I was wondering, when setting up the deck, do you put them in order of number and color? How is it the 10 and 5 come up? Couldnt it be just a random number, but you still know the color?
My intuition is telling me to suggest that you should set your camera to manual focus for the over-hand sequence shots, so that the camera isn’t changing focuses each time your hands move across the center of the screen
I like it . I like doing mostly Impromptu cards tricks, however If I didn't I would snatch this one up. Great job ty for the tutorial. I am subscribing . =)
I know a trick much like this one, where the entire deck is stacked. If I am just doing card tricks for a small group of friends or something, I have another trick I like to do beforehand where a section of the deck is shuffled face-up into the rest of the deck. The great thing about this is that when I gather up all the cards I can stack the entire deck, right in front of them, even if they are paying attention, and it just looks like I am getting all the cards to be facing the same way again. Never had anyone call me on it yet. So, if I want to do the trick with the stacked deck, I do the other trick first (which is impromptu), gather up the whole deck and stack it right in front of them, and go right into my stacked deck trick.
I don't know card tricks, and I definitely can't "fan shuffle" or interlace them like you did. So, it seems the trick requires that the spectator know how to shuffle in the manner you show, right? (Google says it is riffle shuffle. I would likely ruin the pattern).
Easy to explain: if you didn’t shuffle the cards and you split them in 2 x 10 cards piles, one pile would be all black and the other all red. Now that you have shuffled them, each “inconsistency” means that the two cards have replaced each other.
@@ctakitimu haha - don’t feel dumb! I work in IT so doing logic stuff is literally my daily job! I’m not good at figuring out HOW a magic trick works (like Penn and Teller), but when I get an explanation on how to do it, I’m good at figuring out the logic behind :)
@@olefrederiksen9916 Oh that's a cool skill set. Have ever you watched people like Chris Ramsey do epic level puzzle boxes? Or even had a go at some of the sequential ones yourself? It's insane the engineering that goes into some of those
Can someone help me? Can you please tell me where I put the mind reading kicker card at the end, because I put the ace of spades and ace of hearts at the top and bottom of the deck at the start but they didn’t end up as the bottom card at the end for the mind reading kicker. Please can you help ASAP. Thank youuuu
Great trick, but every time I practice it, I make a pretty accurate cut, then count out one stack to reverse the order and put the 5S on top, leaving the 10H on top of the other stack, then a riffle puts one or the other top cards on top, then when I deal out 10 cards each into 2 piles, the cards get clumped back together in large groups of red and large groups of black. Like 3-6 in a row of the same color. I want them to look more random. What am I doing wrong?
Yes, count out the bottom half of the cut and force the bottom card to the top, ensuring the 10H or the 5S will be the first card dealt to the piles of 10, and becomes your final card.
5:08 order of colour is 1,1,3,2,3. Remember the sequence and set cards aside.... then count the cards upside down and reveil them in colour piles after 😊
Cool trick, thanks. Btw, in the one shuffle, they might turn the 10H to the 2nd in the deck (and it will go to the magician's deck) so you'll need to notice and take a pick at the new top card if that happens.
This is the BIG problem with the trick; The SHUFFLE. If the Ten of Hearts does NOT end up on top you lose the ending surprise. The magician can't control the shuffle.
@@mosheshpinel3108 If you count the cut from the bottom half, you force the 5H to the top of the bottom half of the cut, while the 10H remains on top of the top half of the cut. No matter how they riffle, one or the other will be at the top of the combined deck, and that's your final card in the trick. The other card will be in the top 10 so you can eliminate it from your guess. Plus the last card in your flared out pile of 10 will be red if the 5S is the final card in their pile, and the last card in your flared out pile will be black if the 10H is the final card in their pile.
@@mosheshpinel3108 That isn't a problem at all. The last card in their pile has to be either the 10 of hearts or the 5 of spades. It is impossible for it to be any other card. If you see the 5 of spades anywhere in your pile of 10, you know their final card is the10 of hearts. If you see the 10 of hearts anywhere in your stack, you know their final card is the 5 of spades.
Great tutorial - thank you. But please disable your auto-focus setting next time so it doesn’t keep trying to focus on your hands that are coming in and out of your shot.
@@Houjixful It's explained in the video: the card on top will either be the ten of hearts or the five of spades. You see which one is visible so you know the hidden one is the other.
@@vnen how would you know what deck to force if you don't know what pile has the ten? both stacks are face down when you force the pile and video didnt explain that. My only guess is to look at how the spectator shuffles and see if he shuffles the 10 to the top
Hey, quick question: Why must I Magician's Choice the pile? As they are opposite, whichever I have to find, I can do it by peeking at the other. And I can also find the last card in the same way. Thanks! Cool trick.
Because that pile will definitely have one or both of your known cards, which you need for the final reveal. Depending on how the shuffle goes you may have one of your known cards (5S 10H) in each pile, or both in the magician's choice pile but they will never both be in the other pile. Try it a few times and you'll see. I suggest turning those two cards face up to make it easier to follow.
Why should you force audience to choose the one pile, if its just the opposite and 10H vs 5S, then you can just work with any of the pile? Just curious.. Thank
Why force the pile to the spectator? It works with any pile they pick, does not it? (if you don't want to get the last card I mean, but it is without force whatsoever)
Is this a similar trick as in a video called "Shuffling Card Trick" on the "Numberphile" channel? They were trying to explain the mathematical reason why the trick works but I only understood maybe 30%-40% of video.
I think counting the cards face up throws it because looking at it from a spectator i can clearly see they alt red black which your telling how the trick is done right there.
Actually, you don't need to do a magician's force for the 10 packs if the cards are "opposite". That's a needless complexity. In fact, it works better if the spectator has a completely free choice between 10 packs.
Great trick. However, the way it’s done the spectator would notice the red black pattern when counting how many cards were cut. It works exactly the same if the deck was cut and counted with the deck face down
You can count it facing down. The first part of the trick is misdirection. Pretending that you’re testing the spectator’s intuition cutting the deck in exactly half. In reality, you’re just setting up the real trick. So it doesn’t matter whether you count the cards facing down.
The Gilbreath Principle works a follows: You have two stacks of cards, one that goes R-B-R-B-...-R-B and one that goes B-R-B-R-...-B-R-B-R. They are shuffled together, meaning a new stack is created and 52 times, the bottom-most card of either stack becomes the new top-most card of the new stack. The first card has a choice of being either B (left stack) or R (right stack). Whichever we choose, the second card can only be the opposite, no matter what stack it comes from. Adding this second card necessarily makes it so for the third card, we have a choice again. The fourth card will be the opposite of the third. It's now easy to see how, in the new combined stack, every other card is precisely the opposite color of the card below it.
I have 2 questions. What happens if the first cut gives an odd number of cards? And why do you need to force the 10 cards packet as both packets should be the exact opposite of the other?
The key is that you want the number of cards selected to be less than either of the halves in the 'intuition' cut. Most people will do a reasonable job of getting within a card or two of half, so by choosing 10 (20 total), you have some margin relative to 26. But in the event the cut is way lopsided, you could still make it work by using half of the smaller size (if it was 19, you'd use 9 cards in each pile instead of 10, for example...for a total of 18 - must be less than or equal to the smaller pile).
@@vincentv.9729 ..the direct answer is, it doesn't matter if the first cut gives an odd number. The only thing that's important, is that the cut be larger than 19, and less than 33.
I was wondering too about if the intuition cut was odd. But thanks for explaining I get it now. Excellent illusion can't wait to practice it. Great video!!! TY
This is all super smart, great video! I see how it works but I don’t understand how even after a random shuffle the two packs of 10 end up being symmetrical in color???
Why do you need to force the pile? Could they not just pic your pile and you can read off the opposites with the pile containing the 10 of hearts, that way you'll predict their 5 of spades?
Suppose the 10 of hearts is on top after the shuffle as happens in the demonstration. The second card from the top does not need to be the 5 of spades. (It is not in the demonstration.). If you don’t force and they pick the “wrong” pile, the bottom card will be the second card from the top after the shuffle. However you don’t need to force. If they pick the “wrong” pile the bottom card of that pile will be one of the top two or the bottom two from the start of the trick. So now you just need to memorize 4 cards ahead of time.
@@zyklos229 At the drawing of the final card all others are already exposed. The lying down card is the one that's missing. While it's impressive to look over them quickly, you don't even need a trick to figure that one out.
For unexplainable trick, you explained it relatively easily. If you split the deck in half you create two identical packs of alternating cards, due to the number being even in the deck. Both have the same alternating order. Now if you reverse the other pack, when you shuffle them you not only have an alternating order in both of the packs, but also alternating between the hands. So if you shuffle perfectly, they'll be in alternating order, but if you shuffle multiple from the same hand, they are also in an alternating order. As such when you deal them in pairs, they'll always keep the alternating order. When you see one person get multiple of the same color in a row, that's where your shuffling was imperfect, but due to the alternating order in both packs the pairs are still alternating.
Doesn’t need to be a perfect riffle shuffle. In fact it’s better if it’s not perfect. Just ask them to push the two piles together. Rosetta shuffle even 🤙🏽
I’m 25 , went to Vegas and re found my love for magic . That part when you taught us “magicians force “ was actually genius ! I never could of thought to manipulate the situation like that
I've had 8 Maker's and cokes and tried to follow along watching this. It seems VERY impressive, even if I have not been drinking... but alas, I've failed even the 1st prompt, as a drunken magician!!! What I've learned: don't drink and mage!!!
This relies on a very specific method of shuffling - what if the spectator decides to shuffle it a different method? One that will mess up the alternating order? In my mind, you still need an "inside spectator" for this trick - one who will always shuffle the deck using this very specific (albeit most common) method.
@@mmvalex6903 Yes! Even an inaccurate rifle shuffle will work. To make it NOT work, you'd have to allow more than ten cards from one side before even one card comes from the other side. Or is it five consecutively from one side?
Pretty obvious that the black-red mix results in even numbers and placement of cards. Any inconsistency in one hand will show up as the opposite in the other hand. You don't even need to force a hand because if you know one, you know the other, so it doesn't matter which one they pick.
3:46 You memorize both cards at the top (bottom of pile) which in this case it's the 5 of spades and the 10 of hearts. 10:26 The card that is face up to the right, which here is the 5 of spades, meaning he now knows that the last card is the 10 of hearts. =)
Very simple explanation. When you have cards perfectly set red/black and then you do one simple riffle, you're going to displace the two colors equally.
Hi! Amazing trick, and it works with just Math principles! I have one question: when you "guess" the last card ("its a 10 of hearths" for example), do you need to shuffle the deck in such a way that the 10 will be on top of it? What if the 10 gets more in the middle? I think thats the only confusing part for me. Thanks!
Either the 10 of hearts or the 5 of spades will be on top. You need to see which one is in the visible deck, then you know the one actually on top after the shuffle.
Pretty simple to explain actually. The only thing is it doesn't work if the audience member doesn't shuffle the top two cards correctly for guessing the number and the suit. You can only do the suit colors at that point.
A better way would be to peek the bottom card (Key card 1 or KC1) just before you start the trick and after the 1st cut take the packet that contains that KC1 and count it onr by one - all the cards being face down during this part Now for the trick to work for the very last card (still the KC1) the shuffle MUST be done so that tah KC1 syas et the top like Stephen did in both presentation and explaination :-) Its easy to realize that if the KC1 is in second place from the top for instance it won't be in the spactator's hand after making choose the 1st pile of 10 cards.
I count the pile with the 5S on the bottom face down, which puts it at the top. The 10H is on top of the other pile, ensuring that both will be on the top of the large piles before the riffle shuffle, and one of them will be the bottom card of one pile when I deal out 2 piles of 10. Much better presentation. Doesn't give away the pattern.
I would let the spectator turn over the cards at the end. In fact, I would let them block the cards with their hand so I can't see the cards, eliminating the possibility of a marked deck or sleight of hand.
Good trick, but from what I saw, the one part that can get dicey is the last card/10 of hearts reveal. I noticed the 5 of spades and 10 of hearts were the top cards of the two piles, then the spectator shuffled. The ending would need those two cards to remain on top, so a bad shuffle could easily have buried those 2 cards past the top 2 positions. I guess you can watch the shuffle and see if that's what happened and if it did, then you can eliminate the last card prediction...the rest of the trick is still very good. I'd be curious if this observation was wrong.
That's why you need to force one particular pile. Either the 10 of hearts or the 5 of spades will be on top after the shuffle. The other one will be visible in deck, it might not be the last card, but it does not matter because the spectator does not know about it.
I can explain it. It's not that difficult to explain. I'll give you a clue: when you arrange them red & black all the way through - that's an artificial pattern that never changes it just repeats red/back over & over. Then you do 1 cut & 1 shuffle. That's it. that puts the inverse of the new shuffled pattern with almost perfect reciprocal r/b r/b pattern except that has a slight chance of throwing this off but it's mitigated by the fact that you deal off the top 20 cards - which eliminates the differences at the bottom of the shuffle - making a perfect mirror image of the cards in the left & right hands. All you have to do is read the image on one side or the opposite on the other side. This is easy to discern. It took me much longer to type it out than the 30 seconds it took to realize how it works. I left out details but I told you more than I was going to. The details I'd add would further clarify things that are obvious to me but I've told 90 percent of the story.
Ignore all the dip shits that criticize the video and the card trick. These are people with no life that spend their days looking for videos to pick apart, which helps explain why they spend their Friday nights with a porno magazine and a pint of cheap whiskey. I for one enjoyed the card trick. With enough practice I may try to use it one day. I always enjoy learning something fun even if I am not coordinated enough to do it as well as you demonstrated. Thank you for sharing it with us
