Here 5 years later and going through your youtube channel. You provide such detailed teachings. I really appreciate what you have done and you are helping a lot of people!
Joshua Julve I got the same answer as him. Make sure you are changing the L to meters and mass to kg to complement the Ke units. What answer are you getting ?
Do you have a degree in Physics or are you just well-versed in the subject? I just started taking it and am having some trouble, but your explanation was very welcome. Thank you!
Very well explained. I was facing difficulties in reading and understanding my lecture notes on this topic. Now am able to answer different questions using the derived formula. Thank you so much.
two small charged spheres contain charges q1 and q2 respectively a charge dq is removed from sphere carrying charge q1 and is transferred to the other find charge on each sphere for maximum eclectric force between them
A small sphere of charge +6x10^-6C is suspended by a string of negligible mass. A charge of -9.0x10^-6C is placed directly to the right if the sphere and 0.22m away from it. The string is deflected 5degree from the vertical. Find the tension in the string. Can you answer this? Pls
@@celesteebonito-nash1095 When I asked that, it was truly urgent. I never found the answer, unfortunately, and at this point, that ship has sailed. I wish you the best in finding the right answer.
At 4:30 isolate theta instead of q. Also, note that you will need to change the Tan to a Sin instead. (You could do this because Tan acts like Sin for small angles) It will end up looking somethig like this Sin^3Theta = [ (kq^2/4L^2) / mg] -> SinTheta = (...)^1/3 -> Theta = archsin(...)
Three identical small spheres of mass 'm' are suspended by threads of negligible masses and length'l' from a common point.A charge'q' is equally between the spheres and they come to equilibrium at the corners of a horizontal equilateral triangle of side 'a'.Show that: (q^2=12πεmg a^3 [ l^2-(a^2/3) ]^(-0.5) can you help me about this ? WNY Tutor@
Yashwanthkumar Kancherla I 'm so sorry but I send the solution in another vidio , and what is your emil to send to you the sorce , I'm sorry and by the way your number didn't add to my phone
I have almost the same problem, and I'm asked to find the separation distance, however, I was not given an angle, but i was given the charge value for the masses. How would this be solved? Thank you,
At 4:30 isolate theta instead of q. Also, note that you will need to change the Tan to a Sin instead. (You could do this because Tan acts like Sin for small angles) It will end up looking somethig like this Sin^3Theta = [ (kq^2/4L^2) / mg] -> SinTheta = (...)^1/3 -> Theta = archsin(...)
Couldn't you just take that the x forces mg and Tcos5 are equal, and solve for t right there? Once you have t you can find Fe and set that equal to the kq^2/d equation and solve for q there.
