Fantastic explanation! very good job.. thank you very much Students nowadays are so lucky there is literally no excuse for not doing well. When I went to college circa graduation 1979 there was nothing to help except a pay tutor or family member no PCs no You tube , maybe a library but no calculators....nothing. I picked up my 41 yr old text book and tried to do a problem but no avail so listened to this video and within 15 minutes it all came back.
One of the best explained videos regarding vectors thank you so much. you got me out of a big hole by your skill of explaining these equations. Everything kicked in after watching your video. Thank you Aggieer
Thank you soo much *-*, Even my classmates were seeking help from me after I understood this thanks to your video! Really! this was really a good help for me since I'm kinda bad with numbers!
Excellent tutorial.. it was so simplified with full details of everything required 😌 thanks a bunch ... I'm having my physics exams tomorrow and this has really helped me alot😊❤🎉
Even 10 years later this remains useful, never got taught this method probably because I don’t live in America but man this makes everything so much simpler
@ archie lim: Trigonometric functions use standard notation that is defined from the x-axis. So the 160lb force has an angle that is referenced to the x-axis and we use it. The other two forces have angles referenced to the y-axis, so we must find the angle they make with the x-axis and use it. I hope this helps.
Darlina Dzaqura Yes, the resultant force is the magnitude of the three forces combined. Every vector has both magnitude and direction. The magnitude will be a unit (kg, lbs, m/s, etc) and the direction will be which way that magnitude is pointing.
An angle of 270 degrees is on the negative y axis, so the x component would be zero and the y component would be -y (or -r in vector terminology). So if you have a force of 400 lbs at 270 degrees, the x component would be x=0, and the y component would be y = -400. Hope that helps.
It is just a way to organize your numbers so that you don't "misplace" any. When working structural problems where you have forces and moments in three dimensions, it makes it a lot easier to keep up with all the information. Glad that it could help you.
Would love to see videos of Statics (structural engineering maths like are used in both engineering and architecture). I found your video on resultant of 3 vectors (this video) and you explained it so much more easily than the professor of the class my adult kid is taking. You do a great job of, how do we say, "explain it like I'm 5 years old", which is exactly what lost students need more of! Or reach out if you do any tutoring :)
I would eventually like to do a statics series of videos, but the amount of time it takes vs the reward through you tube is so small. One day I hope to be able to get to that.......
Thanks for this video! I was looking for one on how to find a vector using the resultant and one vector and your table really helped be see how to work it backwards!
Make sure you put the negative component in parentheses. Many calculators are programmed such that -2 squared is -4 but (-2) squared is 4. Also, make sure you are using the negative key and not the subtraction key. The negative key is usually look like (-) or +/- Please let me know if this solved your problem.
I have lots more videos (and will actually be uploading a large bunch later this semester) but they are math videos. Since I am a math teacher, that is what I focus on. I am hopeful that some of my videos can help you in physics. Search through my others, as there are many trig videos that can help. Glad this one helped you.
Both are forces, so the problem would be the same. If you change the units in the problem to N, the resultant force would be the same number, but the units would be N. I hope this helps.
Is there a topic from Statics that you would like to see? I am a math teacher, but my background is mechanical engineering, so I would be glad to help.
@@justcharacter2098 all of our basic trigonometric definitions are based on the x-axis, so you will see that I do everything from that axis. You can reference from the y-axis, but it takes some work. I find that trying to explain that in a video tends to overcomplicate it. So the simplest way to work any problem involving trigonometry - always reference to the nearest x-axis. I hope that helps explain it.
Thank you so much. What would you do in the case that the vector is at an angle of 270˚. Would the angle be changed to 90˚. Also when the vector is right on the x or y axis how would you know if the x or y values for the eqaution are positive or negative since they're not in a quadrant.
90 and 270 are "basically" equivalent. Here is the quick and dirty.... Your x-components will be positive in Quadrants I and IV because the x-axis is positive there, and negative in Quadrants II and III because it is negative there. Same with y. When a vector lands on a quadrant line, it doesn't have both components. For example, let's say you have 100 pounds at 270 degrees, the components would be < 0, -100> or x = 0 and y = -100. This is due to the fact that the force is acting in the negative y direction. The longer explanation is the value of sine and cosine at quadrantal values (0, 90, 180, 270). Does that help?
Anyone ever tell you, you sound like the son on King Of The Hill? well anyways slowly crawling through your play-list because my teacher apparently neglects critical aspects to help curb my learning curve. Great vids!! this is the beginning of a beautiful Subscription.
@zepfuck - Not sure what you are asking, could you rephrase your question? By definition in mathematics all clockwise angles are considered in the negative direction if that is what you are referring to. If you can clarify your question, I would be glad to help.
Just a quick back of the napkin calculation, I come up with a resultant of roughly 152 N. Because all of these are East of North, they will be additive......I think 70 N is way too low.
Ohh thank you so much, you have really made me to understand but I have one question that is If you are finding the resultant force should you draw a diagram to represent it
It is not a bad idea, but it is not required. I have found over the years that most students who draw a diagram don't draw it to scale. Then their diagram doesn't match their answer. Usually leads to confusion. Let me know if that answers your question. I do have several other vector videos, and some of those I do go through drawing the diagrams.
