Time Speed and Distance 3 | CAT Preparation 2024 | Arithmetic | Quantitative Aptitude

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CAT PREPARATION 2024 I QUANTITATIVE APTITUDE PREPARATION for CAT 2024
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CAT PREPARATION 2024
How to Prepare for Quantitative Aptitude
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10 апр 2019

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Комментарии : 182

@user-tu4xr8mf7d 10 месяцев назад

The more views he gets, the more I get scared that competition is getting tougher day by day lol

@monishmoolya8919 9 месяцев назад

😂😂

@shubhambhatt2704 3 месяца назад

True

@user-me9yy6wu2c 9 дней назад

Very true

@DevendraSingh-qn5qf 4 года назад

In girl question it is easy when we take ratio S1/S2=T2/T1 Let actual time = x min 4/6=(x-2)/(4+x) x=14min

@techtalkies4119 4 года назад

but how will you calculate usual distance..? from this

@user-ol2pu8bk9v 4 года назад

@@techtalkies4119 Distance = 4(14/60+4/60)

@new_life- 3 года назад

@@user-ol2pu8bk9v can u pls let me know why has it come as 4(14/60+4/60). I didn't understand?

@shubhamrn1885 3 года назад

@@new_life- usual time is found to be 14min. For speed of 4 kmph time is 18min(14+4). thus d = s x t. 4 is speed and (14/60 + 4/60) is time. and usual speed as explained by sir in method 2.

@zaskarcavity6959 3 года назад

4 is in terms of kmph (t+4 is in mins), if u convert 4 kmph into 1/15 kmpm... u will get answer 18....

@roshqsarrosh4225 4 года назад

The first method is more understandable for me personally. Thank you so much

@16psycheee 2 года назад

2nd one also

@Fastlane999 3 года назад

one simple method is comparing SxT for both cases as D is constant, let time be T 4 x (T+4)=6 x (T-2) we get T=14

@dhruvsharma9083 3 года назад

Hello , can someone solve one doubt. Why we cannot say that the difference of 12 mins which coming. It is due to thoae 15 km so train is actually covering 15km in 12 min so . Speed = 75kph?

@zaskarcavity6959 3 года назад

4 is in terms of kmph (t+4 is in mins), if u convert 4 kmph into 1/15 kmpm... u will get answer 18....

@maverick5431 11 месяцев назад

Best one👏

@shivankkapila2954 10 месяцев назад

Last question was just awesome. Discovered a new way to approach the question, Thanks a lot Sir!

@ShuvamNayak 4 года назад

Sir I don’t understand why are we calculating total distance 1st. In each of the methods we could go calculating req value directly.

@amishasahoo7376 7 месяцев назад

Thankyou so much sir ye video ka explanation bhut hi osm lga 🙏🙏

@user-ef5rx2ph5m 6 месяцев назад

just a guess, sir was recording the lecture in the morning around 10-11 am. inference from his taking example of 10 am to explain time difference😅😅

@RohitKumar-hn9dz 10 месяцев назад

In 1st questions solution by 2nd method (usual time taken by girl to reach the skool ) this portion is not understandable can someone explain this

@siddharthshankar6170 Год назад

Method one is more easier then other ones, really helpful thankyou sir.

@saniyanarula1674 3 месяца назад

But how get 14 min usual time through method 1 in first ques

@user-du3mb2sl1i 11 месяцев назад

if we do the first method how are we going to find speed at 4 kmph i.e 18kph?

@pareshswain6897 2 года назад

Sir what's the distance? In the last question

@aadityasinha Год назад

Thank you for this beautiful concept Sir!!!

@thefuddlefox9960 Год назад

Raju when going slower by 30 km/hr, reaches the destination late by 90 hours. If he goes faster by 20 km/hr from his original speed, he reaches early by 40 hours than the original time. Find the distance he covers. Any short trick for this question?

@garou1563 Год назад

Lets take speed as 'S' , time as 't' and distance as 'D' t=D/S [D/(S-30)] - [D/S] = (t+90) - t ------------------ eqn 1 [D/(S+20)] - [D/S] = (t-40) - t ------------------- eqn 2 (difference between time) Solve these above equations you will get speed then put speed in any two eqns you will get distance and then you can time also by (t = D/S) ans. Distance D= 3900 km , Speed S= 130 km/hr , Time t = 300 hrs verify it using this (S-30)(t+90) = (S+20)(t-40) I hope this helps....

@dishasingh7482 3 года назад

Thank you, sir.

@ShivamMishra-ht8bb 2 года назад

2nd one was very understandable for me personally. Thankyou so much sir. 🙂

@thepratiktalks Год назад

Bro how time taken is 18 mins

@chiragshetty6140 Год назад

@@thepratiktalks when time is reduced by 1/3 it takes 6 minutes less. 1/3= 6 minutes Total = 18 minutes (6*3)

@blogbubbleskincarebeauty Год назад

@@thepratiktalks time taken at 4km/hr is 18.. Usual time is 18-4= 14 min

@RohitKumar-hn9dz 10 месяцев назад

@@chiragshetty6140 1/3 how is equal to 3 ,can u plx explain that

@gurmeharsingh7718 10 месяцев назад

@@RohitKumar-hn9dz if 3 parts of the fraction 3/3 = 18, then 1 part of fraction 1/3=6, i hope you got that.

@rohitrohitrohit Месяц назад

i solved the first question really quickly but i doubted if it was correct, i really feel like ive gotten really better at quant thanks to you

@Shivam_General_Fitness Год назад

Thanku sir

@naveenkanamarlaputi9316 3 года назад

Sir. In second problem they are already mentioned by the speed of 3/4 of original speed to reach 15 km is 38 min late but we are calculate it as 36 mins to travel how sir

@zeleoz463 3 месяца назад

36 min is the time taken by train without any problem to cover that 15km

@manu-wd8bv Год назад

Can anyone explain me the last question

@abhisheks6458 10 месяцев назад

In Q1, LCM(Speeds) gives us distance units? Why can't it betime units? Anyone knows on what basis we are able to decide if its time/distance?

@90_yogeshmahour23 8 месяцев назад

i think we assume a distance which has to be an intiger if devided by speed thats why we take lCM of speed as a assumed distance hope it helps

@josephbj8766 10 месяцев назад

Confused with a question actually. If speed increases by 87.5% (7/8) then will the time decrease by 7/15 times? (as per n/n+d formula)

@NikhilKumar-2701 Месяц назад

yes

@unearthedcrux80 3 года назад

If in last question we were asked to find out the total distance , what would be the approach anyone ?

@anmolratan5217 2 года назад

Hi, You can just compare the distance after 85 km as if the train would have traveled at 25kmph then time would be t, but due to reduced speed, the train is getting 38 mins late. So apply the increase decrease ratio, then you will get the time required for distance after 85 km at 25kmph, so you can get the distance = 25 * time. I solved using 2nd case (38 mins extra and cross-checked the answer in case 1(50 mins extra), you can consider any of the cases. Here's the answer I got time taken after 85 km at 25kmph = 114 mins, So total distance = 85+95/2. You can cross-check in both cases. Hope it will help.

@kshitijbalonie4361 4 года назад

Thankyou sir

@krishnachauhan945 Год назад

thank you sir

@namanagarwal9177 Год назад

can someone explain why t=36 mins for the 15 kms in the train problem?

@soustab194 Год назад

1/3t = 12 Hence t = 36

@dhruvsharma9083 3 года назад

Hello , can someone solve one doubt. Why we cannot say that the difference of 12 mins which coming. It is due to thoae 15 km so train is actually covering 15km in 12 min so . Speed = 75kph?

@preshagandhi7320 3 года назад

M having the same doubt

@anshgupta242 3 года назад

Even I have same doubt

@chandansinghpatni 2 года назад

No this is all reference game, you cant determined with surety that with 3/4 speed it will travel 15 km in 12 minuted difference

@GHOST-xr7be Год назад

If the change in speed is already given as 3/4th then why are we taking 1/4th please someone explain

@jagmagjindagi8835 18 дней назад

Because it becomes 3/4 th of actual speed . Example you have 100 rs and if it becomes 3/4 of it then u have just 75 r left. So , 1- 3/4 Will give u 1/4th which means the speed comes down with 1/4

@navneetburagohain4333 10 месяцев назад

In the first question, only the distance was calculated by first method and not the rest of the required sub-questions. And the whole question was solved using the second method. Can i get the solution using the first method???

@vijaygarv 3 месяца назад

Yes, just divide 1.2 by 4 and you'll get 18 mins.

@vijayreddy2501 24 дня назад

Thank you sir 💯

@balreetsingh8474 4 года назад

Isn’t 25 kph the speed after reduction? At 23:52

@jaspreetsingh825 3 года назад

Exactly my thought too. 25 kph should be 3/4 of the original speed

@ArpitKharbandaIsAwesome 3 года назад

That is due to relative change. Here we are considering the change from second condition(original speed in 15km track) -> first condition (train broke down and speed is decreased), so we will get the original time as we specified in the first condition.

@meetpanchal4908 Год назад

In the last question : I have done speed = 15/(12/60) = sp = 75 which is is 3/4, SO,orignal speed is 100 km/hr .Can someone explain why Am i wrong ?

@asmidhyani2909 Год назад

12/60 hr is the time difference between the two scenarios and not the actual time taken in covering this 15km.

@arpankhan8485 4 года назад

Sir your teaching and explainations are awesome but plz make the audio a bit louder

@aadishjain7454 4 года назад

Hndfre lgakr dkh

@arpankhan8485 4 года назад

@@aadishjain7454 phir bhi sound quality achcha nhi ho rha tha.... ab to CAT ho gaya h mera

@aadishjain7454 4 года назад

@@arpankhan8485 acha🤣🤣kya rha score bhai?

@arpankhan8485 4 года назад

@@aadishjain7454 bass 78.92%ile....mere jaise idiot se itna hua yahi kaafi h...lol..😁

@aadishjain7454 4 года назад

Koi bat nh bhai zruri thdi har vykti hi ek kam me acha ho dsre kam bh hte h jeevn me cat jeevan thdi na h koi pura

@siddharthsuman3429 10 месяцев назад

Time taken at 4 km/h=18minute kaise hua nhi samaj aaya

@janmejaypanda5414 2 года назад

Sir how did you get the time take at 4km/hr =18

@arvind109singh Год назад

6*3=18

@utkarshbhardwaj2703 Год назад

I shall make u understand that The speeds are 4 and 6 respectively So the ratio is of Speed 1: speed 2 Is 4:6 Now time is inversely proportional So it would be 6:4 Now if you concentrate and understand the question , between the higher speed and lower speed the diff the girl is able to make is of 6 minutes So the in ratio 6:4 the 6-4= 2 Hence 2 parts make up 6 minutes Henc 6 parts of time while make 6*3 18 minutes Now distance is constant So multiply 4km/60min * 18 min You will get usual distance

@anxious_engineer 4 года назад

10:42 how does time taken at 4km/h become 18 minutes

@sidanshajahan9212 4 года назад

We're considering the speed changes from 4 to 6kmph... The time decreases by 1/3rd of the initial case(when speed is 4kmph) when speed becomes 6kmph,which is equal to 6 minutes. So 1/3rd of the time taken when she travels at 4kmph is 6 minutes. Therefore total time taken is 6*3=18 minutes

@paveldas6036 3 года назад

It's 4 mins late, i.e., 14min + 4min = 18min

@jithinkgeorge2237 3 года назад

@abdulkareem , Imagine total time taken @4km/hr ='x' .It is given that time difference is 6mins. As the time got reduced by 1/3, so 1/3*x=6. x=18(totsl time taken @4km/hr)

@thechannel3420 3 года назад

sir don't do so many methods we will learn everything half and get wrong answer.

@krishsureka8419 Год назад

U r fool than

@caster4824 Год назад

Only watch one then sir is trying to build concept

@pawanyuuvi5683 9 месяцев назад

@@caster4824yes

@tharuns1090 4 месяца назад

U should gain a overall perception of all methods which will help u solve different sums as per u convenience

@nikhilupadhyaya3622 4 года назад

please take the cat level questions in time speed and distance and time and work no video on time and work please make a video on that

@ShuvamNayak 4 года назад

NIKHIL SANJU there are 3 videos on time and work. Please have a look at arithmetic playlist

@raveenamishra7122 4 года назад

Very helpful!!

@pujaraj5908 5 месяцев назад

God's work 🙏

@markapuramkarthik8961 4 года назад

But if you take 2.5km/hr 6mins late and 3.5 km/hr 6 mins early can you explain in method 2 sir

@siddharthawasthi3649 3 года назад

Sir why we are calculating distance in the first question. Just the usual time has been asked

@urvashisomnani6602 3 года назад

Cause without calculating distance you can not calculate speed

@urvashisomnani6602 3 года назад

And usual speed of the girl is also asked

@classiccontext 2 года назад

Sir, please make a video for this : n/d =n/d+n.

@Rodha 2 года назад

Percentages lecture me hai

@MultiCommonwealth 3 года назад

since the distance to school from home is constant, let distance be D. let x be the time she normally takes. D = S X T Case 1: D = 4. (x+4) -- when she is late 4 mins Case 2: D = 6. (x - 2) -- when she is 2 mins early equate 1,2 cases for x. you will get x = 14 mins. Substitute value of x in either of the equation above, you will get D = 72 kms. you have D = 72 and t = 14 mins, S = 72/14 ==> 5 1/7 ans.

@hussainpunawala6113 3 года назад

Very easy technique . Pls can u tell from where else u r learning?

@MultiCommonwealth 3 года назад

@@hussainpunawala6113 self study.

@karthiksikka7350 9 месяцев назад

@@hussainpunawala6113it’s class 9 maths actually

@NareshKumar-ly7lp Месяц назад

14/60 krna chahiye tha km/h mein kr rhe ho na isley

@sidddwho 20 дней назад

If we are asked to calc. distance from school to home. Which answer to consider. Your ans is 72kms. and answer in video is 1.2 kms.

@jesugupta3827 Год назад

Sir how we can find the distance in between the station

@adityaprakash8656 4 года назад

21:50 sir ,how 36 has been calculated here

@ruthwikrao9603 3 года назад

same doubt

@dishabhati4061 3 года назад

12x3

@sonalibehera988 3 года назад

@@dishabhati4061 thanku 🥺

@sureshottrading1459 3 года назад

how to solve 15/(3/4)s-15/s?

@sheetaljain4288 3 года назад

take 1/s common in left side and solve left hand side part which comes 5 i.e. now you have 5/s = 1/5, now after cross multiplication it is s =25.

@anandkumargupta9071 3 года назад

❤❤❤❤

@BSbscphysics-yu4cr 3 года назад

easier eq for ques. 1 will be...=> (2x+8) = (3x-6)

@newuser1282 3 года назад

How?

@visuder7412 Год назад

@@newuser1282 direct apply s=dt

@veereshm4720 Год назад

@@visuder7412d= st😅😅😅

@AbhishekKumar-vw3mo 4 года назад

In train question you have taken speed s to 3/4s and then calculate everything If we do opposite means 3/4s to s ---> 1/4 increase in speed Then 1/5 decrease in time. Now this decrease time is 12 mins 1/5T = 12 mins = 60 mins = 1 hr 3/4 s = 15/1 ==> s =20km/hr I'm not able to understand why it is wrong. Anyone help me

@arunadityarajjain1129 3 года назад

12 mins = 60 mins? Wtf dude?

@AbhishekKumar-vw3mo 3 года назад

@@arunadityarajjain1129 1/5T = 12 T = 60 min (5*12) Calculation dude WTF you don't know this

@rishikeshverma9249 3 года назад

Bro , its 1/4 decrease , so time will increase by 1/3 . Therefore time taken to cover that 15km will be 3x12 =36 min.

@AbhishekKumar-vw3mo 3 года назад

@@rishikeshverma9249 that I understood....we are calculating every thing in terms of s What I have done is in terms of 3/4s 3/4 s to s -->1/4 increase in speed so So time will be decrease by 1/5

@siddharthyadav9625 3 года назад

@@AbhishekKumar-vw3mo from 3/4S to S the increase is not 1/4. ( By your ans - 1/4 inc in 3/4s would mean (1/4of 3/4 + 3/4) , Which will never come 1 ) Its a silly mistake people do . For Example - If from 1 to 1.5 there is a inc of 1/2 doesnt means the same in vice versa , that from 1.5 to 1 there would be a decrease of 1/2 , this can never happen. Hope i solved your problem.

@rashibhatnagar6772 4 года назад

Sir I wanted to know that after we have calculated the speed of the train which is 25km/hr, how will we calculate the total distance and total time taken for the same question?

@amalsurendran4746 3 года назад

It's not possible to calculate total distance or total time unless one more parameter that is.. Total dis or total time is given...

@newsanalysis4831 Год назад

ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TuSz8777COo.html

@vanshikasingh7278 3 месяца назад

Please guide me

@sunnyrathore8921 3 года назад

15/36/60=25KM/H ??????

@arunadityarajjain1129 3 года назад

15/(36/60) = (15*60)/36 = 25

@uncertain2135 4 года назад

Outstanding beauty content on utube.

@ak_47_47_ 3 года назад

Train's original speed should be 100km/hr.

@melodytunes2204 2 года назад

ho sakta hai passenger train ho

@bhumikasoneji6352 Год назад

10:51 in this question...time taken at 4km/h is 18 mins....how???

@bhumikasoneji6352 Год назад

Got my answer @ 17:03

@patelbhavesh90skid 2 месяца назад

Sir through ur video My speed for conceptual clarity is increasing at rate of 100%, study time has decreased 50% 😂❤❤

@MaxwellNaradd 11 месяцев назад

Cat 2023 prep anyone?

@priyanshiagarwal7827 10 месяцев назад

Yes

@Aaditya2k03 3 месяца назад

How much did you scored?

@Aaditya2k03 3 месяца назад

@@priyanshiagarwal7827what about you?

@virajparekh5566 Год назад

10:55 😅😂

@suhas08512 3 года назад

In 2nd qts.. we have to find original speed...from qts we understand that diff. of of 85km-70km= 15km & required time to travel 15km is diff. of time 50mins - 38mins= 12mins. its means train travels 15km in 12mins so..it should be as below S=D/T S=15/(12*60) S=(15*60)/12 S=75km/hr should be the ans. Rechecking Distance covered in 1hr - 15km/12mins=1.25km/hr....so 1.25km/hr x 60mins=75km. Ravi sir thank you very much. Thank you @Rodha

@dhruvsharma9083 3 года назад

I was having the same doubt. Any clarity ?

@dhruvsharma9083 3 года назад

Its wrong . I tried by equations. Sir is right

@Anonymous-er5iv 3 года назад

It's not 12 min time taken for 15 min is 36 min for 85 km ... 12 min is the difference between them

@chandansinghpatni 2 года назад

See we can't tell in 12 km it will reach 15 km because Speed Is changing right! That 12 minute is time difference you cant say that Tarin with 3/4 sped can travel the same distance in 12 mintue distance

@princeg.8834 2 года назад

⭐️⭐️⭐️⭐️⭐️⭐️⭐️

@riyatiwari714 4 года назад

Train wale ques mein 3/4 kse aaya? Smjh ni aaya

@rahulshrivastava8720 4 года назад

Read the question properly ....the speed of the train is becoming 3/4th of the original speed

@GHOST-xr7be Год назад

@@rahulshrivastava8720 fir uska 1/4th kaise hua fir 15km?

@Ssaurav6725 2 года назад

In girl questions we can even use equation where distance is equal which means 4(x+4)=6(x-2) x=14 minutes So here usual time is 14 minutes and we can do further from here.