposites is twice of central number ....this can be proved since 0.4 +0.6=2 0.4 1.4 1.2 1.8 1.0 0.2 0.8 0.6 1.6

Yes

Yes

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1 4 4 6 3 0 2 1 5 I find that the rules don't always make the problem correct.

Sorry 1 4 4 6 3 0 2 2 5

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