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Theorems That Disappointed Mathematicians 

BriTheMathGuy
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18 апр 2024

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Комментарии : 225   
@BriTheMathGuy
@BriTheMathGuy Месяц назад
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . You’ll also get 20% off an annual premium subscription.
@CheckmateSurvivor
@CheckmateSurvivor 25 дней назад
The world is full of fake mathematical models. Just ask the politicians.
@dennismuller1141
@dennismuller1141 Месяц назад
The only theorem that came to my mind when I read the title was Gödel's incompleteness theorem. And now, after watching the video I also remember the problem of constructing a square and a circle with the same area
@roihemed5632
@roihemed5632 Месяц назад
Won't the areas be the same if the side of the square will be the square root of pi times the radius of the circle?
@gaopinghu7332
@gaopinghu7332 Месяц назад
​@@roihemed5632 that's true, however there is no way to construct a side that length with just a straightedge (a ruler with no numbers written on it) and a compass.
@dennismuller1141
@dennismuller1141 Месяц назад
@@roihemed5632 assuming you meant pi times the square of the radius: yes, the area would be the same but it is impossible to construct with the classic rules of geometry
@roihemed5632
@roihemed5632 Месяц назад
@@dennismuller1141 Ok I got what you meant thanks. But I think you're wrong about the length. if x is the side of the square and x² = πr² then x = r√π
@dennismuller1141
@dennismuller1141 Месяц назад
@@roihemed5632 Sorry for the confusion, I misread "square root of pi times the radius" as sqrt(pi * r) instead of sqrt(pi) * r, so I corrected it to sqrt(pi * r²)
@sensorer
@sensorer 29 дней назад
I'd like to see someone draw the Weierstrass function without lifting their pen
@matthew-m
@matthew-m 28 дней назад
right lool
@Fire_Axus
@Fire_Axus 24 дня назад
real
@SteveThePster
@SteveThePster 23 дня назад
Manufacturing a sufficiently thin/fine pen would be a challenge
@sensorer
@sensorer 23 дня назад
@@SteveThePster if epsilon is line thickness, I think that for any epsilon greater than zero, the thickness is not sufficient
@ccbgaming6994
@ccbgaming6994 19 дней назад
@sensorer My pen was manufactured in Surrealia
@fluffysheap
@fluffysheap 28 дней назад
Godel's second incompleteness theorem states that in any collection of disappointing theorems, there will always be a disappointing theorem that is not included
@josepherhardt164
@josepherhardt164 26 дней назад
You are EVIL. Upvoted ...
@kephalopod3054
@kephalopod3054 25 дней назад
This video has to be incomplete, otherwise it would be inconsistent.
@KT-dj4iy
@KT-dj4iy 24 дня назад
Well that's very disappointing.
@chirantanbiswas9330
@chirantanbiswas9330 15 дней назад
There is always a disappointment that you are not aware of. Disappointment never ends.
@yonaoisme
@yonaoisme 14 дней назад
that's not what goedel states.
@moskthinks9801
@moskthinks9801 Месяц назад
The real theorem that dissappointed me the most was the Halting Problem. Something about having undecideable problems in certain axiomatic systems, lacking computational knowledge, and not being able to compute the busy beavers (which, honestly without HP would be tremendous still) is just astounding to me
@Alexagrigorieff
@Alexagrigorieff 29 дней назад
The halting problem, just like its cousin - Goedel incompleteness theorem, prohibits self-referential logic.
@sebij6811
@sebij6811 25 дней назад
​@@AlexagrigorieffAnd Tarski's undefinability theorem.
@muskyoxes
@muskyoxes 22 дня назад
I still don't know how the halting problem manages to be so _practical._ All the proofs i've seen leave me with the feeling of "it's possible to construct some outlandish gigamess of a program that can't be analyzed to see if it stops." It seems like a completely separate and unexplained result that many such problems are simple to describe
@moskthinks9801
@moskthinks9801 22 дня назад
@muskyoxes a good intro video to watch is about "the boundary of computation" and busy beaver numbers, it's the main video that got me interested in the halting problem
@SiqueScarface
@SiqueScarface 8 дней назад
@@muskyoxesIt boils down to a simple contradiction like the set of all sets which do not include themselves. Or in practical terms: A sergeants is disappointed with the shaving attitude of his platoon. He thus commands one soldier to shave all soldiers in his platoon, who don't shave themselves, but only them.
@cmilkau
@cmilkau Месяц назад
5:40 NO! I usually let this slide but this is a maths channel. The nonexistence of a universal algorithm does NOT mean that there are unsolvable instances of the problem. There could be a (different) algorithm for *every* instance of the problem, there is just not a (single, universal) for *all* of them. There may even be a way to describe strategies for all possible cases, while there is just no systematic way to select a strategy that works, so you might continue trying forever.
@paradoxicallyexcellent5138
@paradoxicallyexcellent5138 Месяц назад
Abel Ruffini is kind of a blessing though. Mathematics telling mathematicians, "Guys, guys. What are you doing? Stop solving single variable polynomial equations with roots. You have better things to be doing."
@ndwind
@ndwind Месяц назад
Was expecting the Gödel theorems on this list
@fragileomniscience7647
@fragileomniscience7647 26 дней назад
Would be too easy. Also, it doesn't have to be all too bad. It implies that mathematics has no end, since independent axioms are bound to just pop up. Would be pretty boring if you could do all the math using one rote algorithm.
@allozovsky
@allozovsky Месяц назад
2:00 But Pythagoras would probably be glad to know that the square root of two has a periodic continued fraction *√2 = [1; 2, 2, 2, ...].*
@douglasstrother6584
@douglasstrother6584 Месяц назад
I'd bet he would get a kick out of that.
@JJean64
@JJean64 14 дней назад
Wait until he learns about transcendental numbers
@douglasstrother6584
@douglasstrother6584 14 дней назад
@@JJean64 "Pythagoras, check these out!"
@allozovsky
@allozovsky 14 дней назад
Hm, but did Pythagoras even know anything about the number π? 🤔
@yanntal954
@yanntal954 Месяц назад
3:44 I think Minkowskis question mark function denoted ?(x) Is weirder than this function. It is continues and always increasing (strongly monotonic) yet its derivative is 0 almost everywhere! You'd think such a function with derivative 0 a.e. would at least be constant a.e. but nope. This function is never constant and always increases!
@ibozz9187
@ibozz9187 Месяц назад
Regarding Arrow’s theorem, there are non-ranked systems that satisfy these criteria. Approval Voting (pick as many or as few as you like with no upper limit) and Score Voting (Score every candidate, greatest sum of scores wins) both satisfy these conditions.
@ariaden
@ariaden 29 дней назад
en.wikipedia.org/wiki/Duggan%E2%80%93Schwartz_theorem
@abrarjahin8848
@abrarjahin8848 Месяц назад
Maths is beautiful
@jb76489
@jb76489 Месяц назад
*math ftfy
@devooko
@devooko Месяц назад
meth is more beautiful
@Bodyknock
@Bodyknock Месяц назад
Heh, although ironically this particular video is about instances where math refuses to be beautiful. 😄
@iteo7349
@iteo7349 26 дней назад
The Weierstrass function has a feature which is probably even more striking to non-mathematicians: it's a continuous function, which is not monotone (increasing, decreasing, or constant) on any interval, no matter how small. Seems impossible at first glance. Also, I was anything but disappointed that quintic equations aren't solvable. People need to grow out of this "solving" mindset. To solve something only means to write it in some other way that you find simpler. Guess what, some things just can't be written in simple ways according to narrow minded definitions of simple. Conclusion: expand your horizon and move on.
@glennjohnson4919
@glennjohnson4919 Месяц назад
What an interesting presentation. Loved it.
@douglasstrother6584
@douglasstrother6584 Месяц назад
This Theorem is so boring that we're calling it a Lemma.
@aryandegr859
@aryandegr859 Месяц назад
No Gödel incompleteness theorems?
@josepherhardt164
@josepherhardt164 Месяц назад
And wasn't there a theorem that showed that you couldn't prove that the infinity of the continuum was equal to Aleph-1?
@antoine2571
@antoine2571 26 дней назад
​@@josepherhardt164what you're looking for is continuum hypothesis
@SelvesteDovregubben
@SelvesteDovregubben 12 дней назад
​@@antoine2571CH is the statement that the cardinality of the continuum equals aleph_1. The fact that CH is independent from ZFC should probably be called the Gödel-Cohen theorem, but that name doesn't seem to have caught on.
@SelvesteDovregubben
@SelvesteDovregubben 12 дней назад
Why would one of the greatest theorems (and one of the greatest corollaries) in all of mathematics feature on a list of the most disappointing ones?
@miguelluisalvesdecarvalho1245
@miguelluisalvesdecarvalho1245 11 дней назад
@SelvesteDovregubben I think it's because this theorem proves that there are theorems in mathematics that cannot be proven by other theorems. I'm a little disappointed, because there are truths that can't be proven, but it's better than mathematics being inconsistent. i think that theorems would be the real axioms, and all others mathematic theorem can be proven by this real axioms, but i don't know this is just a thought.
@luccasguth
@luccasguth 27 дней назад
Continuity 👏 does 👏 not 👏 mean 👏 that 👏 a 👏 function 👏can 👏 be 👏drawn 👏withouth 👏lifting 👏 your 👏 pen
@justtimo8638
@justtimo8638 26 дней назад
for 👏🏻 real-valued 👏🏻 functions 👏🏻 in 👏🏻 one 👏🏻 dimension 👏🏻 it 👏🏻 does
@B0bb217
@B0bb217 25 дней назад
​@@justtimo8638no
@lucacesarano3661
@lucacesarano3661 16 дней назад
No, it does not! 1/x is a continuous function. The function indeed is simply not defined in 0. Simply it can't be extended for X=0 to a continuous function, but itself is continuous.
@jorian_meeuse
@jorian_meeuse 15 дней назад
​@lucacesarano3661 1/x is not continuous in x=0. Continuity in x=a means that f(a) = lim_x->a (x). A function is considered continuous on an interval I if the function is continuous for all x in I. Since f(0) doesn't exist for f(x) = 1/x, and the limit when x goes to 0 doesn't even exist, certainly it's not continuous in x=0. Hence, f(x) is not continuous over R.
@lucacesarano3661
@lucacesarano3661 15 дней назад
@@jorian_meeuseThere is a logical misunderstanding in the definition. How would you evaluate the predicate "1=√-1"? True or false? The point is, it does make any sense to say it's true or false, since √-1 is even not defined. You say correctly that in X=0 the function is not defined. Exactly because of it, it does not even make sense to speak about continuity in X=0. That's because of the definition of continuity: "A function f with variable x is continuous at the real number c, if the limit of 𝑓(𝑥) as x tends to c, is equal to 𝑓(𝑐)." Well, if f(c) is not defined, simply the sentence "is equal to f(c)" can't be logically evaluated as true or false. Could you logically evaluate the sentence "1 is a yellow number"? If you say it's false, then it means that the sentence "1 is not a yellow number" is true for you, and the property "not to be yellow" is properly defined. But it is not. For this reason, one can't even say that 1/x is not continuous in x=0. But it is absolutely a continuous function, since it is continuous on every point of its domain(!).
@Alexagrigorieff
@Alexagrigorieff 29 дней назад
And then there are conjectures that are proven to be unprovable.
@zapazap
@zapazap 24 дня назад
All conjectures can be proven to be unprovable modulo some axiomatic system.
@33invasion
@33invasion 25 дней назад
Just a minor correction. IIA in Arrow’s impossibility theorem isn’t about whether alternatives (added or taken out of the menu of alternatives) affect binary preference relations at the aggregate level. It’s about whether changing the preference profile outside the binary comparison yields a different aggregate preference between the two.
@MathFromAlphaToOmega
@MathFromAlphaToOmega Месяц назад
There are actually some really interesting ways of solving quintic equations. One way is with power series, and the coefficients involve factorials related to multiples of 5. Klein also found a way to relate symmetries of the icosahedron to solving quintics.
@FishSticker
@FishSticker Месяц назад
Yeah but they don't always work
@MathFromAlphaToOmega
@MathFromAlphaToOmega Месяц назад
@@FishSticker What do you mean by that? The power series has a finite radius of convergence, but there are ways to get around that. As for the other method, I believe it always works, as long as the quintic is in the right form.
@FishSticker
@FishSticker Месяц назад
@@MathFromAlphaToOmega you won't get an exact answer
@FishSticker
@FishSticker Месяц назад
@@MathFromAlphaToOmega also you might not know if it exists or not
@Hadar1991
@Hadar1991 Месяц назад
Arrow's Impossibility Theorem states only that you cannot achieve global independence of irrelevant alternatives in raked voting. But there are raked voting methods that are locally independent of irrelevant alternatives. In rated voting you can have global independence of irrelevant alternatives. But what is more important global of irrelevant alternatives is often criticized as something you may not want to have in your election system. More interesting (and disappointing) is Gibbard-Satterthwaite theorem which states that there is no election system which isn't susceptible to tactical voting. 4:15 Smooth curve is differentiable everywhere by definition. Weierstrass function is continues, but not differentiable at any point. Weierstrass function is in C_{0} class of smoothness in all of this domain, which basically means that it is nowhere smooth. A smooth function is in C_{infinity} class of smoothness.
@drdca8263
@drdca8263 Месяц назад
*which isn’t susceptible to tactical voting
@Hadar1991
@Hadar1991 Месяц назад
@@drdca8263 Thank you, corrected ;)
@rebase
@rebase 26 дней назад
The Abel-Ruffini theorem states that polynomials of degree greater than 4 cannot be solved *using radicals*. A radical is a solution to the equation x^n = a, or in lay terms an n-th root. E.g. sqrt(2) is a solution of x^2 = 2 If we go beyond plain radicals, and add to our toolbox the so-called Bring radicals, which are the unique real solutions to equations of the form x^5 + x = -a, then the general quintic becomes solvable! So it isn't like quintic polynomials have this infinite complexity compared to lesser degree polynomials. Rather, quintics need a single additional function (the Bring radical function) to express their solutions. Of course, Bring radicals cannot be computed exactly, only approximated, but neither can sqrt(2). Nothing special about it.
@stevenfallinge7149
@stevenfallinge7149 Месяц назад
The weierstrass function ties into the idea of fractals (in fact, the function itself is an example of a fractal) and the idea that most things in nature are fractals, things that are not smooth or well-behaved.
@omp199
@omp199 Месяц назад
"Most"?
@josepherhardt164
@josepherhardt164 25 дней назад
"things that are not smooth or well-behaved." So, like my wife? ;)
@sweettoy3824
@sweettoy3824 29 дней назад
We're doing AI-generated thumbnails now too?
@DrCorndog1
@DrCorndog1 21 день назад
You seriously made this video without bringing up Godel.
@arekkrolak6320
@arekkrolak6320 16 дней назад
Technically speaking Pitagorean Theorem said nothing about segment length, Pythagoras was only concerned with area of constructed squares
@halchen1439
@halchen1439 7 дней назад
At least the upside of all these "there is no general solution/algorithm" theorems is that we can have secure cryptography
@LeoStaley
@LeoStaley 28 дней назад
I want more videos like this.
@saujanyapoudel8910
@saujanyapoudel8910 9 дней назад
Me, an engineering student: *Laughs in Newton Raphson Iteration*
@kaminoeugene
@kaminoeugene Месяц назад
"you can draw it without lifting your pen"...
@MichaelRothwell1
@MichaelRothwell1 29 дней назад
For those of us who can draw nowhere differentiable graphs...
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
If you have Parkinson's, you have an advantage over the rest of us in drawing it.
@theoneeggo4653
@theoneeggo4653 Месяц назад
This man needs more viewers
@wyqtor
@wyqtor 25 дней назад
Gödel: hold this beer, you're gonna need it!
@MarcoMate87
@MarcoMate87 27 дней назад
The solution proposed at 0:16 for the general cubic equation is wrong; it's, indeed, the solution of the depressed cubic y³ + py + q = 0, where y = x + b/(3a). Thus, the general solution you proposed needs a "-b/(3a)" in the second member to be correct.
@SiqueScarface
@SiqueScarface 8 дней назад
I also think that the solution to Hilbert's 1. Problem is quite disappointing.
@VictorRuiz-dc9ed
@VictorRuiz-dc9ed 2 дня назад
Isn't the last theorem a direct consequence of the quintic equation theorem?
@sidimed1956
@sidimed1956 Месяц назад
Can you tell us how to prepare for the IMO pls
@nathancc2526
@nathancc2526 Месяц назад
I would also love to know hope he sees this comment
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
It's probably changed, but back in the day having AM-GM was always a good ticket. So is having intuition. That's probably not changed.
@vikraal6974
@vikraal6974 День назад
Paulo Ruffini gave a algebraic proof but the proof was flawed as it was found later. Niels Henrik Abel proved it using groups.
@erroraftererror8329
@erroraftererror8329 Месяц назад
I think it's for the better that we don't know everything in mathematics and that not everything has a solution. A complete mathematical understanding would mean that we have no more reason to pursue the subject. How boring life would be!
@josepherhardt164
@josepherhardt164 Месяц назад
This is why I rejoice whenever physics gets "broken." :)
@hcm9999
@hcm9999 Месяц назад
It is impossible to be absolutely sure about anything.
@JonnyMath
@JonnyMath Месяц назад
Solution: "Just invent new algebra!" 😅🤣 Why not!!!😉😅
@parthpandey2030
@parthpandey2030 Месяц назад
Euler trying to prove i = sqrt(-1): Proof: he made it up
@JonnyMath
@JonnyMath Месяц назад
@@parthpandey2030 Also known as "by definition"😅🤣
@bimrebeats
@bimrebeats Месяц назад
you should, just don’t “break” the old algebra 😉
@JonnyMath
@JonnyMath Месяц назад
@@bimrebeats Yes this is what I'm saying!!!😅🤣
@columbus8myhw
@columbus8myhw 29 дней назад
Look up Bring radicals.
@scottleung9587
@scottleung9587 Месяц назад
Interesting!
@roykay4709
@roykay4709 14 дней назад
Technically, I would call these "conjectures".
@jonathan3372
@jonathan3372 27 дней назад
At 4:18, I recall that in analysis we usually define a smooth function as one that is infinitely continuously differentiable. Did you mean to say "a continuous curve should be differentiable almost everywhere"?
@nothingok8800
@nothingok8800 Месяц назад
True
@sabriath
@sabriath 18 дней назад
Arrow had it wrong anyway....that's a direct vote system and they all fail in some form, but if you were to change into an indirect vote, suddenly it solves actually quite easily. As an example, instead of voting for which person is the best candidate for position XYZ, considering that the majority of the population doesn't even pay attention to politics and are voting on mostly false assumptions......we should be voting on the policies we want to see enacted or retracted. The candidate who scores the most in comparison to their own beliefs of what should be done against the voters that cover that area, should be the winner to the vote itself. To protect the population from tyrannical measures, a simple minimum requirement of 66% vote for those policy changes are the only ones that can actually be commanded for change....everything else is void until next term to be re-evaluated. This would work for all positions, and noting "policy" as different scenarios based on the field of position XYZ (so president will most detail command of military operations, while laws will deal with legislative branch, and punishment the judicial, etc.)
@JakubS
@JakubS Месяц назад
that AI person in the thumbnail looks like Hugh Dennis
@omp199
@omp199 Месяц назад
I can't see the resemblance.
@BanHelsing
@BanHelsing Месяц назад
AI looking ahh thumbnail
@itsmxrk.9469
@itsmxrk.9469 Месяц назад
Not the AI thumbnail 😭
@ameya0308
@ameya0308 25 дней назад
What is 0+0+0+0+0.... ∞ equal to? Technically it should be 0. But when you treat this series as a Geometric Progression and apply the formula for sum of infinite terms of G.P., the result comes to be 1/(1-(0/0)). How is this possible?
@JJean64
@JJean64 14 дней назад
If you treat this series as 0⁰ + 0¹ + 0² + 0³ + 0⁴ + 0⁵ + ... , when apply the geometric series formula you get 1/(1 - 0) = 1/1 = 1. Which makes sense because 0⁰ is usually defined to be equal to 1, so the series becomes 1 + 0 + 0 + 0 + 0 + 0 + ... = 1.
@figmentincubator7980
@figmentincubator7980 8 дней назад
You can't use the infinite geometric series formula since it is only defined when the absolute value of the common ratio between terms is less than 1. In this case, one could make a decent argument that the common ratio is 1 since the number is not changing between terms, but of course since the first term is 0 you could call it any number you want, since 0*x=0 for all x. So, if you choose r where |r|>=1, use of the formula is just invalid, and if you use r where |r|
@figmentincubator7980
@figmentincubator7980 8 дней назад
@@JJean64 why arbitrarily start at 0^0? Why not begin at 0^-1, or 0^57, or whatever? Usually the first term (a) is considered ar^0, and following terms are ar, ar^2, ar^3 etc. You seem to be thinking of 0 as the common ratio, and rolling with that, we should get 0*0^0 + 0*0^1 + 0*0^2 etc. to give an overall sum of 0.
@JJean64
@JJean64 8 дней назад
@@figmentincubator7980 Why would 0 not be the common ratio?
@figmentincubator7980
@figmentincubator7980 8 дней назад
@@JJean64 My point is that it could be anything (read the comment above the one you replied to). Starting at 0, you can multiply by anything to get 0. e.g. the sequence 0,0,0,0,0,... can be achieved by multiplying the first term be 0 every time, or by 1 every time, or by 276.5 every time, or literally any number you want since any number * 0 is still 0.
@columbus8myhw
@columbus8myhw 29 дней назад
You should cite the Math Stack Exchange post "Theorems that Disappointed Mathematicians," assuming you based this on it
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
Wait, do you memorise all Maths Stack Exchange posts just in case?
@columbus8myhw
@columbus8myhw 7 дней назад
@@xinpingdonohoe3978No, I was one of the main contributors to that post.
@stevenwilson5556
@stevenwilson5556 25 дней назад
Hippasus, not Pythatorus discovered irrational numbers and for his discovery he was tossed into the sea to drown. A true "math martyr". The Pythagoreans did not like reality to intrude into their harmonious "rational bubble"
@josepherhardt164
@josepherhardt164 Месяц назад
Standard equation for the perimeter of an ellipse? That C is not = pi * f(a, b) is seriously disappointing.
@gabitheancient7664
@gabitheancient7664 Месяц назад
I don't think there's any legend about pythagoras discovering the irrationality of the square root of two, it's just that this is related, but there's other greek guy everyone says discovered this tho the pythagorean theorem is related, not only we know for a fact it was not discovered by pythagoras (we don't even know if he existed) but you don't need this theorem to know about the square root of two, it's a very easy fact to discover that the diagonal of a square is the side of another square with double its area
@crix_h3eadshotgg992
@crix_h3eadshotgg992 Месяц назад
I recall hearing a legend about some guy (with a name starting with “H”) proving that the square root of two being irrational, and subsequently being tied up with stone, put on a boat, and thrown into the sea. Not making this up.
@gabitheancient7664
@gabitheancient7664 Месяц назад
@@crix_h3eadshotgg992 ye and this was surely not pythagoras, and the legend says the pythagoreans threw him in the sea I strongly believe this didn't happen tho
@christopherellis2663
@christopherellis2663 15 дней назад
Nonetheless, preferential voting is truer than first past the post.
@TranquilSeaOfMath
@TranquilSeaOfMath Месяц назад
That's a great thumbnail!
@user-gh4lv2ub2j
@user-gh4lv2ub2j Месяц назад
Yes; it took all of 10s to solve that first polynomial.
@omp199
@omp199 Месяц назад
What's the solution, then?
@devenyelve4905
@devenyelve4905 15 дней назад
Can we solve this problem (2+x)^14.33i where i is imaginary
@allozovsky
@allozovsky 14 дней назад
But that's just a binomial with a complex exponent, isn't it? Simply use Newton's binomial theorem.
@allozovsky
@allozovsky 14 дней назад
But the definition of complex exponentiation is even simpler: *zʷ = exp(w·Ln(z)),* where *Ln(z) = ln(|z|) + 𝒊·arg(z) + 2𝒊πk, k ∈ ℤ* is a _multivalued_ complex logarithm, so eventually you get _infinitely_ many values (and may choose one of them on a whim).
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
That's not a problem. That's just an expression. What are we trying to do with it? Equate it to 5? Expand it as a power series?
@drmilkweed
@drmilkweed 11 дней назад
AI is art theft, you are telling every artist that sees this that you don't care about your work.
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
Correct.
@gogogooner
@gogogooner 2 дня назад
Funny that you choose a very solvable fifth-grade... Do your research.
@giorgioleoni3471
@giorgioleoni3471 20 дней назад
I would add the Banach-Tarski Theorem
@lazyman7769
@lazyman7769 16 дней назад
Continous everywhere means you can draw it without lifting your pen😂 mate get straight with your concepts
@user-jb8yv
@user-jb8yv 28 дней назад
please don’t use ai generated thumbnails
@zapazap
@zapazap 24 дня назад
Why?
@JoelRosenfeld
@JoelRosenfeld 22 дня назад
It got you to click, and it got me to click. The data is what is important here more than personal opinions. I think it’s a nice dramatic picture to generate a click.
@evanmagill9114
@evanmagill9114 21 день назад
@@JoelRosenfeld Any stance on this involves personal opinions to some degree. Here's some data for you: Of the comments currently present on this video 4% of them refer to the thumbnail as AI. Of those 6 comments, 1 is neutral and 5 are negative. I personally am a lot less likely to click on videos with thumbnails that are incoherent or particularly noticably AI-generated. Here's some data we don't have: How many more or less views would this video get with a human-made thumbnail that took 5 minutes to make? 3 hours to make? If an artist was paid $30 to make a thumbnail, might it result in additional revenue that would cover those $30? Will the channel's community be affected by the use of AI in thumbnails? Will the relationship with the video's sponsor be negatively impacted? I don't intend to cause you any offense, and I'm not here to try to make you feel one way or another about AI. I just wrote this comment because I know I've used naïve arguments to dismiss people, and I would rather be called out on it than not. Opinions matter, people's thoughts are worth consideration even (and especially) when they differ from your own.
@Nolys-bk4kd
@Nolys-bk4kd 17 дней назад
Why not? He does what he wants
@zapazap
@zapazap 17 дней назад
@@Nolys-bk4kd I asked 11 days ago mate. He's not gonna answer.
@amazingplayer4954
@amazingplayer4954 Месяц назад
Fun fact: the degree of polynomials which always have solutions goes up to 4, just like the number of dimensions, coincidence?
@Penrose707
@Penrose707 Месяц назад
This is true only in so far that polynomials up to degree four may have their roots solved by using a finite number of simple algebraic operations (re: summation, multiplication/division, and exponentiation/nth roots). Technically the roots of any polynomial in degree z (the "solutions") can be determined by solving a particular series of z nonlinear equations (hint: think about coefficients of algebraic polynomials as consisting as sums of combinations of those roots. Otherwise, evoke the complex domain). This is extremely difficult and so in practice we often rely on the use of approximations and perturbation methods instead
@user-gh4lv2ub2j
@user-gh4lv2ub2j Месяц назад
Fun fact: the above is wrong. All polynomials have solutions; you just ignore complex solutions. People using science as religion get facts wrong: coincidence?
@James2210
@James2210 Месяц назад
​@@user-gh4lv2ub2jx^2+1 😳
@ethanbottomley-mason8447
@ethanbottomley-mason8447 Месяц назад
Yes, this is entirely a coincidence. The reason why all polynomials of degree at most 4 can be explicitly solved in terms of radicals is because every group of order at most 24 is solvable. This is not the case in general. For instance S_5 is not solvable. This is why the roots of the polynomial x^5 + x + 1 cannot be expressed in terms of radicals. The real reason is Galois theory, not some spurious coincidence that the number 4 appears in two places.
@drdca8263
@drdca8263 Месяц назад
@@ethanbottomley-mason8447It seems very likely to be only a coincidence, but, I’m not sure that that description of why quintic not solvable, proves that it is. I suppose for that we might need a more precise definition of what it means for it to be a coincidence
@nathancc2526
@nathancc2526 Месяц назад
Can I get a heart pls been following for a long time gr8 vid btw
@osvaldo701
@osvaldo701 28 дней назад
If you are disappointed by any of those theorems, you are really not understanding them
@prostoopid
@prostoopid Месяц назад
W
@mkks4559
@mkks4559 26 дней назад
Please don't use AI-generated images.
@v8torque932
@v8torque932 Месяц назад
IM THE 1000TH VIEWER IM FAMOUS!
@reaperplays6072
@reaperplays6072 Месяц назад
25 seconds and no views bro fell off
@yuraje4k348
@yuraje4k348 Месяц назад
12hours and 4k views
@creativename.
@creativename. Месяц назад
15 hours and almost 5k views bro fell off
@DKAIN_404
@DKAIN_404 Месяц назад
19 hours and 6.4k views bro fell off
@Chaosz511
@Chaosz511 Месяц назад
The npc's are coming out again
@mechanicalmonkee6262
@mechanicalmonkee6262 Месяц назад
😐👎
@gaurang6186
@gaurang6186 Месяц назад
Please like this comment so that u can solve millenium prize problem
@Ostup_Burtik
@Ostup_Burtik Месяц назад
Dislike, because WE NEED VIDEO ABOUT WHAT IS i^^i!
@xinpingdonohoe3978
@xinpingdonohoe3978 7 дней назад
The ith tetration of i? Is that what you're asking? Quite a quandary. Unfortunately, there isn't an agreed upon meaning for tetration outside of natural numbers yet. We have the property a↑↑(n+1)=a^(a↑↑n), and hence a↑↑n=log_a(a↑↑(n+1)), but that doesn't so easily apply to more general cases. Powers are nice. (a^b)^c=a^bc is powerful. Find something like that for tetration, and we'll get somewhere.
@Maths_B
@Maths_B Месяц назад
Anyone does not known how I got this much likes
@AvinamGurung-nu3kl
@AvinamGurung-nu3kl Месяц назад
You ain't got any likes nigga 🤡
@riothememer2029
@riothememer2029 Месяц назад
Very Cool
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