Statics: Lesson 69 - Moment of Inertia, Composite Shape Method

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2 окт 2024

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Комментарии : 82

@Dana__black 4 года назад

Thank you dad

@rockroll5422 2 года назад

THE FK is wrong with you?!

@AtrioxiClean 10 месяцев назад

LOL fancy seeing you here I’ve seen you on mma vids. Small world indeed

@gail7909 Месяц назад

These videos are quite informative and really helped me understand the topics. I passed my last test thanks to you!!

@chikanmao8326 3 года назад

Thanks for carrying me through.. glad i wont have to do this after today...you helped me cross the finish line

@GETurnt Год назад

I'm pretty sure you've had to do it multiple times till now, myself coming back to this video thrice a year lmao

@quinnrison9274 Год назад

Just want to mention the correct answer is 469.366 in^4. I say this because Jeff accidentally wrote down -36.63 in^4 despite saying -38.63in^4. Other than that amazing video thanks jeff

@anthonyconte8117 3 года назад

The moment of inertia for the cirlce in the second line should be 38.63 not 36.63. Dr.H says its 38.63 but writes down 36.63 the final answer should be 469.37 in ^4 if you round those totals to 2 decimals.

@samuelchuonyo7022 3 года назад

Another small problem is: he rotated the whole shape (and switched up b & h places)... But forgot to use the same "switch method" for the triangle.... The correct value for triangle alone is -124.5024m^4

@chrisperez4533 3 года назад

@@samuelchuonyo7022 No he did the triangle correctly.

@nickwhite5771 3 года назад

@@samuelchuonyo7022 The whole object is suppose to be rotated like this when solving for Iyy the triangle is treated the same as the rest.

@ld4677 10 месяцев назад

38.63…. Amazing how your mind can hear something different than you just read a loud to yourself…

@patrikengas6479 4 месяца назад

thank you, that deviation bugged me😄

@Oscar-gx2yf 3 года назад

You are the patron saint of statics thank you Jeff

@georgesadler7830 3 года назад

DR. Hanson ,thank you for another awesome lecture on the Moments of Inertia and the Composite shape method. These topics are a combination of Physics and Statics.

@tomm9966 3 года назад

This guy is freakin dope

@LANRIE-DEV21 7 месяцев назад

Kudos👍👍👍 to you, Mr Hanson.

@tylertorsiello8450 2 года назад

am i crazy or is the x value in the table for shape 3 6 not 7

@Cantgumbo2 2 года назад

he did correct. the triangle he used to subtract is not the one intersect with the circle but it is on the right upper corner that doesn't exist. Look carefully

@a_ditto5722 3 года назад

Hey jeff! Love the video, however i believe you have made a mistake near the end with the equation for the triangle. When completing your calculations you set up the formula for the rectangle so that you could swap base and height - you did this correctly when putting in the values to your formula. However, you did not swap the formula for the triangle yet you still switched the base and height values which i believe is incorrect? If I'm wrong please feel free to explain this to me as i'd love to know!

@eglencelialmanca5964 2 года назад

Hi mate there is no mistake.. the formula of the rectangle was firstly in the way that is used for Iyy but the formula for the triangle is other way around (Ixx).. for the circle it does not matter anyway(base = height).. in order to have them in the same way he changed the rect. Formula to Ixx too and he turned the whole shape 90 degree in his imagination and calculated the values accordingly.. i hope this helps

@MrAwesomePaul1 5 месяцев назад

how dare you question jeff

@keyboardkyubey 9 дней назад

@@eglencelialmanca5964 TY for explaining why the base and height were switched

@hannahrebeccaevelopez9704 3 года назад

Thank you so much Sir! May GOD BLESS YOU MORE 😇 💕 you're such a great teacher😊 If I were your child/student though I'm not I'm so very very proud of you😊😇

@judypak3886 2 года назад

bless up bless up!

@brandon.d 2 года назад

bless up ! Bless up!

@LouieOConnell-ih5ix 2 месяца назад

Amazing explanations Jeff! Very much appreciated.

@1972hattrick 2 года назад

good job

@tannerrosen3648 4 года назад

You’re the boss thank you

@SIASOUKHTEH 3 года назад

thank you. what about the moment of inertia at left edge?

@kentw3137 3 года назад

wow so amazing, thx

@terrancepage9163 Год назад

im confused on the last part. For the triangle equation, should the base be 3" and the height be 6" ? it seems Dr. Hanson had the opposite

@ropafadzochinzara7120 5 месяцев назад

I am wondering the same thing

@aquaflames5901 3 года назад

The Iy'=Iy+Ad^2 is the parallel axis theorem, right? For my professor, the Iy is on left and Iy' is on the right with the formula as Iy=Iy'+Adx^2. Which is right? Thanks so much for these videos! They're super easy to follow and comprehend. Thanks again!

@nathanjohnson9464 3 года назад

I believe the one on the left is correct.

@maths2bsquared172 3 года назад

if i may ask,which book is he using

@mukhunyimkay5126 3 года назад

why is the centroid axix of the triangle 1/3 not 1/2 of 3 ? n is it 1/3 of all triangles ? so confused .

@carultch Год назад

Because the mass isn't equally concentrated on both sides of the midpoint of the base. The centroid is therefore "weighted" closer to the altitude edge of the right triangle. Let the triangle be the area bounded by the x-axis and the equation: y = -h/b * x + h Each area element, has a width dx, and a height of y, and thus dA = y*dx The first moment of area (which I'll call mu) is integral r*dA. About the y-axis, r=x. Substitute in dA and get: mu = integral r*dA = mu = integral x*y*dx mu = integral x*(-h/b * x + h) dx, from x=0 to x = b Carry out the integral and get: mu = b^2*h/6 Divide mu by the area of the triangle, and get c, the distance from the y-axis to the centroid: c = mu/A c = b^2*h/6 / (1/2*b*h) c = b/3

@JulianJArens Год назад

Huge help!!!!

@gehadyasser1001 3 года назад

thnxxx so much ur a great teacher

@chiragno1368 2 года назад

Love from India 🇮🇳

@josuealvarez2525 2 года назад

It's Saturday Dec 11, 2021, 5:24pm, I've been working on the same statics problem for 2 hours. I don't know what's wrong. I come to youtube and I find you, Mr. Hanson. Thanks!! Just Thanks!

@BhupinderSingh-cf4rt 2 года назад

Haha same. My final is in 90 minutes and I was stuck understanding the moment of inertia too.

@joshuaagbenyegah6962 2 года назад

I would want to ask the difference between bh³/3 and bh³/12 for the moment of inertia about the x axis.

@carultch Год назад

b*h^3/3 is for the 2nd moment of area of a rectangular shape, about the edge that has length b. b*h^3/12 is for the 2nd moment of area of a rectangular shape, about its center, through an axis that is parallel to length b Through the parallel axis theorem, also known as Steiner's Theorem, you can show that b*h^3/3 is related to b*h^3/12: I_edge = I_center + A*d^2 I_edge = b*h^3/12 + b*h*(h/2)^2 I_edge = b*h^3/12 + b*h^3/4 I_edge = b*h^3/12 + 3*b*h^3/12 I_edge = b*h^3/3

@yebgarganera1842 10 месяцев назад

Ty sir Jeff

@ytniadachiii 3 года назад

is there a way i can have the same book? i really love this channel!

@thomasschenk1831 11 месяцев назад

You make this fun Jeff. You are my slime. Many thanks!

@zozotto2437 5 месяцев назад

Im confused as to why you calculated x bar when the question is about y

@richardle5110 2 года назад

Thank god I found this man before my exams god blesses

@claudiaromero2759 2 года назад

Great professor. I understood it completely !!!

@andrewbrown3733 3 года назад

Nice Lecture

@selinsipal8693 3 года назад

thanks sir

@aphelelentlukwana2 3 года назад

May i please ask which type of a textbook are you using sir(name, author and edition)?/ which book would you recommend that i must use to get more practice for this module?

@rawadhasan9111 2 года назад

Engineering Mechanics 14th ed by Hibbler

@jargalsaikhantengis8338 10 месяцев назад

loveya

@kevcopo Год назад

THE GOATTTTTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

@maths2bsquared172 3 года назад

professor if i may ask,which book were u using for this online series

@ukznukzn8015 3 года назад

@@britrossi4876 thanks man👍👍

@BODYBUILDERS_AGAINST_FEMINISM 2 года назад

Can you teach some of my other classes as well? I have to retake a geologic hydrology class next semester and could really use some help lmao. Thank you for all of your help though seriously, I will recommend you whenever possible to those in need.

@estifanosgirmafissaha6307 8 месяцев назад

we love you jefff

@CB-mh6dq Год назад

You are the reason im about to pass my final. A true God-send

@mahdicfc1730 2 года назад

why you are teaching so coooool???🙌🙌😍😍😍

@OneOneThree-wl7ml 2 года назад

Wow you really saved the day haha. This makes so much sense. You have a gift!

@ironforged2329 Год назад

Nice

@tolgayucel8138 4 месяца назад

Real G

@zahozil3140 2 года назад

guys i have a question.If the problem tell us that we have to calcutate the inertia about the x axis, we find the cetroids of each shape and in the paralel axis theorem we take d to be the distance betwen the cetroid of the shape and the x axis?if anyone can responde thank you becuase i am pretty confused.