Thank you, and your welcome. You may like this video also. MOSFET Push Pull Amplifier Visual Demo ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE--6N7l1dnk6s.html
Your tutorials seem to come at just the right time..five minutes ago I gave up on my amp circuit...couldn't get it right....this circuit looks way better than what I had...trying to get a 9.5 mm mic amped up to drive an 8 ohm speaker...
Best teacher on the net! Thanks for sharing this! I think this is the problems i have at my poweramps, I have looked and measured, But I dident think about this!
Ok I can see that the compensating diodes are required for a smooth transition. But WHY and how do they fix the problem? Best Wishes n Blessings. Keith
Here is a way to look at it. Note: that both the transistors have what look like diodes inside. Well in effect they act just like diodes as the transistors will not conduct until input voltage reaches at least 0.6/0.7 volts. That is why we get little kinks shown on scope. So adding in those two extra diodes means that they also will not conduct until the voltage rises across them to be 0.6/0.7. This means the input voltage is then always held just at this level of threshold voltage. Now since there are two transistors between + and ground you need two of those diodes to match the same voltage as the transistors. Hence you then get a smooth output.
I have once watched an audio circuit that uses magnetic type (center tapped trans) as push-pull's load. Static type has actually cross over as this video, courtesy of you.
Thank you. I have a video on compensating diodes. Crossover Biasing Compensating Diodes ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-v2mITbaCHUE.html
As long as the diodes are forward bias, either side or between the diodes will work. I think this video will answer your question. How can a DIODE pass an AUDIO SIGNAL UNDISTORTED ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ddfrkGkAvZY.html
thank you very much. One question/remark : When the top transistor is conducting more, the "resistance" of the bottom one is kind of increasing (as it is actually kind of "blocking"), this mean that the extra current that Top transistor generates is actually "directed" to the load as it cannot go down ? Is that correct ? Thx
Thanks for this video. I tried building this but my results were barely audible. The transistors used were not exactly matching. They were 230 and 240 respectively. When I built the schematic on breadboard I used my phone as a sound source and a mono 8ohm speaker as the listening device.The circuit barely produced any sound being driven by my phone with the volume maxed out. Also, I removed the 100k resistor before the output and tried replacing with a potentiometer. It did nothing at all. The sound through the circuit was the same with the resistor to ground, without the resistor, and also the same with the pot. It didn't make any difference. Do you have any idea what I'm doing wrong? Thanks for your time.
It does not matter if the input is between the diodes or on one side. These two videos should help you understand this circuit. How can a DIODE pass an AUDIO SIGNAL UNDISTORTED ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ddfrkGkAvZY.html Crossover Biasing Compensating Diodes ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-v2mITbaCHUE.html
Little to nothing. I think this video may help. How can a DIODE pass an AUDIO SIGNAL UNDISTORTED ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ddfrkGkAvZY.html
@4.32 ..can anyone pls explain me in that diagram....from which point we collected the output from that npn transistor ?is it not that we collect the out always from the collector ...be it npn or pnp?...pls guide...thank you
It does not matter if the input is between the diodes or on one side. These two videos should help you understand this circuit. How can a DIODE pass an AUDIO SIGNAL UNDISTORTED ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ddfrkGkAvZY.html Crossover Biasing Compensating Diodes ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-v2mITbaCHUE.html
@@Enigma758 I know it does not seem right, but that's what makes it so interesting. Those diodes compensates for the EB junctions of both transistors. Each are about 0.7VDC. The best way to understand this circuit is to build it and experiment. I did a video on Crossover Biasing Compensating Diodes, here's the link. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-v2mITbaCHUE.html
Hi! I have some questions. Audio source has a + and a -. It sends signal from + to -. It's push type? And at audio amplifiers it's the same. It pushes the speaker. Push pull it's when + and - switch to - and + signal and back? To push and pull the speaker?
This setup has two 12VDC supplies. They are connect together in series so if you measured from + to - you would read 24VDC. The ground is in the middle of the two power supplies. If you put a meter, the black lead on the ground and the other lead on +, it will read +12VDC. If you put the black lead on the ground and the other on -' the meter will read -12VDC.
@@AllAmericanFiveRadio I was writing about the output signal. On + it goes from 0 to + and back to 0 and to + and back to 0. Or it goes from 0 to + to 0 to - to 0? The speaker is just pushed or it's pulled too?
This video I used FreeHand 11, but I have recently started using CorelDraw Essentials. I also use PhotoshopElements and PremiereElements. This video is and example of CorelDraw. Triode Tube Amplification Visual Demo ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-4FkD0LRiu7A.html
Hi, I have a jukebox that uses a tube amp. For the life of me I can't get it to work. I am considering either sending it out for repair (EXPENSIVE) or replacing it with a mosfet amp. Just curious if you have an opinion of the pros and cons of doing this. Thanks, and as always love your vids.
Ohms Law. You start by working backwards. What is it that you going to drive with your amplifier? What is its impedance, this determines, in this amp, the Emitter voltage. Then with the specifications from the manufacturer of the transistors you can determine what the Base voltage should be to forward bias the E B junction. Now you need to known the impedance of the input signal to determine the two voltage bridge resistors that will supply the Base bias voltage. This two resistors impedance should match the input signal impedance for the most signal transfer to the base of the transistors. The best way to learn how to build amplifiers is to build some.
These two videos may help. Crossover Biasing Compensating Diodes ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-v2mITbaCHUE.html How can a DIODE pass an AUDIO SIGNAL UNDISTORTED ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ddfrkGkAvZY.html
@@AllAmericanFiveRadio thank you, i was thinking about that because i've seen somewhere a formula that RMS Watts= Volts/1 Amp... so most videos on youtube 12v amplifier based are fakes that they can amplify to 100w without changing (increasing) voltage?they will get a maximum of 12W
I just got so confused, I can barely stand up. I need a shower for this. There were no diodes to begin with and therefore there were 2 bumps showing in the sine wave. Unless I did not hear that nor saw that correctly. Then to clear that bumps you showed 2 diodes to be installed in series along between the bases. I don't know if I saw and heard that right either. Then you showed in your bread board mentioning that you actually installed the diodes but shorted out... whatever that means. Why did you install it shorted out. Unless installing it in series means shorted out in the first place... but that is....confusing regardless... I don't know what to even say... here. So you end up showing that you are removing the diodes that you wanted to be there in the first place to remove the bumps. But only by removing it you smoothed out the sine wave. End up with no diode that you started in the first place that caused the bumps to be there. I AM LOST. AM I SO GONE IN THE HEAD OR WHAT THAT I SEE AND HEAR THINGS THAT DON'T EXIST. I DON'T SEE ANYBODY ELSE COMPLAINING HERE.
@@phillipneal8194 You will need at least one RF choke coil. This is to keep the RF from getting into (shorted out by) the power supply. What frequencies are you interested in using?
I know it is an old video... very well done, but I have a question, if you can reply will be very appreciated... Which is the purpose of the two 470ohm resistors on the emitters? Are they used to "control" the differences in any way ? Thank you
Thanks for your response. I tried only in LTSpice and nothing sensible happened. For this reason I suspected it was for thermal runavay compensation. Is it right ?
The output impedance of the driving stage should mach the input impedance of the next stage. This transfers the most signal possible. Look up the input impedance of the transistor or MOSFET your using.
