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Transistors Part 2 Understanding Transistor Circuits - Circuits & Components For Beginners LER 

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Learn Electronics Repair #054
Circuits and Components For Beginners - Transistors Part 2.
In this installment we learn how transistors are used in a variety of common circuits.
This is an important lesson! There is no math or complicated equations here - rather than looking at transistor circuits from a circuit designer's point of view, this video concentrates on the basic understanding of transistor circuits that you will need in order to diagnose faults and troubleshoot these circuits successfully.
You can watch parts 1 & 3 here
Part 1 • Transistors Part 1. Ho...
Part 3 • Transistors for Beginn...
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25 июл 2024

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Комментарии : 34   
@billguitarvin
@billguitarvin 2 года назад
As many below have already said, you do a great job of explaining things. I really, really appreciate your explaining about what is happening with voltages, currents and watts at various parts of the circuit. It seems not many RU-vid videos go into talking about this. Finally some basic things of electronics are starting to make sense to me after 4 years of trying to learn what I can, thanks to your videos. Keep up the great work and thank you so much for taking the time to make these most excellent videos! Subscribed!
@carlgradolph9676
@carlgradolph9676 Год назад
After vainly struggling through myriad books trying to understand the basic principles of transistor operation, it is such a pleasure to have found your video series. Many thanks for presenting this content so clearly.
@jimbossemi-customs3129
@jimbossemi-customs3129 Год назад
You Sir, are the best electronics channel I've found. Wanting to learn more about electronics at 59 has been a bit of a struggle for me to understand. The way you explain things makes me understand all the other videos I've watched before I found your channel. Cannot wait to watch all your learning videos. Thank you!
@johnlabuci96
@johnlabuci96 10 месяцев назад
your words motivates me sir.. i thought me learning at 35 is too late
@NuclearPhysix
@NuclearPhysix 2 года назад
Man, I have been searching for a video like this like mad. Great work explaining transistor combinations/arrangements - Subbed
@LearnElectronicsRepair
@LearnElectronicsRepair 2 года назад
You're welcome! Thanks for the sub
@TheAnbyrley
@TheAnbyrley Год назад
Brings me back to my college days. Thanks for this! Great reminders!
@danielgodlewski9932
@danielgodlewski9932 Год назад
I finally understand how transistors work. Big thanks mate!!!
@jboy6944
@jboy6944 Год назад
Made sense of what many couldn’t. I appreciate the effort, Sir. Thank you!
@bones1225
@bones1225 2 года назад
Best explanation of an inverted amplifier transistor in the world . Many thanks.
@LearnElectronicsRepair
@LearnElectronicsRepair 2 года назад
WoW! Thanks
@mohammadusman831
@mohammadusman831 8 месяцев назад
Pure 24K gold!
@andyg873
@andyg873 2 года назад
Great explanation, thank you!
@overengineeredinoz7683
@overengineeredinoz7683 Год назад
I am really enjoying this series and learning at the same time. Thankyou.
@spelunkerd
@spelunkerd 2 года назад
Great summary, I've been looking for the next level for a while.
@amadeo.dujmovic
@amadeo.dujmovic Год назад
excellent
@daz41262010
@daz41262010 2 года назад
fantastic info :) great explanations :)
@frieddo
@frieddo Год назад
love your explanations ! very clear, very understandable. thank you very much for this kind of learning videos
@christopherholmqvist6216
@christopherholmqvist6216 Год назад
Pure gold!!!
@abbyhartsphotography5058
@abbyhartsphotography5058 Год назад
Thanks for taking the time for doing these videos
@user-kz8zb6vi6j
@user-kz8zb6vi6j 2 года назад
excellent explanation of transistor.thanks
@knightwar3
@knightwar3 Год назад
Great explanation as always
@jonathanrose456
@jonathanrose456 4 месяца назад
👏👏👏👏
@gearstil
@gearstil 2 года назад
Thank you!
@boybravo689
@boybravo689 Год назад
Thumbs up done sir can you differentiate a class b versus ab amplifier sir i'm so confused with their ckt configuration sir tnx
@coloradowilderness3139
@coloradowilderness3139 3 года назад
Very nice .
@LearnElectronicsRepair
@LearnElectronicsRepair 3 года назад
Thank You
@plinker439
@plinker439 Год назад
41:40 peak to peak is not 0 to 12V, instead of -6V to 6V?
@carlkellogg5342
@carlkellogg5342 Год назад
You need to talk planner. Other then that its a great video. TY
@williamwoo1437
@williamwoo1437 Год назад
I don’t quite understand the voltage across C and E in the voltage regulator example, because in part one it was mentioned that if the transistor is turned on then it should behave like a closed circuit. Which means the voltage across C-E should be close to zero. But yet the example used 2.7 V across C-E Which means there can be a voltage across if there is significant current flowing through, simply because there is still a small amount of resistance between C-E when the transistor was turned on. Is this a correct explanation?
@nemonemo2218
@nemonemo2218 Год назад
No, it's not for any resistance as such. Like you said, there *could* be enough current to short the transistor. Let's start at the Zener. See, the Zener essentially keeps the base voltage at 10V. (Everything above that is going through the Zener to ground.) The emitter Voltage now easily goes up to 9.3V (through (partly) base and (mostly) collector towards emitter). Now this is critical: As soon as the voltage there tries to go above 9.3, the voltage from base to emitter will go *below* 0.7V. But that's the voltage you need to open the transistor. So when that happens, the current is too little to keep the transistor fully open. It starts to throttle it. (You *could* regard this throttling as the resistance you mentioned, but it would lead you on a wrong track, I think.) So the transistor essentially limits its own output to Zener breakdown voltage minus base-emitter voltage. And - different from what a fixed resistance at that C-E connection would do - this is, up to a melting point, independent of the collector voltage. The C-E voltage therefore will always be collector voltage minus (Zener breakdown voltage minus base-emitter voltage). With 24V, you therefore would have 24 - (10 - 0.7) = 14.7V across C and E. Good question, though. Exactly the stuff I was asking myself so often.
@oldskoolordie
@oldskoolordie 3 месяца назад
I studied electronics as part of an apprenticeship and nobody explained things like you do. It was just, heres the maths and work out some examples. Maybe build a circuit on workbench. This is the way electronics should be taught. Less maths and more practical examples.
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