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Titration of a weak acid with a strong base | Chemistry | Khan Academy

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Calculating the pH for titration of acetic acid with strong base NaOH before adding any base and at half-equivalence point. Created by Jay.
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Chemistry on Khan Academy: Did you know that everything is made out of chemicals? Chemistry is the study of matter: its composition, properties, and reactivity. This material roughly covers a first-year high school or college course, and a good understanding of algebra is helpful.
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Опубликовано:

22 авг 2024

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Комментарии : 65

@Michael-cm4nr 8 лет назад

WHY DONT THEY EVER JUST GIVE YOU Ka IN THE QUESTION. WHY DO THEY ALWAYS MAKE YOU GO LOOK IT UP. AHHHHHHHHHH I AM ENRAGED

@infernape716 8 лет назад

+Michael Buss I feel you bro

@dylannguyen4045 7 лет назад

Michael Buss EXACTLY

@sohoyankee66 7 лет назад

After you do them enough, you begin to just know them by heart.....until after the test that is then....they're gone again.

@christopherpanetta1243 7 лет назад

Just wanted to say thank you to Khan Academy, you guys are always really helpful when I don't understand something!

@alyannadarza4728 8 лет назад

thank you. but suggestion, you should increase the level volume of your voice. I can't hear you in my laptop =.= . good for for people with pc's

@Belldrop 8 лет назад

+Alyanna Darza buy new laptop bro, I'm okay with it

@alyannadarza4728 8 лет назад

you must be listening on a quiet area, i'm listening in a classroom

@alyannadarza4728 8 лет назад

and if you compare this from other videos, his' do has lower volume

@sohoyankee66 7 лет назад

Same here. Just use earphones.

@kirasmith461 6 лет назад

i have a question.... why did u do the ice table in part a using concentration (M) but in part b u used mol? how do u know when to use what?

@km-sc4kz 5 лет назад

I think as long as you're not adding any new reagent to the solution (and hence changing the volume) you can do your ice tables using concentration terms itself. That's why in part (a) he uses concentration terms for the ice tables, because we're currently not adding any NaOH to the solution. But in part (b), we've just added some NaOH, and the volume of the solution is constantly changing during the reaction and so I don't think using concentration terms will be helpful. You can see He does this in the next video also.

@daD3ATHBR1NG3R 7 лет назад

2:16 = How I look after studying all night for this exam.

@JB-gv7pt 5 лет назад

Normally I do very well in my AP Chem class but titration made me struggle a lot and it killed me. Thank you so much!

@jacky8128 6 лет назад

thank you khan academy, they explained it much better than my chemistry teacher. He is explaining it in the most difficult way possible. No wonder noone in my class rlly understand his lessons

@vsalukir7019 5 лет назад

I have a problem with what happens at 9:00. The hydroxide takes half of the acetic acid and turns it into acetate and water. But it seems to me that once that has happened you still need to do an equalibrium reaction between the remaining acetic acid and the remaining acetate.

@rebekahadrian487 3 года назад

In the first part we calculated the pH, as well as the amount of CH3COO- at equilibrium. But then in the second part we're saying that we start with 0mol CH3COO-???? I am so confused about this process.... we found that at equilibrium because it's a weak acid there's already a certain amount of CH3COO-. why does it go away for the start of the second part?

@driesvanranst3440 3 года назад

Yes, indeed. I think this is a mistake. The amount of CH3COO- should be taken into consideration as well imo!

@violetmcjunkin9036 6 лет назад

how do I know when to use molarity or moles in my table?? This video uses moles but a previous Khan Academy video I watched, seemingly about the same thing, used molarity/concentration.

@brayan9645 7 лет назад

There's an error in the calculation of OH-. You have excess OH- so because of this your acid is the limiting reagent and the OH- is the excess. Don't you have to subtract the acid from the OH- to get 0.0400 mol of OH- while the acid is neutralized completely. Or am I wrong?

@L33t0wner 8 лет назад

Thanks a lot! You're the real MVP

@2023Transformation 8 лет назад

All the Khan Organic videos are too low in volume.

@briang8663 7 лет назад

Best titration vids hands down

@agent475816 8 лет назад

You are supposed to check because you ignored the x in the denominator. Ignore the x, but check the answer by doing (x/0.2) x 100. If the answer is

@MartialXD 7 лет назад

You don't need to check when the Ka is 3 orders of magnitude larger than the concentration.

@agent475816 7 лет назад

Martial Really? I always was taught to always go back and check the "5% rule"

@djmussy18 7 лет назад

its good to check, nothing wrong it.. plus it literally takes 2 seconds once you fine the [H+]

@doughnutchocolatewithsprin4159 7 лет назад

Is there any way to know the end point of titration apart from based on the changes in indicator?

@djmussy18 7 лет назад

if you know the exact amount it takes to reach the endpoint, or if you have a pH reader, stick it in the solution, and slowly drop your solution, once you see a drastic change in pH, thats your endpoint.

@alzainab6538 7 лет назад

thanks a lot... it's really help me to finish my home work

@Amy-sz4gq 5 лет назад

So that people might practice, it might be good to include everything that is needed for the problem in the typed out version as if it is a test (i.e. the Ka...)

@charliewilson3234 8 лет назад

Great Video

@agent475816 8 лет назад

Is it really necessary to put 0.200? That's just a waste of space, just write 0.2.

@krishnanarayanan4653 8 лет назад

good practice to ALWAYS write in 3sf. In an exam you may get penalised for not writing numbers to 3sf. You need to be clear.

@krishnanarayanan4653 8 лет назад

0.2 could be 0.228584023 rounded, so writing 0.200 makes it clearer that it is exactly 0.2

@YinYangLogo 7 лет назад

I don't write 0.200 out when I'm doing my work... but nevertheless I probably should. Sig Figs aren't really much of an issue as the AP exam as well as my teacher go by +/- 1 on your answers so yeah... Sig Figs don't really matter. Outside of this I'm sure it would be an issue, but 2.74 isn't that much different than 2.7 in a highschool classroom setting.

@este4911 5 месяцев назад

im not sure if part B is correct. all of the acid gets used up.

@sivasankar7531 4 года назад

At 13.13 pH should be greater than 7 because salt dissociation generates NaOH which creates oh - ions ..

@socialistguerrilla773 7 лет назад

what if I had less than 0.005 moles of OH-? it would still be a 1-1 reaction and all of the OH would be gone and according to your reaction I would have the same A-/HA thus log would be again one , thus pKa=pH again? , I dont get why especially 0.005 moles of OH bring us to the half equivalence while even if we had less than that it would have been the exact same thing

@rassimsimou1594 3 месяца назад

Good

@charlesdale2600 7 лет назад

You save lives!

@natashamwamba3468 Год назад

Thank u😍

@bentoby2123 7 лет назад

What happens if the concentration isn't the same. Can you use the H-H equation then?

@ClumpypooCP 6 лет назад

Ben Toby yeah dude

@KoalaKrisp1 8 лет назад

Very helpful. Thanks!

@mdashiquzzaman4181 6 лет назад

CH3COOH(C-CA)=CH3COO-(CA)+H+(CA) HERE IF I M NT WRONG THEN THIS H+ IN (CA) AMOUNT GONNA BE REACTING WITH THE OH_ THAT IS COMING FROM THE FULL DISSOCIATION OF NAOH i.e the whole (ca) amount acetic acid is going to finish but here in this video there is no calculation for (ca) for acetic acid when it is reacting with NAOH

@isihummetli4671 7 лет назад

how about acids with 2 or more hydrogen(as H2SO4 , H3PO4 ). are their titration goes with this way as well ?, someone said me no, there is some differences..please someone explains. i have exam after 2 days

@nurlybektoktarov469 2 года назад

Lifehack: put it at the speed 1.5 and Khan Academy will speak like normal human 😄

@hudachanna4918 5 лет назад

Good video though

@ellenellen950 8 лет назад

How do we get the Ka (1.8x 10^-5)

@djmussy18 7 лет назад

you could get the Ka if you already knew the pH and the conc. but then again, this is a question about finding pH, so Ka is always given, or to trick you, they'd give you Kb, or pKa to see if you know the conversions...lol

@BOLYANA 3 месяца назад

اشكر امك على هالانتاج

@ondreiat6674 3 года назад

Where did he get the Ka 1.8x10(-5) from ??

@user-ri8ps6cl4w 3 года назад

it is one of those things that you should memorize or if your school is nice then they will give you a tabell with Ka and Kb of those common solutions

@ondreiat6674 3 года назад

@@user-ri8ps6cl4w Good to know..Thank you I thought I missed something in one of your steps.

@user-ri8ps6cl4w 3 года назад

@@ondreiat6674 you are welcome but i am not the guy in the video xD

@ondreiat6674 3 года назад

@@user-ri8ps6cl4w Thank you