Thermodynamics - Test 1 Problem 1 - Multifluid manometer 

This is hands-down the best video I have watched on manometer problems

Hey thanks for this video, it is very consistent and affective. It's better than other videos. The last video I watched had 100k+ views or something but had a contradiction within it which made it confusing. I wish I came across this video first hopefully you got more views, I appreciate the content thank you.

Wow, thank you so much! You have no idea how much of a life saver you are. I couldn't figure out why you sometimes minus and other times add pgh until I came across your video. You saved me hours of grief.

I have a test tomorrow and this is the exact question i have in my workbook but couldnt solve it. thank you man you came in clutch

Thank you for this well explained steps in solving pressure. You helped a lot. Keep it up, sir.

Thank you your lesson are much easier to understand, your slow talking makes easily process the information

Thank you!, I am so happy to find videos like this: completly clearly and don´t need to go around and around the problem to solve and to understand what to do. ^--^

Also thank you from NZ, I spent all day trying to get my head around this reading from a text book, fluid start to fluid end, end up=Pa(- )/end down=Pa(+) very helpful, I just could see it, can now thanks.

Thanks sir. very nice concept, from back to first. I was doing always first to last. back to first is easy to understand in some problem

Thanks a lot for the clear and precise explanation!!!

Thank you you are already a legend ❤️. Keep it up.

Thank you, I finally understand this topic!!!

Your students are lucky 😪. Thank you for the video!

I just checked out your thermo google file and its pretty good. hopefully you put some more for thermo 2 (ch 9 and up). I also dont know how this problem is thermo, this is more like fluid mechanics problems xD but cool thanks!

Thank you so so so much you made this SUPER EASY

Thanks bro helped me a lot

You're the best 👏🏾👏🏾

Thank you so much.. nicely explained

Thank you so much!

thank you so much

Can you please explain why you didn't subtract P(atm) from each term as you did for P2.

thank you so much

Alas' the saviour shows up making the fog of the minus and plus lift up.

thank you

Loved this! I was having a major struggle with this guy! By any chance, could you share the unit’s conversion sheet?

sir is it still correct if i got the same answer but it is negative? I started finding out the gage in point 1.

thanks bro!

Thank you

thank you sir

You are a god

Omg you 😍 amazing 👏

why is going up negative and going down positive? is there an explanation for this? great video btw!

I have the same exact equation in my lectures

Thanks brother

good day, i just want to ask if can we have a copy of the pdf conversion file of yours? thank you

sir can you me the link of the conversion pdf

Sir for my problem, at the end of the question they stated that the local atmospheric pressure to be 95.5 kPa. They still asked to determine the gage pressure though. So is this value just meant to throw the students off or am I to consider P2 as 95.5 kPa? Edit: This was a past assignment and just stumbled upon it while reviewing. I do not know if I actually got it right as I considered P2 as 95.5 kPa.

i have a question : to use or apply the rule that we all know that any point at the same horizontal plan has the same pressure ;; is the point has to be in the same material or liquid?? or it could be different???

but in our version it gave us the atm pressure value. do we need to take into account?

What book is this from sir?

My problem specified that P2=Patm so Im good. but what if it didnt specify or didnt put gauge pressure instead, it says "determine air pressure" instead of gauge pressure, would P2 = Patm ?

just before the test i came up to this, lucky me

bro i need this conversion sheet so bad pls give it to me + why gage = zero

Thanks for the explanation but may i know from which book you got this question?

Isn't P(gage) =P(abs) - P(atm)? Why p(atm)=0

hey give me unit conversion

Patm= 101Kpa

Wouldnt the water be 'down' too?

This is not Thermo dynamic , it's fluids mechanic !!

Can u add arabic translation 🙂

thank you

Thank you sir