Watch me solve this Rational Equation - step-by-step

Подписаться 635 тыс.

Просмотров 9 тыс.

50% 1

How to solve a rational equation and check for extraneous solutions.
TabletClass Math Academy
Help with Middle and High School Math
Test Prep for High School Math, College Math, Teacher Certification Math and More!
Popular Math Courses:
Math Foundations
tabletclass-academy.teachable...
Math Skills Rebuilder Course:
tabletclass-academy.teachable...
Pre-Algebra
tabletclass-academy.teachable...
Algebra
tabletclass-academy.teachable...
Geometry
tabletclass-academy.teachable...
Algebra 2
tabletclass-academy.teachable...
Pre-Calculus
tabletclass-academy.teachable...

Опубликовано:

25 окт 2023

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист

Посмотреть позже

Комментарии : 29

@tomtke7351 8 месяцев назад

I'd guess a bit of substitution might be helpful as in substitute Y = (1/(1+x)) so that 6Y^2 - Y = 1

@b213videoz 2 месяца назад

This is exactly what I did 😉

@mr.mxyzptlks8391 10 дней назад

Exactly what my first instinct was, substitute…

@user-xy2wq1qn9p 8 месяцев назад

just: Let a = 1/(x+1). Then you have to solve 6a^2-a=1 that is 6a^2 -a -1=0, Discriminant = 25, a=1/2 or a=-1/3, that is x=1 or x=-4

@panlomito 8 месяцев назад

This is exactly what I did, very clean and simple, I don't understand why you would make such a hustle of this equation.

@EdwardCurrent 7 месяцев назад

@@panlomito It'd be cool to show both methods. Math is beautiful how different journeys lead to the same destination

@panlomito 7 месяцев назад

@@EdwardCurrent True, but I prefer short cuts when available.

@MargaretCutt-um8iq 4 месяца назад

I had an "ah ha! L" moment with this. I am refreshing my very very very rusty algebra skills with your classes. Phew!

@padraicbrown6718 8 месяцев назад

I got 1 through inspection; and realise that it is a QE and would have another solution. I shall watch to review this kind of equation! .... and got it! Thanks Mr RU-vid Math Man!

@MartinHermans-dw3is 4 месяца назад

I subbed in 'u' for 1/1+x and then factored that. solving for both solutions, i put u = 1/1+x and entered the two values for u and got my two answers

@EdwardCurrent 7 месяцев назад

I don't remember learning this in high school (multiplying by an LCD involving variables), very cool.

@russelllomando8460 8 месяцев назад

good one, thanks

@devonwilson5776 8 месяцев назад

Greetings. We must realize that X has two values, and the values are 1 and minus 4. From the expression given we have (6-(X+1))/(X+1)^2=1. Moving on, we have 6-X-1=X^2+2X+1, and 5-X=X^2 +2X+1 is reduced to X^2 +3X-4=0 after transposing and adding and subtracting like terms. Now, we will simply factor the expression X^2+3X-4=0 to get (X+4)(X-1)=0 from which it is determined that X =1 or -4.

@user-cg5xv4zz2b 8 месяцев назад

this is how I did it, but made some math errors 6 -(x+1) I made into x+5 , not -x + 5. Once fixed, I got it right.

@janetdavis4724 8 месяцев назад

This should only be used in college , most people in high school don’t use this after they graduated..

@stuartyoung5728 8 месяцев назад

The , equation can be solved as a quadratic in 1/(x+1).

@b213videoz 2 месяца назад

Much to my surprise I managed to solve it. In fact it's nowhere this intimidating that it appears to be. The trick is to introduce a variable. 1 let t = --- x+1 6t² - t - 1 = 0 t1 = - 1/3 1 1 --- = ---; x+1 = -3; x = -4 x+1 -3 t2 = 1/2 1 1 --- = ---; x+1 = 2; x = 1 x+1 2