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Solving Olympiad Problem with Quadratic Mean | ISI Entrance 2024 Objective 6 | Math Olympiad Algebra 

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29 сен 2024

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Комментарии : 4   
@sujaychanda9567
@sujaychanda9567 4 месяца назад
If we join the bottom of the line depicting gm to the top of the line depicting am we get the quadratic mean which is actually the hypotenuse of a right angled triangle.
@arulbiswas1260
@arulbiswas1260 4 месяца назад
isnt it also called root mean square?
@Arkaraan.-ej1vk
@Arkaraan.-ej1vk 4 месяца назад
x_1 +x_2+...+x_n= 1 Now a solution when a exact x_i =1 and other x_j =0 : i != J So max value of x_i = 1 for all i=1(to) n So Max (√x1 +...+√x_n) = Max(√x1)+...+max(√x_n) =√(max x1)+...+√max(xn) =1+1....1( n Times ) =n
@DiyaDhanuka
@DiyaDhanuka 4 месяца назад
Great explanation... Understood the topic properly....😊
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