U Tube Manometer 

The best video as far as the explanation and concept clearing is concerned. You touched all the necessary point that was needed to be clarified. Hope to see more of your videos

This is confusing.. the Pressure PA on the cylinder in left is basically equal to your rho*g*h1 because it is the same gas and its pressure will be the same at all points once you open that cylinder..If its not the same pressure yet then it will continue to push the orange fluid up until it becomes stable and can't push further. Also, atmospheric pressure can't be neglected in an open manometer. How could you neglect 101.325 KPa which is a huge magnitude.

If the right side is open, there is also the pressure from the atmosphere specified at a certain level

amazing sir is really help full for every one even for a gate

Thank you for your effort ❤️

SUPER EXPLANATION SIR. THANK YOU

Thank you very much

thank u sir very nice video upload some more for venturimeter

sir it is alright but here at right limb there exist atmospheric pressure but you not mention in general equation

Thank You Sir, Very Helpful! LongLive Indians!

Thank you sir ❤

Thank you.

Thank you so much

Thank you sir ❤❤❤🎉

Thanks a lot sir.. All my doubts where really clarified.. are you a malayali!?

well explained

sir why we didn't add the atmospheric pressure on the right limb as it is open not closed ?

super sir.......

means how to measure pressure inside tank n pressure diffrnt of gap of tank..

tq sir

don't atmospheric pressure act in the right limb?

Please explain why datum line is drawn

plz upload video to pressure calculation of tank n pressure diffrnt of tank,how to calculate liquid tank pressure

the name of prograamme u used

in second case, how the pressure becomes zero in right limb.?????

not all heroes wear capes :'')

Super bro

What happen if h2 is less than h1

Why didn't you consider Atmoshperic pressure in the right limb?

Enough idea 💡🙄

Great video but some improvement needed. The U tube is open at the end of both limbs. So there is atmospheric pressure acting on both sides of the limb. So the correct equation is Patm + Pa + r1gh1 = Patm + r2gh2. 2) Using the same equation for determining vacuum pressure Patm + Pv + r1gh1 + r2gh2 = Patm This equation correctly describes the pressure dynamic at play. It was very unclear in your video why the pressure on right limb was 0.

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Find the hight please sir

#mano_tube

Good video..But do try to improve your spoken language. Its feels as though there isnt any passion in it.

slow down and pronounce words